You are viewing a plain text version of this content. The canonical link for it is here.
Posted to users@tomcat.apache.org by Chen Yang <cy...@hrsg.ca> on 2015/10/02 16:42:50 UTC
The resource path [...] is not valid
Hi all,
I'm transforming xml into pdf files, but getting this strange error in my log. (tomcat 8.0.26)
The resource path [file:/C:/Program%20Files/Apache%20Software%20Foundation/Tomcat%208.0/] is not valid
Here is my code
//Setup sources
StreamSource xmlSrc = new StreamSource(new URL(rootUrl + "/output/xml/" + xml).openStream());
StreamSource xsltSrc = new StreamSource(new URL(rootUrl + "/output/xslt/" + xslt).openStream());
//Setup the XSL transformation
Transformer transformer = this.transFactory.newTransformer(xsltSrc); //error out
transformer.setURIResolver(this.uriResolver);
XML & XSLT file are not stored locally, so I don't understand why it's looking at the tomcat folder?
Cheers,
Chen
RE: The resource path [...] is not valid
Posted by "Terence M. Bandoian" <te...@tmbsw.com>.
On 10/2/2015 10:28 AM, Chen Yang wrote:
> I wonder if it's because of this?
>
> org.apache.fop.servlet.FopServlet$1.getResource(FopServlet.java:116)
>
> this.uriResolver = new ServletContextURIResolver(getServletContext());
> this.transFactory = TransformerFactory.newInstance();
> this.transFactory.setURIResolver(this.uriResolver);
> //Configure FopFactory as desired
> ResourceResolver resolver = new ResourceResolver() {
> public OutputStream getOutputStream(URI uri) throws IOException {
> URL url = getServletContext().getResource(uri.toASCIIString());
> return url.openConnection().getOutputStream();
> }
>
> public Resource getResource(URI uri) throws IOException {
> return new Resource(getServletContext().getResourceAsStream(uri.toASCIIString())); //line 116
> }
> };
> FopFactoryBuilder builder = new FopFactoryBuilder(new File(".").toURI(), resolver);
>
> root cause
> java.lang.IllegalArgumentException: The resource path [file:/C:/Program%20Files/Apache%20Software%20Foundation/Tomcat%208.0/] is not valid
> org.apache.catalina.webresources.StandardRoot.validate(StandardRoot.java:250)
> org.apache.catalina.webresources.StandardRoot.getResource(StandardRoot.java:212)
> org.apache.catalina.webresources.StandardRoot.getResource(StandardRoot.java:206)
> org.apache.fop.servlet.FopServlet$1.getResource(FopServlet.java:116)
> org.apache.fop.apps.io.InternalResourceResolver.getResource(InternalResourceResolver.java:92)
> org.apache.fop.apps.io.InternalResourceResolver.getResource(InternalResourceResolver.java:78)
> org.apache.fop.apps.FOUserAgent.resolveURI(FOUserAgent.java:411)
> org.apache.fop.apps.FOUserAgent$1.resolveURI(FOUserAgent.java:160)
> org.apache.xmlgraphics.image.loader.impl.AbstractImageSessionContext.newSource(AbstractImageSessionContext.java:92)
> org.apache.xmlgraphics.image.loader.impl.AbstractImageSessionContext.needSource(AbstractImageSessionContext.java:191)
> org.apache.xmlgraphics.image.loader.cache.ImageCache.needImageInfo(ImageCache.java:123)
> org.apache.xmlgraphics.image.loader.ImageManager.getImageInfo(ImageManager.java:123)
> org.apache.fop.fo.flow.ExternalGraphic.bind(ExternalGraphic.java:81)
> org.apache.fop.fo.FObj.processNode(FObj.java:129)
> org.apache.fop.fo.FOTreeBuilder$MainFOHandler.startElement(FOTreeBuilder.java:291)
> org.apache.fop.fo.FOTreeBuilder.startElement(FOTreeBuilder.java:179)
> com.sun.org.apache.xml.internal.serializer.ToXMLSAXHandler.closeStartTag(Unknown Source)
> com.sun.org.apache.xml.internal.serializer.ToSAXHandler.flushPending(Unknown Source)
> com.sun.org.apache.xml.internal.serializer.ToXMLSAXHandler.endElement(Unknown Source)
> com.sun.org.apache.xml.internal.serializer.ToXMLSAXHandler.endElement(Unknown Source)
> GregorSamsa.insert_cover_page_template()
