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Posted to issues@calcite.apache.org by "Julian Hyde (JIRA)" <ji...@apache.org> on 2015/12/11 22:34:46 UTC

[jira] [Updated] (CALCITE-1016) "GROUP BY constant" on empty relation should return 0 rows

     [ https://issues.apache.org/jira/browse/CALCITE-1016?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel ]

Julian Hyde updated CALCITE-1016:
---------------------------------
    Summary: "GROUP BY constant" on empty relation should return 0 rows  (was: What should "GROUP BY 1" return on an empty table?)

> "GROUP BY constant" on empty relation should return 0 rows
> ----------------------------------------------------------
>
>                 Key: CALCITE-1016
>                 URL: https://issues.apache.org/jira/browse/CALCITE-1016
>             Project: Calcite
>          Issue Type: Bug
>            Reporter: Julian Hyde
>            Assignee: Julian Hyde
>
> What should "GROUP BY 1" return on an empty table? Calcite currently returns 0 rows. I am hearing claims that according to standard SQL it should return 1 row.
> Here is what Oracle 11.2.0.2.0 does.
> {noformat}
> SQL> select count(*) from emp where 1 = 0;
>   COUNT(*)
> ----------
> 	 0
> SQL> select count(*) from emp where 1 = 0 group by ();
> no rows selected
> SQL> select count(*) from emp where 1 = 0 group by 1;
> no rows selected
> SQL> select count(*) from emp;
>   COUNT(*)
> ----------
> 	14
> SQL> select count(*) from emp group by ();
>   COUNT(*)
> ----------
> 	14
> SQL> select count(*) from emp group by 1;
>   COUNT(*)
> ----------
> 	14
> {noformat}
> I had expected {code}select count(*) from emp where 1 = 0 group by (){code} would return 1 row, but it returns 0, like {code}group by 1{code}.



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