You are viewing a plain text version of this content. The canonical link for it is here.
Posted to issues@spark.apache.org by "Maxim Gekk (JIRA)" <ji...@apache.org> on 2018/06/16 03:49:00 UTC
[jira] [Updated] (SPARK-24571) Support literals with values of the
Char type
[ https://issues.apache.org/jira/browse/SPARK-24571?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel ]
Maxim Gekk updated SPARK-24571:
-------------------------------
Description:
Currently, Spark doesn't support literals with the Char (java.lang.Character) type. For example, the following code throws an exception:
{code}
val df = Seq("Amsterdam", "San Francisco", "London").toDF("city")
df.where($"city".contains('o')).show(false)
{code}
It fails with the exception:
{code:java}
Unsupported literal type class java.lang.Character o
java.lang.RuntimeException: Unsupported literal type class java.lang.Character o
at org.apache.spark.sql.catalyst.expressions.Literal$.apply(literals.scala:78)
{code}
One of the possible solutions can be automatic conversion of Char literal to String literal of length 1.
was:
Currently, Spark doesn't support literals with the Char (java.lang.Character) type. For example, the following code throws an exception:
{code:scala}
val df = Seq("Amsterdam", "San Francisco", "London").toDF("city")
df.where($"city".contains('o')).show(false)
{code}
It fails with the exception:
{code}
Unsupported literal type class java.lang.Character o
java.lang.RuntimeException: Unsupported literal type class java.lang.Character p
at org.apache.spark.sql.catalyst.expressions.Literal$.apply(literals.scala:78)
{code}
One of the possible solutions can be automatic conversion of Char literal to String literal of length 1.
> Support literals with values of the Char type
> ---------------------------------------------
>
> Key: SPARK-24571
> URL: https://issues.apache.org/jira/browse/SPARK-24571
> Project: Spark
> Issue Type: Improvement
> Components: SQL
> Affects Versions: 2.3.1
> Reporter: Maxim Gekk
> Priority: Minor
>
> Currently, Spark doesn't support literals with the Char (java.lang.Character) type. For example, the following code throws an exception:
> {code}
> val df = Seq("Amsterdam", "San Francisco", "London").toDF("city")
> df.where($"city".contains('o')).show(false)
> {code}
> It fails with the exception:
> {code:java}
> Unsupported literal type class java.lang.Character o
> java.lang.RuntimeException: Unsupported literal type class java.lang.Character o
> at org.apache.spark.sql.catalyst.expressions.Literal$.apply(literals.scala:78)
> {code}
> One of the possible solutions can be automatic conversion of Char literal to String literal of length 1.
--
This message was sent by Atlassian JIRA
(v7.6.3#76005)
---------------------------------------------------------------------
To unsubscribe, e-mail: issues-unsubscribe@spark.apache.org
For additional commands, e-mail: issues-help@spark.apache.org