> GregorSamsa.template$dot$0()
> GregorSamsa.applyTemplates()
> GregorSamsa.transform()
> com.sun.org.apache.xalan.internal.xsltc.runtime.AbstractTranslet.transform(Unknown Source)
> com.sun.org.apache.xalan.internal.xsltc.trax.TransformerImpl.transform(Unknown Source)
> com.sun.org.apache.xalan.internal.xsltc.trax.TransformerImpl.transform(Unknown Source)
> org.apache.fop.servlet.FopServlet.render(FopServlet.java:397)
> org.apache.fop.servlet.FopServlet.renderXML(FopServlet.java:342)
> org.apache.fop.servlet.FopServlet.doGet(FopServlet.java:150)
> javax.servlet.http.HttpServlet.service(HttpServlet.java:618)
> javax.servlet.http.HttpServlet.service(HttpServlet.java:725)
> org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
>
>
>
> -----Original Message-----
> From: Christopher Schultz [mailto:chris@christopherschultz.net]
> Sent: Friday, October 02, 2015 11:05 AM
> To: Tomcat Users List<us...@tomcat.apache.org>
> Subject: Re: The resource path [...] is not valid
>
> -----BEGIN PGP SIGNED MESSAGE-----
> Hash: SHA256
>
> Chen,
>
> On 10/2/15 10:42 AM, Chen Yang wrote:
>> >I'm transforming xml into pdf files, but getting this strange error in
>> >my log. (tomcat 8.0.26)
>> >
>> >The resource path
>> >[file:/C:/Program%20Files/Apache%20Software%20Foundation/Tomcat%208.0/
> ]
>> >is not valid
>> >
>> >Here is my code
>> >
>> >//Setup sources StreamSource xmlSrc = new StreamSource(new URL(rootUrl
>> >+ "/output/xml/" + xml).openStream()); StreamSource xsltSrc = new
>> >StreamSource(new URL(rootUrl + "/output/xslt/" + xslt).openStream());
> What's the value of "rootUrl"?
>
>> >//Setup the XSL transformation Transformer transformer =
>> >this.transFactory.newTransformer(xsltSrc); //error out
>> >transformer.setURIResolver(this.uriResolver);
>> >
>> >XML & XSLT file are not stored locally, so I don't understand why it's
>> >looking at the tomcat folder?
> What's the stack trace?
>
> - -chris
Are you able to execute the transformation stand-alone (not within Tomcat)?
Also, you may want to ask this on the Apache FOP users mailing list:
https://xmlgraphics.apache.org/fop/maillist.html
-Terence Bandoian
---------------------------------------------------------------------
To unsubscribe, e-mail: users-unsubscribe@tomcat.apache.org
For additional commands, e-mail: users-help@tomcat.apache.org
RE: The resource path [...] is not valid
Posted by Chen Yang <cy...@hrsg.ca>.
I wonder if it's because of this?
org.apache.fop.servlet.FopServlet$1.getResource(FopServlet.java:116)
this.uriResolver = new ServletContextURIResolver(getServletContext());
this.transFactory = TransformerFactory.newInstance();
this.transFactory.setURIResolver(this.uriResolver);
//Configure FopFactory as desired
ResourceResolver resolver = new ResourceResolver() {
public OutputStream getOutputStream(URI uri) throws IOException {
URL url = getServletContext().getResource(uri.toASCIIString());
return url.openConnection().getOutputStream();
}
public Resource getResource(URI uri) throws IOException {
return new Resource(getServletContext().getResourceAsStream(uri.toASCIIString())); //line 116
}
};
FopFactoryBuilder builder = new FopFactoryBuilder(new File(".").toURI(), resolver);
root cause
java.lang.IllegalArgumentException: The resource path [file:/C:/Program%20Files/Apache%20Software%20Foundation/Tomcat%208.0/] is not valid
org.apache.catalina.webresources.StandardRoot.validate(StandardRoot.java:250)
org.apache.catalina.webresources.StandardRoot.getResource(StandardRoot.java:212)
org.apache.catalina.webresources.StandardRoot.getResource(StandardRoot.java:206)
org.apache.fop.servlet.FopServlet$1.getResource(FopServlet.java:116)
org.apache.fop.apps.io.InternalResourceResolver.getResource(InternalResourceResolver.java:92)
