Re: Question about validating a XmlObject

[Radu Preotiuc-Pietro <ra...@bea.com>]

Also, if you have programatically compiled your Schema, you should have
a reference to a SchemaTypeSystem object.

XmlObject xml = schemaTypeSystem.parse(xmlFile)

will make sure that the "xml" XmlObject has the right type from the
beginning.

Radu

On Thu, 2007-05-31 at 14:33 -0700, Jacob Danner wrote:
> Hi Patrizio,
> There is a method on the XmlObject class that should allow the
> functionality you are looking for. The method is changeType().
> 
>  XmlObject 	changeType(SchemaType newType)
>           Changes the schema type associated with this data and
> returns a new XmlObject instance whose schemaType is the new type.
> 
> http://xmlbeans.apache.org/docs/2.2.0/reference/org/apache/xmlbeans/XmlObject.html#changeType(org.apache.xmlbeans.SchemaType)
> Please let the list know if you have any other problems.
> Thanks,
> -Jacob Danner
> 
> 
> On 5/31/07, Patrizio.Ferlito@b-source.ch <Pa...@b-source.ch> wrote:
> > Hi all,
> >
> > I would like to validate a xml document against a given xsd.
> > My xml document doesn't contain any xsi:schemaLocation but the given xsd
> > is well known.
> >
> > Below I reported a piece of code:
> >
> >   File xmlFile = new File(xmlFilePath);
> >   XmlObject xml = XmlObject.Factory.parse(xmlFile);
> >
> >   System.out.println("Schema type: " + xml.schemaType()); //output is
> > 'Schema type: N='
> >
> >   // Validate the XML.
> >   boolean isValid = xml.validate(validateOptions);
> >
> > If I know what is the given xsd (xsdFilePath), how can I specify what
> > xsd to be used ?
> > Is there any setSchemaType() / assignSchemaType() ?
> >
> > Thanks
> > Patrizio
> >
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