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Posted to issues@spark.apache.org by "Apache Spark (JIRA)" <ji...@apache.org> on 2016/10/14 19:19:20 UTC

[jira] [Assigned] (SPARK-17863) SELECT distinct does not work if there is a order by clause

     [ https://issues.apache.org/jira/browse/SPARK-17863?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel ]

Apache Spark reassigned SPARK-17863:
------------------------------------

    Assignee:     (was: Apache Spark)

> SELECT distinct does not work if there is a order by clause
> -----------------------------------------------------------
>
>                 Key: SPARK-17863
>                 URL: https://issues.apache.org/jira/browse/SPARK-17863
>             Project: Spark
>          Issue Type: Bug
>          Components: SQL
>            Reporter: Yin Huai
>            Priority: Blocker
>              Labels: correctness
>
> {code}
> select distinct struct.a, struct.b
> from (
>   select named_struct('a', 1, 'b', 2, 'c', 3) as struct
>   union all
>   select named_struct('a', 1, 'b', 2, 'c', 4) as struct) tmp
> order by struct.a, struct.b
> {code}
> This query generates
> {code}
> +---+---+
> |  a|  b|
> +---+---+
> |  1|  2|
> |  1|  2|
> +---+---+
> {code}
> The plan is wrong because the analyze somehow added {{struct#21805}} to the project list, which changes the semantic of the distinct (basically, the query is changed to {{select distinct struct.a, struct.b, struct}} from {{select distinct struct.a, struct.b}}).
> {code}
> == Parsed Logical Plan ==
> 'Sort ['struct.a ASC, 'struct.b ASC], true
> +- 'Distinct
>    +- 'Project ['struct.a, 'struct.b]
>       +- 'SubqueryAlias tmp
>          +- 'Union
>             :- 'Project ['named_struct(a, 1, b, 2, c, 3) AS struct#21805]
>             :  +- OneRowRelation$
>             +- 'Project ['named_struct(a, 1, b, 2, c, 4) AS struct#21806]
>                +- OneRowRelation$
> == Analyzed Logical Plan ==
> a: int, b: int
> Project [a#21819, b#21820]
> +- Sort [struct#21805.a ASC, struct#21805.b ASC], true
>    +- Distinct
>       +- Project [struct#21805.a AS a#21819, struct#21805.b AS b#21820, struct#21805]
>          +- SubqueryAlias tmp
>             +- Union
>                :- Project [named_struct(a, 1, b, 2, c, 3) AS struct#21805]
>                :  +- OneRowRelation$
>                +- Project [named_struct(a, 1, b, 2, c, 4) AS struct#21806]
>                   +- OneRowRelation$
> == Optimized Logical Plan ==
> Project [a#21819, b#21820]
> +- Sort [struct#21805.a ASC, struct#21805.b ASC], true
>    +- Aggregate [a#21819, b#21820, struct#21805], [a#21819, b#21820, struct#21805]
>       +- Union
>          :- Project [1 AS a#21819, 2 AS b#21820, [1,2,3] AS struct#21805]
>          :  +- OneRowRelation$
>          +- Project [1 AS a#21819, 2 AS b#21820, [1,2,4] AS struct#21806]
>             +- OneRowRelation$
> == Physical Plan ==
> *Project [a#21819, b#21820]
> +- *Sort [struct#21805.a ASC, struct#21805.b ASC], true, 0
>    +- Exchange rangepartitioning(struct#21805.a ASC, struct#21805.b ASC, 200)
>       +- *HashAggregate(keys=[a#21819, b#21820, struct#21805], functions=[], output=[a#21819, b#21820, struct#21805])
>          +- Exchange hashpartitioning(a#21819, b#21820, struct#21805, 200)
>             +- *HashAggregate(keys=[a#21819, b#21820, struct#21805], functions=[], output=[a#21819, b#21820, struct#21805])
>                +- Union
>                   :- *Project [1 AS a#21819, 2 AS b#21820, [1,2,3] AS struct#21805]
>                   :  +- Scan OneRowRelation[]
>                   +- *Project [1 AS a#21819, 2 AS b#21820, [1,2,4] AS struct#21806]
>                      +- Scan OneRowRelation[]
> {code}
> If you use the following query, you will get the correct result
> {code}
> select distinct struct.a, struct.b
> from (
>   select named_struct('a', 1, 'b', 2, 'c', 3) as struct
>   union all
>   select named_struct('a', 1, 'b', 2, 'c', 4) as struct) tmp
> order by a, b
> {code}



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