org.apache.fop.apps.io.InternalResourceResolver.getResource(InternalResourceResolver.java:78)
org.apache.fop.apps.FOUserAgent.resolveURI(FOUserAgent.java:411)
org.apache.fop.apps.FOUserAgent$1.resolveURI(FOUserAgent.java:160)
org.apache.xmlgraphics.image.loader.impl.AbstractImageSessionContext.newSource(AbstractImageSessionContext.java:92)
org.apache.xmlgraphics.image.loader.impl.AbstractImageSessionContext.needSource(AbstractImageSessionContext.java:191)
org.apache.xmlgraphics.image.loader.cache.ImageCache.needImageInfo(ImageCache.java:123)
org.apache.xmlgraphics.image.loader.ImageManager.getImageInfo(ImageManager.java:123)
org.apache.fop.fo.flow.ExternalGraphic.bind(ExternalGraphic.java:81)
org.apache.fop.fo.FObj.processNode(FObj.java:129)
org.apache.fop.fo.FOTreeBuilder$MainFOHandler.startElement(FOTreeBuilder.java:291)
org.apache.fop.fo.FOTreeBuilder.startElement(FOTreeBuilder.java:179)
com.sun.org.apache.xml.internal.serializer.ToXMLSAXHandler.closeStartTag(Unknown Source)
com.sun.org.apache.xml.internal.serializer.ToSAXHandler.flushPending(Unknown Source)
com.sun.org.apache.xml.internal.serializer.ToXMLSAXHandler.endElement(Unknown Source)
com.sun.org.apache.xml.internal.serializer.ToXMLSAXHandler.endElement(Unknown Source)
GregorSamsa.insert_cover_page_template()
GregorSamsa.template$dot$0()
GregorSamsa.applyTemplates()
GregorSamsa.transform()
com.sun.org.apache.xalan.internal.xsltc.runtime.AbstractTranslet.transform(Unknown Source)
com.sun.org.apache.xalan.internal.xsltc.trax.TransformerImpl.transform(Unknown Source)
com.sun.org.apache.xalan.internal.xsltc.trax.TransformerImpl.transform(Unknown Source)
org.apache.fop.servlet.FopServlet.render(FopServlet.java:397)
org.apache.fop.servlet.FopServlet.renderXML(FopServlet.java:342)
org.apache.fop.servlet.FopServlet.doGet(FopServlet.java:150)
javax.servlet.http.HttpServlet.service(HttpServlet.java:618)
javax.servlet.http.HttpServlet.service(HttpServlet.java:725)
org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
-----Original Message-----
From: Christopher Schultz [mailto:chris@christopherschultz.net]
Sent: Friday, October 02, 2015 11:05 AM
To: Tomcat Users List <us...@tomcat.apache.org>
Subject: Re: The resource path [...] is not valid
-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA256
Chen,
On 10/2/15 10:42 AM, Chen Yang wrote:
> I'm transforming xml into pdf files, but getting this strange error in
> my log. (tomcat 8.0.26)
>
> The resource path
> [file:/C:/Program%20Files/Apache%20Software%20Foundation/Tomcat%208.0/
]
> is not valid
>
> Here is my code
>
> //Setup sources StreamSource xmlSrc = new StreamSource(new URL(rootUrl
> + "/output/xml/" + xml).openStream()); StreamSource xsltSrc = new
> StreamSource(new URL(rootUrl + "/output/xslt/" + xslt).openStream());
What's the value of "rootUrl"?
> //Setup the XSL transformation Transformer transformer =
> this.transFactory.newTransformer(xsltSrc); //error out
> transformer.setURIResolver(this.uriResolver);
>
> XML & XSLT file are not stored locally, so I don't understand why it's
> looking at the tomcat folder?
What's the stack trace?
- -chris
-----BEGIN PGP SIGNATURE-----
Comment: GPGTools - http://gpgtools.org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=+K3y
-----END PGP SIGNATURE-----
---------------------------------------------------------------------
To unsubscribe, e-mail: users-unsubscribe@tomcat.apache.org
For additional commands, e-mail: users-help@tomcat.apache.org
---------------------------------------------------------------------
To unsubscribe, e-mail: users-unsubscribe@tomcat.apache.org
For additional commands, e-mail: users-help@tomcat.apache.org
RE: The resource path [...] is not valid
Posted by Chen Yang <cy...@hrsg.ca>.
