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Posted to dev@fineract.apache.org by ivange larry <iv...@gmail.com> on 2019/03/13 12:07:56 UTC
Adding a new Resource in Fineract 1.x
Hi all,
I'm trying to add a new endpoint /healthCheck which will always respond
with 200 to confirm that the server is reachable. I have implemented a
HealthCheckResource.java in org.apache.fineract.system.api. I created the
package system.api. Here's my resource class
https://gist.github.com/ivange94/3b67a80c6d9f90adeceddf052c6026d5
I keep getting a 404 when I try to access the endpoint at
https://localhost:8443/fineract-provider/api/v1/healthCheck?tenantIdentifier=default
.
Is there anything I'm missing?
Thanks,
Larry
Re: Adding a new Resource in Fineract 1.x
Posted by Courage Angeh <co...@gmail.com>.
you are welcome
On Thu, Mar 14, 2019 at 12:42 AM ivange larry <iv...@gmail.com> wrote:
> Thanks Courage. That fixed my problem for me.
>
> On Wed, Mar 13, 2019 at 9:57 PM Courage Angeh <co...@gmail.com>
> wrote:
>
> > Sorry wrong code, this is the right one.
> >
> > *. . .*
> > <context:component-scan
> > base-package="org.apache.fineract.accounting.*
> > org.apache.fineract.commands.provider.*,
> > org.apache.fineract.commands.handler.*,
> > *...*
> >
> > org.apache.fineract.system.*">
> > <context:exclude-filter expression="
> > org.springframework.stereotype.Controller"
> > * ...*
> >
> > On Wed, Mar 13, 2019 at 4:42 PM Courage Angeh <co...@gmail.com>
> > wrote:
> >
> > > Hi Larry,
> > >
> > > You need to add your base package to the
> > > fineract-provider/src/main/resources/META-INF/spring/appContext.xml
> > > <
> >
> https://github.com/apache/fineract/pull/283/files#diff-f3d6abe979dfc7dfbafc5831007ba31e
> >
> > like
> > > so:
> > >
> > > *. . .*
> > > <context:component-scan
> > > base-package="org.apache.fineract.accounting.*
> > > org.apache.fineract.commands.provider.*,
> > > org.apache.fineract.commands.handler.*,
> > > *...*
> > >
> > > org.apache.fineract.notification.*">
> > > <context:exclude-filter expression="
> > > org.springframework.stereotype.Controller"
> > > * ...*
> > >
> > > On Wed, Mar 13, 2019 at 11:43 AM ivange larry <iv...@gmail.com>
> > > wrote:
> > >
> > >> Maybe I should mention that I do get this strange error when I run the
> > >> application. https://pastebin.com/t3H2LBNa
> > >>
> > >> The application seems to look for the resource class in the wrong
> > location
> > >> and returns a ClassNotFoundException
> > >>
> > >> On Wed, Mar 13, 2019 at 4:39 PM ivange larry <iv...@gmail.com>
> > >> wrote:
> > >>
> > >> > Thanks Vishwas for that observation. Unfortunately, it still doesn't
> > >> work.
> > >> > I have tried with this url
> > >> >
> > >> >
> > >> >
> > >>
> >
> https://localhost:8443/fineract-provider/api/v1/heathCheck?tenantIdentifier=default
> > >> >
> > >> > Since that's the one I actually coded accidentally and it still
> > returns
> > >> > 404. The parameter tenantIdentifier is only present because I just
> > >> copied
> > >> > that link from other resources and changed the resource to
> heathCheck.
> > >> But
> > >> > my implementation does not actually expect a parameter. When I
> delete
> > >> the
> > >> > parameter from the string and make a request with
> > >> > https://localhost:8443/fineract-provider/api/v1/heathCheck, I now
> > get a
> > >> > 400 error complaining of the missing parameter.
> > >> >
> > >> > Is there a guide that documents the steps needed to add a new
> > resource?
