[jira] [Created] (SPARK-12703) Spark KMeans Documentation Python Api

["Anton (JIRA)" <ji...@apache.org>]

Anton created SPARK-12703:
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             Summary: Spark KMeans Documentation Python Api
                 Key: SPARK-12703
                 URL: https://issues.apache.org/jira/browse/SPARK-12703
             Project: Spark
          Issue Type: Documentation
          Components: MLlib
            Reporter: Anton
            Priority: Minor


In the documentation of Spark's Kmeans - python api:
http://spark.apache.org/docs/latest/mllib-clustering.html#k-means

the cost of the final result is calculated using the 'error()' function where its returning:
{quote}
return sqrt(sum([x**2 for x in (point - center)]))
{quote}

As I understand, it's wrong to use sqrt() and it should be omitted
{quote} sum([x**2 for x in (point - center)]).{quote}

Please refer to :
https://en.wikipedia.org/wiki/K-means_clustering#Description
Where you can see that the power is canceling the square.

What do you think? It's minor but wasted me a few min to understand why the result isn't what I'm expecting.



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