Hi Christ
javax.servlet.ServletException: javax.xml.transform.TransformerException: org.xml.sax.SAXException: The resource path [file:/C:/Program%20Files/Apache%20Software%20Foundation/Tomcat%208.0/] is not valid
java.lang.IllegalArgumentException: The resource path [file:/C:/Program%20Files/Apache%20Software%20Foundation/Tomcat%208.0/] is not valid
org.apache.fop.servlet.FopServlet.doGet(FopServlet.java:162)
javax.servlet.http.HttpServlet.service(HttpServlet.java:618)
javax.servlet.http.HttpServlet.service(HttpServlet.java:725)
org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
rootUrl is the site domain or IP. for example http://192.xxx.128.xx
here is the doGet(), just in case you want to see
public void doGet(HttpServletRequest request,HttpServletResponse response) throws ServletException, IOException {
try {
//Get parameters
String foParam = request.getParameter(FO_REQUEST_PARAM);
String xmlParam = request.getParameter(XML_REQUEST_PARAM);
String xsltParam = request.getParameter(XSLT_REQUEST_PARAM);
String rootParam = request.getParameter(ROOT_REQUEST_PARAM);
//Analyze parameters and decide with method to use
if (foParam != null) {
renderFO(foParam, response);
} else if ((xmlParam != null) && (xsltParam != null)) {
renderXML(xmlParam,xsltParam,rootParam,response);
} else {
response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("<html><head><title>Error</title></head>\n"
+ "<body><h1>FopServlet Error</h1><h3>No 'fo' "
+ "request param given.</body></html>");
}
} catch (Exception ex) {
throw new ServletException(ex);
}
}
-----Original Message-----
From: Christopher Schultz [mailto:chris@christopherschultz.net]
Sent: Friday, October 02, 2015 11:05 AM
To: Tomcat Users List <us...@tomcat.apache.org>
Subject: Re: The resource path [...] is not valid
-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA256
Chen,
On 10/2/15 10:42 AM, Chen Yang wrote:
> I'm transforming xml into pdf files, but getting this strange error in
> my log. (tomcat 8.0.26)
>
> The resource path
> [file:/C:/Program%20Files/Apache%20Software%20Foundation/Tomcat%208.0/
]
> is not valid
>
> Here is my code
>
> //Setup sources StreamSource xmlSrc = new StreamSource(new URL(rootUrl
> + "/output/xml/" + xml).openStream()); StreamSource xsltSrc = new
> StreamSource(new URL(rootUrl + "/output/xslt/" + xslt).openStream());
What's the value of "rootUrl"?
> //Setup the XSL transformation Transformer transformer =
> this.transFactory.newTransformer(xsltSrc); //error out
> transformer.setURIResolver(this.uriResolver);
>
> XML & XSLT file are not stored locally, so I don't understand why it's
> looking at the tomcat folder?
What's the stack trace?
- -chris
-----BEGIN PGP SIGNATURE-----
Comment: GPGTools - http://gpgtools.org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=+K3y
-----END PGP SIGNATURE-----
---------------------------------------------------------------------
To unsubscribe, e-mail: users-unsubscribe@tomcat.apache.org
For additional commands, e-mail: users-help@tomcat.apache.org
---------------------------------------------------------------------
To unsubscribe, e-mail: users-unsubscribe@tomcat.apache.org
For additional commands, e-mail: users-help@tomcat.apache.org
Re: The resource path [...] is not valid
Posted by Christopher Schultz <ch...@christopherschultz.net>.
-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA256
Chen,
On 10/2/15 10:42 AM, Chen Yang wrote:
> I'm transforming xml into pdf files, but getting this strange
> error in my log. (tomcat 8.0.26)
>
> The resource path
> [file:/C:/Program%20Files/Apache%20Software%20Foundation/Tomcat%208.0/
]
> is not valid
>
> Here is my code
>
> //Setup sources StreamSource xmlSrc = new StreamSource(new
> URL(rootUrl + "/output/xml/" + xml).openStream()); StreamSource
> xsltSrc = new StreamSource(new URL(rootUrl + "/output/xslt/" +
> xslt).openStream());
What's the value of "rootUrl"?
> //Setup the XSL transformation Transformer transformer =
> this.transFactory.newTransformer(xsltSrc); //error out
> transformer.setURIResolver(this.uriResolver);
>
> XML & XSLT file are not stored locally, so I don't understand why
> it's looking at the tomcat folder?
What's the stack trace?
- -chris
-----BEGIN PGP SIGNATURE-----
Comment: GPGTools - http://gpgtools.org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=+K3y
-----END PGP SIGNATURE-----
---------------------------------------------------------------------
To unsubscribe, e-mail: users-unsubscribe@tomcat.apache.org
For additional commands, e-mail: users-help@tomcat.apache.org