> > >> >
> > >> > Let outline again the steps I took, maybe my code changes are not
> even
> > >> > reflected in the deployment.
> > >> >
> > >> > 1) I added a class HealthCheckResource as already explained above.
> > >> > 2) Build application with ./gradlew build
> > >> > 3) Run application with ./gradlew tomcatRunWar
> > >> >
> > >> > Let me know if I'm doing something wrong.
> > >> >
> > >> > Thanks,
> > >> > Larry
> > >> >
> > >> > On Wed, Mar 13, 2019 at 3:43 PM Vishwas Babu <
> > >> > vishwas@confluxtechnologies.com> wrote:
> > >> >
> > >> >> Larry,
> > >> >>
> > >> >> There is a typo in the path parameter of your resource class, i.e
> > >> >> heathCheck instead
> > >> >> of healthCheck
> > >> >>
> > >> >> Regards,
> > >> >> Vishwas
> > >> >>
> > >> >>
> > >> >> On Wed, Mar 13, 2019 at 5:08 AM ivange larry <
> ivangelarry@gmail.com>
> > >> >> wrote:
> > >> >>
> > >> >> > Hi all,
> > >> >> >
> > >> >> > I'm trying to add a new endpoint /healthCheck which will always
> > >> respond
> > >> >> > with 200 to confirm that the server is reachable. I have
> > implemented
> > >> a
> > >> >> > HealthCheckResource.java in org.apache.fineract.system.api. I
> > created
> > >> >> the
> > >> >> > package system.api. Here's my resource class
> > >> >> >
> > >> >> >
> https://gist.github.com/ivange94/3b67a80c6d9f90adeceddf052c6026d5
> > >> >> >
> > >> >> > I keep getting a 404 when I try to access the endpoint at
> > >> >> >
> > >> >> >
> > >> >>
> > >>
> >
> https://localhost:8443/fineract-provider/api/v1/healthCheck?tenantIdentifier=default
> > >> >> > .
> > >> >> >
> > >> >> > Is there anything I'm missing?
> > >> >> >
> > >> >> > Thanks,
> > >> >> > Larry
> > >> >> >
> > >> >>
> > >> >
> > >> >
> > >> > --
> > >> > GSoC 2016 @OpenMRS
> > >> > GSoC 2017 @LibreHealth
> > >> > GCI 2016 Mentor @OpenMRS
> > >> > GCI Org Admin @OpenMRS
> > >> >
> > >>
> > >>
> > >> --
> > >> GSoC 2016 @OpenMRS
> > >> GSoC 2017 @LibreHealth
> > >> GCI 2016 Mentor @OpenMRS
> > >> GCI Org Admin @OpenMRS
> > >>
> > >
> >
>
>
> --
> GSoC 2016 @OpenMRS
> GSoC 2017 @LibreHealth
> GCI 2016 Mentor @OpenMRS
> GCI Org Admin @OpenMRS
>
Re: Adding a new Resource in Fineract 1.x
Posted by ivange larry <iv...@gmail.com>.
Thanks Courage. That fixed my problem for me.
On Wed, Mar 13, 2019 at 9:57 PM Courage Angeh <co...@gmail.com>
wrote:
> Sorry wrong code, this is the right one.
