Node as argument in "setParameter" method?

[John Ollier <jo...@capula.co.uk>]

I have a simple stylesheet (shown below) which combines two XML 
Documents effectively copying one into the other.

In my code this works:

transformer.setParameter("infoTextFile", "infoText.xml" )

Where "infoText.xml" is the name of a file containing the second document.

I want to do the same thing, but instead of "infoText.xml", I want to 
pass as the parameter something that I can derive from a Node object 
representing the same Document. My XSL book says the "document()" 
function can take a URL as argument. Can I construct a URL which will 
have the desired effect?

Thanks in advance.

John


<!-- imports info text into master document -->
<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
	<xsl:param name="infoTextFile"/>
	<xsl:template match="/ | * | @* ">
		<xsl:copy>
			<xsl:apply-templates select=" * | @* | text()"/>
		</xsl:copy>
	</xsl:template>
	<!-- copy everything except the 'info'  -->
	<xsl:template match="info">
		<xsl:variable name="id">
			<xsl:value-of select="parent::node/@id"/>
		</xsl:variable>
		<info>
		<xsl:call-template name="insertInfoText">
			<xsl:with-param name="id" select="$id"/>
			<xsl:with-param name="document" select="."/>
			</xsl:call-template>
		</info>
	</xsl:template>
	<!-- info text is imported from the corresponding info text file -->
	<xsl:template name="insertInfoText">
		<xsl:param name="id"/>
		<xsl:param name="document"/>
		<xsl:variable name="infoText" select="document( $infoTextFile, 
$document )/boilerplate/info[@id=$id]"/>
		<xsl:copy-of select="$infoText/infoGroup"/>
	</xsl:template>
	
</xsl:stylesheet>