[jira] Created: (OJB-104) Report sub-query in ORDER BY clause

["Vasily Ivanov (JIRA)" <ji...@apache.org>]

Report sub-query in ORDER BY clause
-----------------------------------

         Key: OJB-104
         URL: http://issues.apache.org/jira/browse/OJB-104
     Project: OJB
        Type: Improvement
  Components: PB-API  
    Versions: 1.0.4, 1.0.3    
    Reporter: Vasily Ivanov
    Priority: Minor


There is no way in OJB to set report sub-query to ORDER BY clause.

QueryByCriteria.addOrderBy(String, boolean)
QueryByCriteria.addOrderBy(FieldHelper)
QueryByCriteria.addOrderByAscending(String)
QueryByCriteria.addOrderByDescending(String)

... no methods to set report sub-query.

Workaround:
I've got 2 classes:
class Parent:
 int id
 String data
 Collection children
class Child:
 int id
 String data
 int parentId
 Parent parent

I need to get collection of parents sorted by the number of children.
This is the code that works:
>QueryByCriteria query = QueryFactory.newQuery(Parent.class, new Criteria());
>query.addOrderByDescending("(SELECT count(1) FROM CHILD AAA WHERE
AAA.PARENT_ID = A0.ID)");
>persistenceManager.getBroker().getCollectionByQuery(query);

This is generated sql:
> SELECT A0.ID, A0.DATA, (SELECT count(1)
                                          FROM CHILD AAA
                                          WHERE AAA.PARENT_ID =
A0.ID) as ojb_col_3
> FROM PARENT A0
> ORDER BY 3 DESC

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