>
> *. . .*
> <context:component-scan
> base-package="org.apache.fineract.accounting.*
> org.apache.fineract.commands.provider.*,
> org.apache.fineract.commands.handler.*,
> *...*
>
> org.apache.fineract.system.*">
> <context:exclude-filter expression="
> org.springframework.stereotype.Controller"
> * ...*
>
> On Wed, Mar 13, 2019 at 4:42 PM Courage Angeh <co...@gmail.com>
> wrote:
>
> > Hi Larry,
> >
> > You need to add your base package to the
> > fineract-provider/src/main/resources/META-INF/spring/appContext.xml
> > <
> https://github.com/apache/fineract/pull/283/files#diff-f3d6abe979dfc7dfbafc5831007ba31e>
> like
> > so:
> >
> > *. . .*
> > <context:component-scan
> > base-package="org.apache.fineract.accounting.*
> > org.apache.fineract.commands.provider.*,
> > org.apache.fineract.commands.handler.*,
> > *...*
> >
> > org.apache.fineract.notification.*">
> > <context:exclude-filter expression="
> > org.springframework.stereotype.Controller"
> > * ...*
> >
> > On Wed, Mar 13, 2019 at 11:43 AM ivange larry <iv...@gmail.com>
> > wrote:
> >
> >> Maybe I should mention that I do get this strange error when I run the
> >> application. https://pastebin.com/t3H2LBNa
> >>
> >> The application seems to look for the resource class in the wrong
> location
> >> and returns a ClassNotFoundException
> >>
> >> On Wed, Mar 13, 2019 at 4:39 PM ivange larry <iv...@gmail.com>
> >> wrote:
> >>
> >> > Thanks Vishwas for that observation. Unfortunately, it still doesn't
> >> work.
> >> > I have tried with this url
> >> >
> >> >
> >> >
> >>
> https://localhost:8443/fineract-provider/api/v1/heathCheck?tenantIdentifier=default
> >> >
> >> > Since that's the one I actually coded accidentally and it still
> returns
> >> > 404. The parameter tenantIdentifier is only present because I just
> >> copied
> >> > that link from other resources and changed the resource to heathCheck.
> >> But
> >> > my implementation does not actually expect a parameter. When I delete
> >> the
> >> > parameter from the string and make a request with
> >> > https://localhost:8443/fineract-provider/api/v1/heathCheck, I now
> get a
> >> > 400 error complaining of the missing parameter.
> >> >
> >> > Is there a guide that documents the steps needed to add a new
> resource?
> >> >
> >> > Let outline again the steps I took, maybe my code changes are not even
> >> > reflected in the deployment.
> >> >
> >> > 1) I added a class HealthCheckResource as already explained above.
> >> > 2) Build application with ./gradlew build
> >> > 3) Run application with ./gradlew tomcatRunWar
> >> >
> >> > Let me know if I'm doing something wrong.
> >> >
> >> > Thanks,
> >> > Larry
> >> >
> >> > On Wed, Mar 13, 2019 at 3:43 PM Vishwas Babu <
> >> > vishwas@confluxtechnologies.com> wrote:
> >> >
> >> >> Larry,
> >> >>
> >> >> There is a typo in the path parameter of your resource class, i.e
> >> >> heathCheck instead
> >> >> of healthCheck
> >> >>
> >> >> Regards,
> >> >> Vishwas
> >> >>
> >> >>
> >> >> On Wed, Mar 13, 2019 at 5:08 AM ivange larry <iv...@gmail.com>
> >> >> wrote:
> >> >>
> >> >> > Hi all,
> >> >> >
> >> >> > I'm trying to add a new endpoint /healthCheck which will always
> >> respond
> >> >> > with 200 to confirm that the server is reachable. I have
> implemented
> >> a
> >> >> > HealthCheckResource.java in org.apache.fineract.system.api. I
> created
> >> >> the
> >> >> > package system.api. Here's my resource class
> >> >> >
> >> >> > https://gist.github.com/ivange94/3b67a80c6d9f90adeceddf052c6026d5
> >> >> >
> >> >> > I keep getting a 404 when I try to access the endpoint at
> >> >> >
> >> >> >
> >> >>
> >>
> https://localhost:8443/fineract-provider/api/v1/healthCheck?tenantIdentifier=default
> >> >> > .
> >> >> >
> >> >> > Is there anything I'm missing?
