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Posted to users@camel.apache.org by cmoulliard <cm...@gmail.com> on 2008/07/18 12:53:47 UTC
How to transpose this route in Spring XML ?
hi,
How can I transpose this splitter route (where there is no XPATH expression)
into XML ?
from("direct:A")
.splitter(body())
.to("bean:MyBean")
or
from("direct:A")
.splitter(body().tokenize(","))
.to("bean:MyBean")
It should be interesting to improve the documentation concerning this point.
Regards,
Charles Moulliard
-----
Enterprise Architect
Xpectis
12, route d'Esch
L-1470 Luxembourg
Phone +352 25 10 70 470
Mobile +352 621 45 36 22
e-mail : cmoulliard@xpectis.com
web site : www.xpectis.com
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RE: How to transpose this route in Spring XML ?
Posted by Claus Ibsen <ci...@silverbullet.dk>.
Yep the DSL are in badly need for improved documentation or documentation at all.
Med venlig hilsen
Claus Ibsen
......................................
Silverbullet
Skovsgårdsvænget 21
8362 Hørning
Tlf. +45 2962 7576
Web: www.silverbullet.dk
-----Original Message-----
From: cmoulliard [mailto:cmoulliard@gmail.com]
Sent: 18. juli 2008 12:54
To: camel-user@activemq.apache.org
Subject: How to transpose this route in Spring XML ?
hi,
How can I transpose this splitter route (where there is no XPATH expression)
into XML ?
from("direct:A")
.splitter(body())
.to("bean:MyBean")
or
from("direct:A")
.splitter(body().tokenize(","))
.to("bean:MyBean")
It should be interesting to improve the documentation concerning this point.
Regards,
Charles Moulliard
-----
Enterprise Architect
Xpectis
12, route d'Esch
L-1470 Luxembourg
Phone +352 25 10 70 470
Mobile +352 621 45 36 22
e-mail : cmoulliard@xpectis.com
web site : www.xpectis.com
--
View this message in context: http://www.nabble.com/How-to-transpose-this-route-in-Spring-XML---tp18526794s22882p18526794.html
Sent from the Camel - Users mailing list archive at Nabble.com.