You are viewing a plain text version of this content. The canonical link for it is here.
Posted to dev@xalan.apache.org by bu...@apache.org on 2002/07/20 00:42:23 UTC

DO NOT REPLY [Bug 10995] New: - Failed assertion on simple XPath syntax errors

DO NOT REPLY TO THIS EMAIL, BUT PLEASE POST YOUR BUG 
RELATED COMMENTS THROUGH THE WEB INTERFACE AVAILABLE AT
<http://nagoya.apache.org/bugzilla/show_bug.cgi?id=10995>.
ANY REPLY MADE TO THIS MESSAGE WILL NOT BE COLLECTED AND 
INSERTED IN THE BUG DATABASE.

http://nagoya.apache.org/bugzilla/show_bug.cgi?id=10995

Failed assertion on simple XPath syntax errors

           Summary: Failed assertion on simple XPath syntax errors
           Product: XalanJ2
           Version: 2.4Dx
          Platform: PC
        OS/Version: Linux
            Status: NEW
          Severity: Normal
          Priority: Other
         Component: org.apache.xpath
        AssignedTo: xalan-dev@xml.apache.org
        ReportedBy: kse@wp.pl


Using wrong (Java/C-style) '==' operator is a nasty trap. 

To cause an assertion failure, use the following xsl.

I use command line with Sun JDK1.4 for Linux, jars in lib/endorsed. No source xml needed. See 
also Bug 2139.

I think this should produce a helpful message instead.

<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

  <!-- a simple XPath syntax error test -->

<xsl:template match="doc">
	<xsl:if test="@atr == 'val'"/>

	<!-- You may also try: -->
	<xsl:if test="@atr = = 'val'"/>
	<xsl:if test="@atr ="/>
	<xsl:if test="@atr != != 'val'"/>
	<xsl:if test="@atr =!= 'val'"/>
	<xsl:if test="@atr =&gt; 'val'"/>
	<xsl:if test="@atr = + 'val'"/>
</xsl:template>

</xsl:stylesheet>