> >> >> >
> >> >> > Thanks,
> >> >> > Larry
> >> >> >
> >> >>
> >> >
> >> >
> >> > --
> >> > GSoC 2016 @OpenMRS
> >> > GSoC 2017 @LibreHealth
> >> > GCI 2016 Mentor @OpenMRS
> >> > GCI Org Admin @OpenMRS
> >> >
> >>
> >>
> >> --
> >> GSoC 2016 @OpenMRS
> >> GSoC 2017 @LibreHealth
> >> GCI 2016 Mentor @OpenMRS
> >> GCI Org Admin @OpenMRS
> >>
> >
>
--
GSoC 2016 @OpenMRS
GSoC 2017 @LibreHealth
GCI 2016 Mentor @OpenMRS
GCI Org Admin @OpenMRS
Re: Adding a new Resource in Fineract 1.x
Posted by Courage Angeh <co...@gmail.com>.
Sorry wrong code, this is the right one.
*. . .*
<context:component-scan
base-package="org.apache.fineract.accounting.*
org.apache.fineract.commands.provider.*,
org.apache.fineract.commands.handler.*,
*...*
org.apache.fineract.system.*">
<context:exclude-filter expression="
org.springframework.stereotype.Controller"
* ...*
On Wed, Mar 13, 2019 at 4:42 PM Courage Angeh <co...@gmail.com>
wrote:
> Hi Larry,
>
> You need to add your base package to the
> fineract-provider/src/main/resources/META-INF/spring/appContext.xml
> <https://github.com/apache/fineract/pull/283/files#diff-f3d6abe979dfc7dfbafc5831007ba31e> like
> so:
>
> *. . .*
> <context:component-scan
> base-package="org.apache.fineract.accounting.*
> org.apache.fineract.commands.provider.*,
> org.apache.fineract.commands.handler.*,
> *...*
>
> org.apache.fineract.notification.*">
> <context:exclude-filter expression="
> org.springframework.stereotype.Controller"
> * ...*
>
> On Wed, Mar 13, 2019 at 11:43 AM ivange larry <iv...@gmail.com>
> wrote:
>
>> Maybe I should mention that I do get this strange error when I run the
>> application. https://pastebin.com/t3H2LBNa
>>
>> The application seems to look for the resource class in the wrong location
>> and returns a ClassNotFoundException
>>
>> On Wed, Mar 13, 2019 at 4:39 PM ivange larry <iv...@gmail.com>
>> wrote:
>>
>> > Thanks Vishwas for that observation. Unfortunately, it still doesn't
>> work.
>> > I have tried with this url
>> >
>> >
>> >
>> https://localhost:8443/fineract-provider/api/v1/heathCheck?tenantIdentifier=default
>> >
>> > Since that's the one I actually coded accidentally and it still returns
>> > 404. The parameter tenantIdentifier is only present because I just
>> copied
>> > that link from other resources and changed the resource to heathCheck.
>> But
>> > my implementation does not actually expect a parameter. When I delete
>> the
>> > parameter from the string and make a request with
>> > https://localhost:8443/fineract-provider/api/v1/heathCheck, I now get a
>> > 400 error complaining of the missing parameter.
>> >
>> > Is there a guide that documents the steps needed to add a new resource?
>> >
>> > Let outline again the steps I took, maybe my code changes are not even
>> > reflected in the deployment.
>> >
>> > 1) I added a class HealthCheckResource as already explained above.
>> > 2) Build application with ./gradlew build
>> > 3) Run application with ./gradlew tomcatRunWar
>> >
>> > Let me know if I'm doing something wrong.
