Re: [xsl] How to get the Browser URL within XSL?

["Mark R. Diggory" <md...@latte.harvard.edu>]

I believe that Cocoon has a Xalan Extension for the HttpServletRequest 
request object somewhere within it. you should be able to access the 
request object by using it.

I wrote a similar extesion for Saxon. I'd like to see information on one 
for Xalan as well.

-Mark

Hubert Holtz wrote:
> Hy all,
> 
> First of all I do not know if this is a pure xsl or cocoon question so i mail it to both lists.
> 
> I know I can access the request parameters of the url in xsl using the xsl-with-parameters type in my sitemap,
> but how can I get the whole URL string in xsl.
> 
> The reason why I need to get this, is that I have the following URL structure:
> 
> http://www.somwhere.de/test/program.html?id=300&lang=ger
> 
> and I want to change the lang value to another value (eng i.e.) by clicking on my flag symbol, the problem is that I don't know
> the sitename in front of .html, because I just want to change the lang parameter the rest should be the same,
> depending on the last requested url (or is it possible to get this value inside xsl?) !
> 
> I'm using Cocoon 2.03 on tomcat4.1.
> 
> Any help is welcome.
> 
> Regards, Steve
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 


---------------------------------------------------------------------
To unsubscribe, e-mail: cocoon-users-unsubscribe@xml.apache.org
For additional commands, e-mail: cocoon-users-help@xml.apache.org