>>> Starting an .exe though out of a servlet

[Patrick Kosiol <ko...@simu.de>]

Hi,

I'm runnung TomCat 4.0.4 and I want to start an external .exe-File.
My Code:

        String[] runString = {relativeDataPath + "data.exe",
          parameter0, parameter1, parameter2, parameter3};
        Process p = Runtime.getRuntime().exec(runString);
        System.out.println(runString);
        if(p.waitFor() == 0){
          ........

The 'data.exe'-File is placed in 
$CATALINA_HOME/webapps/ROOT/relativeDataPath so it should be no problem 
to access this File. The Number of  Parameters etc. is OK.
But I get the following Error-Message:

java.io.IOException: CreateProcess: 
'relativeDataPath'/bfpldata.exe parameter0 parameter1 parameter2 
parameter3 error=3

Does someone know what 'error=3' mean? And how can I access this 
'data.exe' and execute this File with the Parameters? The 
starting-routine seems to be correct.


Thx
Patrick


--
To unsubscribe, e-mail:   <ma...@jakarta.apache.org>
For additional commands, e-mail: <ma...@jakarta.apache.org>