>> >
>> > Thanks,
>> > Larry
>> >
>> > On Wed, Mar 13, 2019 at 3:43 PM Vishwas Babu <
>> > vishwas@confluxtechnologies.com> wrote:
>> >
>> >> Larry,
>> >>
>> >> There is a typo in the path parameter of your resource class, i.e
>> >> heathCheck instead
>> >> of healthCheck
>> >>
>> >> Regards,
>> >> Vishwas
>> >>
>> >>
>> >> On Wed, Mar 13, 2019 at 5:08 AM ivange larry <iv...@gmail.com>
>> >> wrote:
>> >>
>> >> > Hi all,
>> >> >
>> >> > I'm trying to add a new endpoint /healthCheck which will always
>> respond
>> >> > with 200 to confirm that the server is reachable. I have implemented
>> a
>> >> > HealthCheckResource.java in org.apache.fineract.system.api. I created
>> >> the
>> >> > package system.api. Here's my resource class
>> >> >
>> >> > https://gist.github.com/ivange94/3b67a80c6d9f90adeceddf052c6026d5
>> >> >
>> >> > I keep getting a 404 when I try to access the endpoint at
>> >> >
>> >> >
>> >>
>> https://localhost:8443/fineract-provider/api/v1/healthCheck?tenantIdentifier=default
>> >> > .
>> >> >
>> >> > Is there anything I'm missing?
>> >> >
>> >> > Thanks,
>> >> > Larry
>> >> >
>> >>
>> >
>> >
>> > --
>> > GSoC 2016 @OpenMRS
>> > GSoC 2017 @LibreHealth
>> > GCI 2016 Mentor @OpenMRS
>> > GCI Org Admin @OpenMRS
>> >
>>
>>
>> --
>> GSoC 2016 @OpenMRS
>> GSoC 2017 @LibreHealth
>> GCI 2016 Mentor @OpenMRS
>> GCI Org Admin @OpenMRS
>>
>
Re: Adding a new Resource in Fineract 1.x
Posted by Courage Angeh <co...@gmail.com>.
Hi Larry,
You need to add your base package to the
fineract-provider/src/main/resources/META-INF/spring/appContext.xml
<https://github.com/apache/fineract/pull/283/files#diff-f3d6abe979dfc7dfbafc5831007ba31e>
like
so:
*. . .*
<context:component-scan
base-package="org.apache.fineract.accounting.*
org.apache.fineract.commands.provider.*,
org.apache.fineract.commands.handler.*,
*...*
org.apache.fineract.notification.*">
<context:exclude-filter expression="
org.springframework.stereotype.Controller"
* ...*
On Wed, Mar 13, 2019 at 11:43 AM ivange larry <iv...@gmail.com> wrote:
> Maybe I should mention that I do get this strange error when I run the
> application. https://pastebin.com/t3H2LBNa
>
> The application seems to look for the resource class in the wrong location
> and returns a ClassNotFoundException
>
> On Wed, Mar 13, 2019 at 4:39 PM ivange larry <iv...@gmail.com>
> wrote:
>
> > Thanks Vishwas for that observation. Unfortunately, it still doesn't
> work.
> > I have tried with this url
> >
> >
> >
> https://localhost:8443/fineract-provider/api/v1/heathCheck?tenantIdentifier=default
> >
> > Since that's the one I actually coded accidentally and it still returns
> > 404. The parameter tenantIdentifier is only present because I just copied
> > that link from other resources and changed the resource to heathCheck.
> But
> > my implementation does not actually expect a parameter. When I delete the
> > parameter from the string and make a request with
> > https://localhost:8443/fineract-provider/api/v1/heathCheck, I now get a
> > 400 error complaining of the missing parameter.
> >
> > Is there a guide that documents the steps needed to add a new resource?
> >
> > Let outline again the steps I took, maybe my code changes are not even
> > reflected in the deployment.
> >
> > 1) I added a class HealthCheckResource as already explained above.
> > 2) Build application with ./gradlew build
> > 3) Run application with ./gradlew tomcatRunWar
> >
> > Let me know if I'm doing something wrong.
