Further XSLT question

[Joona Palaste <jo...@dmm.fi>]

Thanks to Agnes Kielen and Jarkko Moilanen, I've managed to write an
XSLT stylesheet that groups successive value nodes into group nodes.
But there's one thing I can't figure out.
I'm trying to implement a transform from a simple one-dimensional list
to a two-dimensional table in the XSL:FO language. The list (a simplified
version of our real source XML, which is secret) looks like this:

<list delimiter="," module="3">
  <node>1</node>
  <node>2</node>
  <node>3</node>
  <node>4</node>
  <node>5</node>
  <node>6</node>
</list>

The XSL I'm using (again, a simplified one) looks like this:

<xsl:template match="list">
  <xsl:variable name="module"><xsl:value-of 
select="@module"/></xsl:variable>
  <fo:table table-layout="fixed">
    <xsl:for-each select="node[position()&lt;($module+1)]">
      <fo:table-column column-width="20mm"/>
    </xsl:for-each>
    <fo:table-body>
      <xsl:for-each select="node[(position() mod $module)=1]">
        <fo:table-row>
          <xsl:for-each select=". | 
following-sibling::node[position()&lt;$module]">
            <fo:table-cell>
              <fo:block>
                <xsl:value-of select=".">
<!--
                <xsl:if test="not(position()=last())">
                  <xsl:value-of select="../@delimiter"/>
                </xsl:if>
-->
              </fo:block>
            </fo:table-cell>
          </xsl:for-each>
        </fo:table-row>
      </xsl:for-each>
    </fo:table-body>
  </fo:table>
</xsl:template>

This works fine, and produces a two-dimensional XSL:FO table. But if I
uncomment the block shown above in <!-- --> to make it real XSL code,
then the table only renders the first table-cell in every table-row.
What is the reason for this?

Joona Palaste
joona.palaste@dmm.fi