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Posted to issues@tez.apache.org by "Tsuyoshi Ozawa (JIRA)" <ji...@apache.org> on 2015/07/08 04:30:04 UTC
[jira] [Updated] (TEZ-2604) PipelinedSorter doesn't use number of
items when creating SortSpan
[ https://issues.apache.org/jira/browse/TEZ-2604?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel ]
Tsuyoshi Ozawa updated TEZ-2604:
--------------------------------
Attachment: TEZ-2604.001.patch
Attaching a first patch.
> PipelinedSorter doesn't use number of items when creating SortSpan
> -------------------------------------------------------------------
>
> Key: TEZ-2604
> URL: https://issues.apache.org/jira/browse/TEZ-2604
> Project: Apache Tez
> Issue Type: Bug
> Affects Versions: 0.8.0
> Reporter: Tsuyoshi Ozawa
> Assignee: Tsuyoshi Ozawa
> Attachments: TEZ-2604.001.patch
>
>
> {quote}
> int items = 1024*1024;
> int perItem = 16;
> if(span.length() != 0) {
> items = span.length();
> perItem = span.kvbuffer.limit()/items;
> items = (int) ((span.capacity)/(METASIZE+perItem));
> if(items > 1024*1024) {
> // our goal is to have 1M splits and sort early
> items = 1024*1024;
> }
> }
> Preconditions.checkArgument(listIterator.hasNext(), "block iterator should not be empty");
> span = new SortSpan((ByteBuffer)listIterator.next().clear(), (1024*1024),
> perItem, ConfigUtils.getIntermediateOutputKeyComparator(this.conf));
> {quote}
> Should we use items instead of (1024*1024)?
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