> >
> > Thanks,
> > Larry
> >
> > On Wed, Mar 13, 2019 at 3:43 PM Vishwas Babu <
> > vishwas@confluxtechnologies.com> wrote:
> >
> >> Larry,
> >>
> >> There is a typo in the path parameter of your resource class, i.e
> >> heathCheck instead
> >> of healthCheck
> >>
> >> Regards,
> >> Vishwas
> >>
> >>
> >> On Wed, Mar 13, 2019 at 5:08 AM ivange larry <iv...@gmail.com>
> >> wrote:
> >>
> >> > Hi all,
> >> >
> >> > I'm trying to add a new endpoint /healthCheck which will always
> respond
> >> > with 200 to confirm that the server is reachable. I have implemented a
> >> > HealthCheckResource.java in org.apache.fineract.system.api. I created
> >> the
> >> > package system.api. Here's my resource class
> >> >
> >> > https://gist.github.com/ivange94/3b67a80c6d9f90adeceddf052c6026d5
> >> >
> >> > I keep getting a 404 when I try to access the endpoint at
> >> >
> >> >
> >>
> https://localhost:8443/fineract-provider/api/v1/healthCheck?tenantIdentifier=default
> >> > .
> >> >
> >> > Is there anything I'm missing?
> >> >
> >> > Thanks,
> >> > Larry
> >> >
> >>
> >
> >
> > --
> > GSoC 2016 @OpenMRS
> > GSoC 2017 @LibreHealth
> > GCI 2016 Mentor @OpenMRS
> > GCI Org Admin @OpenMRS
> >
>
>
> --
> GSoC 2016 @OpenMRS
> GSoC 2017 @LibreHealth
> GCI 2016 Mentor @OpenMRS
> GCI Org Admin @OpenMRS
>
Re: Adding a new Resource in Fineract 1.x
Posted by ivange larry <iv...@gmail.com>.
Maybe I should mention that I do get this strange error when I run the
application. https://pastebin.com/t3H2LBNa
The application seems to look for the resource class in the wrong location
and returns a ClassNotFoundException
On Wed, Mar 13, 2019 at 4:39 PM ivange larry <iv...@gmail.com> wrote:
> Thanks Vishwas for that observation. Unfortunately, it still doesn't work.
> I have tried with this url
>
>
> https://localhost:8443/fineract-provider/api/v1/heathCheck?tenantIdentifier=default
>
> Since that's the one I actually coded accidentally and it still returns
> 404. The parameter tenantIdentifier is only present because I just copied
> that link from other resources and changed the resource to heathCheck. But
> my implementation does not actually expect a parameter. When I delete the
> parameter from the string and make a request with
> https://localhost:8443/fineract-provider/api/v1/heathCheck, I now get a
> 400 error complaining of the missing parameter.
>
> Is there a guide that documents the steps needed to add a new resource?
>
> Let outline again the steps I took, maybe my code changes are not even
> reflected in the deployment.
>
> 1) I added a class HealthCheckResource as already explained above.
> 2) Build application with ./gradlew build
> 3) Run application with ./gradlew tomcatRunWar
>
> Let me know if I'm doing something wrong.
>
> Thanks,
> Larry
>
> On Wed, Mar 13, 2019 at 3:43 PM Vishwas Babu <
> vishwas@confluxtechnologies.com> wrote:
>
>> Larry,
>>
>> There is a typo in the path parameter of your resource class, i.e
>> heathCheck instead
>> of healthCheck
>>
>> Regards,
>> Vishwas
>>
>>
>> On Wed, Mar 13, 2019 at 5:08 AM ivange larry <iv...@gmail.com>
>> wrote:
>>
>> > Hi all,
>> >
>> > I'm trying to add a new endpoint /healthCheck which will always respond
>> > with 200 to confirm that the server is reachable. I have implemented a
>> > HealthCheckResource.java in org.apache.fineract.system.api. I created
>> the
>> > package system.api. Here's my resource class
>> >
>> > https://gist.github.com/ivange94/3b67a80c6d9f90adeceddf052c6026d5
>> >
>> > I keep getting a 404 when I try to access the endpoint at
>> >
>> >
>> https://localhost:8443/fineract-provider/api/v1/healthCheck?tenantIdentifier=default
>> > .
