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Posted to users@tapestry.apache.org by Lidija Dolinar <li...@gmail.com> on 2014/01/02 08:59:08 UTC
How to retrieve complete current URL with context
Hi,
My page name is Najdi and I have a query parameter appended to the link so
the link looks like this: http://localhost:8080/najdi/test .
I need to remember this url because I'm redirecting user back to this page
later on when he logs in (we have a custom login page).
I'm assigning resources.getPageName(); to the session variable - in this
case the value is Najdi, so the redirection url is
http://localhost:8080/Najdi. But I also need the additional parameters -
context ("test" in the above case). It would be very nice if I could just
read the whole URL, save it into session and then redirect user back to
this url.
But I'm having difficulties getting complete url:
linkSource.createPageRenderLink(resources.getPageName(),
false).toAbsoluteURI();
returns "http://localhost:8080/Najdi".
So my question is - how can I simply retrieve complete URL with context (if
it exists), in other words, is there a simple way to get "
http://localhost:8080/najdi/test"?
Kind regards,
Lidija
Re: How to retrieve complete current URL with context
Posted by Lidija Dolinar <li...@gmail.com>.
I already have Request object injected as you specified.
My import is:
import org.apache.tapestry5.services.Request;
but it doesn't have getRequestURL() method, there's only
request.getRemoteHost().
I should probably have servletRequest injected:
@Inject
private HttpServletRequest servletRequest;
and then call servletRequest.getRequestURL(), but it doesn't give me the
"correct" url - i get "
http://localhost:8080/najdi.layoutnajdi.loginlink.prijava"
Regards,
Lidija
On Thu, Jan 2, 2014 at 9:05 AM, Matthias <th...@gmail.com> wrote:
> Hi, you could try to inject the tapestry request class.
>
> @Inject
> Request request
>
> void func() {
> String url = request.getRequestURL();
>
> }
>
> On 02.01.2014 08:59, Lidija Dolinar wrote:
>
>> Hi,
>>
>> My page name is Najdi and I have a query parameter appended to the link so
>> the link looks like this: http://localhost:8080/najdi/test .
>>
>> I need to remember this url because I'm redirecting user back to this page
>> later on when he logs in (we have a custom login page).
>>
>> I'm assigning resources.getPageName(); to the session variable - in this
>> case the value is Najdi, so the redirection url is
>> http://localhost:8080/Najdi. But I also need the additional parameters -
>> context ("test" in the above case). It would be very nice if I could just
>> read the whole URL, save it into session and then redirect user back to
>> this url.
>>
>> But I'm having difficulties getting complete url:
>>
>> linkSource.createPageRenderLink(resources.getPageName(),
>> false).toAbsoluteURI();
>>
>> returns "http://localhost:8080/Najdi".
>>
>> So my question is - how can I simply retrieve complete URL with context
>> (if
>> it exists), in other words, is there a simple way to get "
>> http://localhost:8080/najdi/test"?
>>
>> Kind regards,
>> Lidija
>>
>>
>
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>
>
Re: How to retrieve complete current URL with context
Posted by Matthias <th...@gmail.com>.
Hi, you could try to inject the tapestry request class.
@Inject
Request request
void func() {
String url = request.getRequestURL();
}
On 02.01.2014 08:59, Lidija Dolinar wrote:
> Hi,
>
> My page name is Najdi and I have a query parameter appended to the link so
> the link looks like this: http://localhost:8080/najdi/test .
>
> I need to remember this url because I'm redirecting user back to this page
> later on when he logs in (we have a custom login page).
>
> I'm assigning resources.getPageName(); to the session variable - in this
> case the value is Najdi, so the redirection url is
> http://localhost:8080/Najdi. But I also need the additional parameters -
> context ("test" in the above case). It would be very nice if I could just
> read the whole URL, save it into session and then redirect user back to
> this url.
>
> But I'm having difficulties getting complete url:
>
> linkSource.createPageRenderLink(resources.getPageName(),
> false).toAbsoluteURI();
>
> returns "http://localhost:8080/Najdi".
