Deserializing a String (string)

[Chris Coyle <ch...@yahoo.com>]

I am new to SOAP and I am trying to implement a simple HelloWorld type app. When I use the TcpTunnelGui I can see my expected response from the SOAP app. However, my client fires off the following fault: 


I thought SOAP understood how to serialize/deserialize type String by default...


[SOAPException: faultCode=SOAP-ENV:Client; msg=No Deserializer found to deserial 
ize a ':return' using encoding style 'http://schemas.xmlsoap.org/soap/encoding/' 
.; targetException=java.lang.IllegalArgumentException: No Deserializer found to 
deserialize a ':return' using encoding style 'http://schemas.xmlsoap.org/soap/en 
coding/'.]

Here is my DeploymentDescriptor.xml:

<isd:service xmlns:isd="http://xml.apache.org/xml-soap/deployment"
             id="urn:HelloTest">
  <isd:provider type="java"
                scope="Application"
                methods="sayHello">
    <isd:java class="samples.hellotest.HelloTest" static="false"/>
  </isd:provider>

  <isd:faultListener>org.apache.soap.server.DOMFaultListener</isd:faultListener>
  <isd:mappings />

</isd:service>


Here is my client code (HelloClient.java)

import java.io.*;
import java.util.*;
import java.net.*;
import org.apache.soap.*;
import org.apache.soap.util.xml.*;
import org.apache.soap.rpc.*;

public class HelloClient {

public static void main(String[] args) {

try {
  System.out.println("Calling rpc servlet...");
  URL url = new URL(args[0]);
  String name = args[1];
  
  Call call = new Call();
  call.setTargetObjectURI("urn:HelloTest");
  call.setMethodName("sayHello");
  call.setEncodingStyleURI(Constants.NS_URI_SOAP_ENC);
  Vector params = new Vector();
  params.addElement(new Parameter("name", String.class, name, null));
  call.setParams(params);
  
  System.out.println("Server says: ");

  Response resp = call.invoke(url, "");

  if(resp.generatedFault()) {
    Fault fault = resp.getFault();
    System.out.println("\nOuch call failed.");
    System.out.println("  Fault Code = " + fault.getFaultCode());
    System.out.println("  Fault String = " + fault.getFaultString());
    }

    else {

    Parameter result = resp.getReturnValue();
    System.out.print(result.getValue());
    System.out.println();
    }
  }

catch (Exception e) {
  e.printStackTrace();
  }

  }

}   

Any help would be greatly appreciated.

Chris Coyle



---------------------------------
Do You Yahoo!?
HotJobs, a Yahoo! service - Search Thousands of New Jobs