RE: How to parse an XML Tree that was created with the DOM API ? (in my servlet)

[MAHE Vincent FTRD/DIH/REN <vi...@rd.francetelecom.fr>]

You're right but it was just a mistake from me. This was not really the
source code I'm using.

I do the following in my DoGet() function of my servlet :


// Create the DOM Tree
Document doc= new DocumentImpl();
root_element = doc.createElement("Products");     // Create Root Element
named <Products>
                                                     
Element product_element= doc.createElement("Produit");  // Create the tag
<Product> child of <Products>
                               
Element ref_element = doc.createElement("Ref"); // Create the tag <Ref>
child of <Product>
ref_element.appendChild( doc.createTextNode("my content"));
product_element.appendChild( ref_element );
                               
root.appendChild( product_element );  


// Process the tree with Xalan and an XSL file


XSLTProcessor processor = null;     
try
{
  processor = XSLTProcessorFactory.getProcessor();

  XMLParserLiaison xmlProcessorLiaison = processor.getXMLProcessorLiaison();
  xmlProcessorLiaison.setUseValidation(false);
           
  processor.process(new XSLTInputSource(root_element),
                  new XSLTInputSource("/toto/transfo.xsl"),
                  new XSLTResultTarget(out));
}
catch (Exception exc)
{
  out.println("Exception occurred during Transformation:"
                                                        + "<br>" +
exc.getMessage() + "<br>");
}
finally
{
  processor.reset();
} // end of try ... catch ... finally

 

And I've got an exception but with no explicit message. So I don't know
where my error comes from.

I know that my DOM tree is build well because when I serialize it with
Xerces, it creates a beautiful XML file just the way I want it.

So where is my error coming from ?

Vincent.

-----Message d'origine-----
De: Tako Schotanus [ mailto:quintesse@palacio-cristal.com
<ma...@palacio-cristal.com> ]
Date: mercredi 11 octobre 2000 17:45
À: xalan-dev@xml.apache.org
Objet: RE: How to parse an XML Tree that was created with the DOM API ?
(in my servlet)



Shouldn't this be:

processor.process(new XSLTInputSource(root_xml_node), new
XSLTInputSource("my_xsl.xsl"), newXSLTResultTarget(out));

?

-Tako

> I've created a tree in memory with the DOM API and I want to
> parse this tree
> with Xalan and to send the result to the output of my servlet.
>
> What should I use instead of  :
>       processor.process(XSLTInputSource(root_xml_node), "my_xsl.xsl",
> XSLTResultTarget(out));
>
> I get an error from the parser but I don't know which error it is (my
> exception sends no message).
> I'm sure that my XSL file is good because I've tested it with
> simpletransform.
>
> Any help would be nice ...
>
> Thanks.

RE: How to parse an XML Tree that was created with the DOM API ? (in my servlet)

[Tako Schotanus <qu...@palacio-cristal.com>]

<snip>

> // Create the DOM Tree
> Document doc= new DocumentImpl();
> root_element = doc.createElement("Products");     // Create Root Element

<snip>

>   processor.process(new XSLTInputSource(root_element),
>                   new XSLTInputSource("/toto/transfo.xsl"),
>                   new XSLTResultTarget(out));

I think you should have entered "doc" instead of "root_element"

Good luck,
 -Tako

> So where is my error coming from ?
>
> Vincent.
>
> -----Message d'origine-----
> De: Tako Schotanus [ mailto:quintesse@palacio-cristal.com
> <ma...@palacio-cristal.com> ]
> Date: mercredi 11 octobre 2000 17:45
> À: xalan-dev@xml.apache.org
> Objet: RE: How to parse an XML Tree that was created with the DOM API ?
> (in my servlet)
>
>
>
> Shouldn't this be:
>
> processor.process(new XSLTInputSource(root_xml_node), new
> XSLTInputSource("my_xsl.xsl"), newXSLTResultTarget(out));
>
> ?
>
> -Tako
>
> > I've created a tree in memory with the DOM API and I want to
> > parse this tree
> > with Xalan and to send the result to the output of my servlet.
> >
> > What should I use instead of  :
> >       processor.process(XSLTInputSource(root_xml_node), "my_xsl.xsl",
> > XSLTResultTarget(out));
> >
> > I get an error from the parser but I don't know which error it is (my
> > exception sends no message).
> > I'm sure that my XSL file is good because I've tested it with
> > simpletransform.
> >
> > Any help would be nice ...
> >
> > Thanks.
>