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Posted to dev@tinkerpop.apache.org by "Marko A. Rodriguez (JIRA)" <ji...@apache.org> on 2017/02/22 16:49:44 UTC
[jira] [Assigned] (TINKERPOP-1626) choose() is buggy in OLAP
[ https://issues.apache.org/jira/browse/TINKERPOP-1626?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel ]
Marko A. Rodriguez reassigned TINKERPOP-1626:
---------------------------------------------
Assignee: Marko A. Rodriguez
> choose() is buggy in OLAP
> -------------------------
>
> Key: TINKERPOP-1626
> URL: https://issues.apache.org/jira/browse/TINKERPOP-1626
> Project: TinkerPop
> Issue Type: Bug
> Components: process
> Affects Versions: 3.3.0
> Reporter: Daniel Kuppitz
> Assignee: Marko A. Rodriguez
>
> Not yet tested in older versions.
> What follows are two queries that only differ in where {{as("p2").select("p1","p2")}} is done. {{p1}} is a person and {{p2}} is (supposed to be) either a person known by {{p1}} or - if {{p1}} doesn't know anybody - the same as {{p1}}.
> *OLTP (all good):*
> {noformat}
> gremlin> g = TinkerFactory.createModern().traversal()
> ==>graphtraversalsource[tinkergraph[vertices:6 edges:6], standard]
> gremlin> g.V().hasLabel("person").as("p1").choose(outE("knows"), out("knows"), identity()).as("p2").select("p1","p2")
> ==>[p1:v[1],p2:v[2]]
> ==>[p1:v[1],p2:v[4]]
> ==>[p1:v[2],p2:v[2]]
> ==>[p1:v[4],p2:v[4]]
> ==>[p1:v[6],p2:v[6]]
> gremlin> g.V().hasLabel("person").as("p1").choose(outE("knows"), out("knows").as("p2").select("p1","p2"), __.as("p2").select("p1","p2"))
> ==>[p1:v[1],p2:v[2]]
> ==>[p1:v[1],p2:v[4]]
> ==>[p1:v[2],p2:v[2]]
> ==>[p1:v[4],p2:v[4]]
> ==>[p1:v[6],p2:v[6]]
> {noformat}
> *OLAP (only works when {{select()}} is done twice - once for each branch):*
> {noformat}
> gremlin> g = g.withComputer()
> ==>graphtraversalsource[tinkergraph[vertices:6 edges:6], graphcomputer]
> gremlin> g.V().hasLabel("person").as("p1").choose(outE("knows"), out("knows"), identity()).as("p2").select("p1","p2")
> ==>[p1:v[1],p2:v[1]]
> ==>[p1:v[1],p2:v[1]]
> gremlin> g.V().hasLabel("person").as("p1").choose(outE("knows"), out("knows").as("p2").select("p1","p2"), __.as("p2").select("p1","p2"))
> ==>[p1:v[2],p2:v[2]]
> ==>[p1:v[4],p2:v[4]]
> ==>[p1:v[6],p2:v[6]]
> ==>[p1:v[1],p2:v[2]]
> ==>[p1:v[1],p2:v[4]]
> {noformat}
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