>
> So my question is - how can I simply retrieve complete URL with context (if
> it exists), in other words, is there a simple way to get "
> http://localhost:8080/najdi/test"?
>
> Kind regards,
> Lidija
>
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Re: How to retrieve complete current URL with context
Posted by Lidija Dolinar <li...@gmail.com>.
You're right, of course :).
Sorry for the confusion - "test" string in above url represents query in
our application.
Regards,
Lidija
On Thu, Jan 2, 2014 at 12:25 PM, Thiago H de Paula Figueiredo <
thiagohp@gmail.com> wrote:
> On Thu, 02 Jan 2014 05:59:08 -0200, Lidija Dolinar <li...@gmail.com>
> wrote:
>
> Hi,
>>
>
> Hi!
>
>
> My page name is Najdi and I have a query parameter appended to the link
>> so the link looks like this: http://localhost:8080/najdi/test .
>>
>
> Jan already answered your question, but I'd like to add something: the URL
> above does *not* have any query parameters. It has a page activation
> context.
>
> --
> Thiago H. de Paula Figueiredo
> Tapestry, Java and Hibernate consultant and developer
> http://machina.com.br
>
>
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> To unsubscribe, e-mail: users-unsubscribe@tapestry.apache.org
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>
>
Re: How to retrieve complete current URL with context
Posted by Thiago H de Paula Figueiredo <th...@gmail.com>.
On Thu, 02 Jan 2014 05:59:08 -0200, Lidija Dolinar <li...@gmail.com>
wrote:
> Hi,
Hi!
> My page name is Najdi and I have a query parameter appended to the link
> so the link looks like this: http://localhost:8080/najdi/test .
Jan already answered your question, but I'd like to add something: the URL
above does *not* have any query parameters. It has a page activation
context.
--
Thiago H. de Paula Figueiredo
Tapestry, Java and Hibernate consultant and developer
http://machina.com.br
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Re: How to retrieve complete current URL with context
Posted by Lidija Dolinar <li...@gmail.com>.
Thank you!
It indeed helped :).
I added onPassivate method to Najdi page:
String onPassivate() {
return q; // returns query parameter
}
And now I get the complete URL with the following code:
String absolute = linkSource.createPageRenderLink(resources.getPageName(),
false).toAbsoluteURI();
Regards,
Lidija
On Thu, Jan 2, 2014 at 9:16 AM, Jan Fryblik <ja...@ebrothers.cz>wrote:
>
> Hi,
>
> may be that link would help you.
>
> http://jumpstart.doublenegative.com.au/jumpstart/examples/navigation/
> returntopage1/abc
>
>
> BR,
> Jan
>
>
Re: How to retrieve complete current URL with context
Posted by Jan Fryblik <ja...@ebrothers.cz>.
Hi,
may be that link would help you.
http://jumpstart.doublenegative.com.au/jumpstart/examples/navigation/returntopage1/abc
BR,
Jan
On Thu, 02 Jan 2014 08:59:08 +0100, Lidija Dolinar <li...@gmail.com>
wrote:
> Hi,
>
> My page name is Najdi and I have a query parameter appended to the link
> so
> the link looks like this: http://localhost:8080/najdi/test .
>
> I need to remember this url because I'm redirecting user back to this
> page
> later on when he logs in (we have a custom login page).
>
> I'm assigning resources.getPageName(); to the session variable - in this
> case the value is Najdi, so the redirection url is
> http://localhost:8080/Najdi. But I also need the additional parameters -
> context ("test" in the above case). It would be very nice if I could just
> read the whole URL, save it into session and then redirect user back to
> this url.
>
> But I'm having difficulties getting complete url:
>
> linkSource.createPageRenderLink(resources.getPageName(),
> false).toAbsoluteURI();
>
> returns "http://localhost:8080/Najdi".
>
> So my question is - how can I simply retrieve complete URL with context
> (if
> it exists), in other words, is there a simple way to get "
> http://localhost:8080/najdi/test"?
>
> Kind regards,
> Lidija
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