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Posted to issues@spark.apache.org by "Romi Kuntsman (JIRA)" <ji...@apache.org> on 2016/11/29 09:07:58 UTC

[jira] [Updated] (SPARK-18621) PySQL SQL Types (aka Dataframa Schema) have __repr__() with Scala and not Python representation

     [ https://issues.apache.org/jira/browse/SPARK-18621?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel ]

Romi Kuntsman updated SPARK-18621:
----------------------------------
    Description: 
When using Python's repr() on an object, the expected result is a string that Python can evaluate to construct the object.
See: https://docs.python.org/2/library/functions.html#func-repr

However, when getting a DataFrame schema in PySpark, the code (in "__repr()__" overload methods) returns the string representation for Scala, rather than for Python.

Relevant code in PySpark:
https://github.com/apache/spark/blob/5f02d2e5b4d37f554629cbd0e488e856fffd7b6b/python/pyspark/sql/types.py#L442

Python Code:

{code}
# 1. define object
struct1 = StructType([StructField("f1", StringType(), True)])
# 2. print representation, expected to be like above
print(repr(struct1))
# 3. actual result:
# StructType(List(StructField(f1,StringType,true)))
# 4. try to use result in code
struct2 = StructType(List(StructField(f1,StringType,true)))
# 5. get bunch of errors
# Unresolved reference 'List'
# Unresolved reference 'f1'
# StringType is class, not constructed object
# Unresolved reference 'true'
{code}

  was:
When using Python's repr() on an object, the expected result is a string that Python can evaluate to construct the object.
See: https://docs.python.org/2/library/functions.html#func-repr

However, when getting a DataFrame schema in PySpark, the code (in "__repr()__" overload methods) returns the string representation for Scala, rather than for Python.

Relevant code in PySpark:
https://github.com/apache/spark/blob/5f02d2e5b4d37f554629cbd0e488e856fffd7b6b/python/pyspark/sql/types.py#L442

Python Code:

# 1. define object
struct1 = StructType([StructField("f1", StringType(), True)])
# 2. print representation, expected to be like above
print(repr(struct1))
# 3. actual result:
# StructType(List(StructField(f1,StringType,true)))
# 4. try to use result in code
struct2 = StructType(List(StructField(f1,StringType,true)))
# 5. get bunch of errors
# Unresolved reference 'List'
# Unresolved reference 'f1'
# StringType is class, not constructed object
# Unresolved reference 'true'


> PySQL SQL Types (aka Dataframa Schema) have __repr__() with Scala and not Python representation
> -----------------------------------------------------------------------------------------------
>
>                 Key: SPARK-18621
>                 URL: https://issues.apache.org/jira/browse/SPARK-18621
>             Project: Spark
>          Issue Type: Bug
>          Components: PySpark
>    Affects Versions: 1.6.2, 2.0.2
>            Reporter: Romi Kuntsman
>            Priority: Minor
>
> When using Python's repr() on an object, the expected result is a string that Python can evaluate to construct the object.
> See: https://docs.python.org/2/library/functions.html#func-repr
> However, when getting a DataFrame schema in PySpark, the code (in "__repr()__" overload methods) returns the string representation for Scala, rather than for Python.
> Relevant code in PySpark:
> https://github.com/apache/spark/blob/5f02d2e5b4d37f554629cbd0e488e856fffd7b6b/python/pyspark/sql/types.py#L442
> Python Code:
> {code}
> # 1. define object
> struct1 = StructType([StructField("f1", StringType(), True)])
> # 2. print representation, expected to be like above
> print(repr(struct1))
> # 3. actual result:
> # StructType(List(StructField(f1,StringType,true)))
> # 4. try to use result in code
> struct2 = StructType(List(StructField(f1,StringType,true)))
> # 5. get bunch of errors
> # Unresolved reference 'List'
> # Unresolved reference 'f1'
> # StringType is class, not constructed object
> # Unresolved reference 'true'
> {code}



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