>> >
>> > Is there anything I'm missing?
>> >
>> > Thanks,
>> > Larry
>> >
>>
>
>
> --
> GSoC 2016 @OpenMRS
> GSoC 2017 @LibreHealth
> GCI 2016 Mentor @OpenMRS
> GCI Org Admin @OpenMRS
>
--
GSoC 2016 @OpenMRS
GSoC 2017 @LibreHealth
GCI 2016 Mentor @OpenMRS
GCI Org Admin @OpenMRS
Re: Adding a new Resource in Fineract 1.x
Posted by ivange larry <iv...@gmail.com>.
Thanks Vishwas for that observation. Unfortunately, it still doesn't work.
I have tried with this url
https://localhost:8443/fineract-provider/api/v1/heathCheck?tenantIdentifier=default
Since that's the one I actually coded accidentally and it still returns
404. The parameter tenantIdentifier is only present because I just copied
that link from other resources and changed the resource to heathCheck. But
my implementation does not actually expect a parameter. When I delete the
parameter from the string and make a request with
https://localhost:8443/fineract-provider/api/v1/heathCheck, I now get a 400
error complaining of the missing parameter.
Is there a guide that documents the steps needed to add a new resource?
Let outline again the steps I took, maybe my code changes are not even
reflected in the deployment.
1) I added a class HealthCheckResource as already explained above.
2) Build application with ./gradlew build
3) Run application with ./gradlew tomcatRunWar
Let me know if I'm doing something wrong.
Thanks,
Larry
On Wed, Mar 13, 2019 at 3:43 PM Vishwas Babu <
vishwas@confluxtechnologies.com> wrote:
> Larry,
>
> There is a typo in the path parameter of your resource class, i.e
> heathCheck instead
> of healthCheck
>
> Regards,
> Vishwas
>
>
> On Wed, Mar 13, 2019 at 5:08 AM ivange larry <iv...@gmail.com>
> wrote:
>
> > Hi all,
> >
> > I'm trying to add a new endpoint /healthCheck which will always respond
> > with 200 to confirm that the server is reachable. I have implemented a
> > HealthCheckResource.java in org.apache.fineract.system.api. I created the
> > package system.api. Here's my resource class
> >
> > https://gist.github.com/ivange94/3b67a80c6d9f90adeceddf052c6026d5
> >
> > I keep getting a 404 when I try to access the endpoint at
> >
> >
> https://localhost:8443/fineract-provider/api/v1/healthCheck?tenantIdentifier=default
> > .
> >
> > Is there anything I'm missing?
> >
> > Thanks,
> > Larry
> >
>
--
GSoC 2016 @OpenMRS
GSoC 2017 @LibreHealth
GCI 2016 Mentor @OpenMRS
GCI Org Admin @OpenMRS
Re: Adding a new Resource in Fineract 1.x
Posted by Vishwas Babu <vi...@confluxtechnologies.com>.
Larry,
There is a typo in the path parameter of your resource class, i.e
heathCheck instead
of healthCheck
Regards,
Vishwas
On Wed, Mar 13, 2019 at 5:08 AM ivange larry <iv...@gmail.com> wrote:
> Hi all,
>
> I'm trying to add a new endpoint /healthCheck which will always respond
> with 200 to confirm that the server is reachable. I have implemented a
> HealthCheckResource.java in org.apache.fineract.system.api. I created the
> package system.api. Here's my resource class
>
> https://gist.github.com/ivange94/3b67a80c6d9f90adeceddf052c6026d5
>
> I keep getting a 404 when I try to access the endpoint at
>
> https://localhost:8443/fineract-provider/api/v1/healthCheck?tenantIdentifier=default
> .
>
> Is there anything I'm missing?
>
> Thanks,
> Larry
>