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Posted to issues@spark.apache.org by "Apache Spark (JIRA)" <ji...@apache.org> on 2019/02/19 09:22:00 UTC
[jira] [Assigned] (SPARK-26929) table owner should use user instead
of principal when use kerberos
[ https://issues.apache.org/jira/browse/SPARK-26929?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel ]
Apache Spark reassigned SPARK-26929:
------------------------------------
Assignee: Apache Spark
> table owner should use user instead of principal when use kerberos
> ------------------------------------------------------------------
>
> Key: SPARK-26929
> URL: https://issues.apache.org/jira/browse/SPARK-26929
> Project: Spark
> Issue Type: Bug
> Components: SQL
> Affects Versions: 2.3.0, 2.3.1, 2.3.2, 2.3.3, 2.4.0
> Reporter: hong dongdong
> Assignee: Apache Spark
> Priority: Major
>
> In kerberos cluster, when use spark-sql or beeline to create table, the owner will be whole info of principal. the _issue_ has occur in SPARK-19970 and modify by SPARK-22846, so it occur again. It will causes some problems when using role., and this time should resolved two issues together.
> Use org.apache.hadoop.hive.shims.Utils.getUGI directly to get ugi.getShortUserName
> instead of use conf.getUser which return principal info.
> Code change
> {code:java}
> private val userName: String = try {
> val ugi = HiveUtils.getUGI
> ugi.getShortUserName
> } catch {
> case e: LoginException => throw new IOException(e)
> }
> {code}
> Berfore
> scala> sql("create table t(a int)").show
> scala> sql("desc formatted t").show(false)
> ...
> |Owner:|spark@EXAMPLE.COM| |
> After:
> scala> sql("create table t(a int)").show
> scala> sql("desc formatted t").show(false)
> ...
> |Owner:|spark| |
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