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Posted to dev@openoffice.apache.org by jorge ivan poot diaz <iv...@gmail.com> on 2013/04/25 03:09:40 UTC
OUStringBuffer
I have doubts about using
class OUStringBuffer
I want to implement this code:
x = new OUStringBuffer().append("a").append(4).append("c").toString();
(one example)
This snippet, missing something? (A declaration of variables?)
I need to include libraries or something?
Help me, regards.
Re: OUStringBuffer
Posted by Regina Henschel <rb...@t-online.de>.
Hi Jorge,
I fear, I cannot help you really. Perhaps, you ask again with a clear
statement, what the goal of your tries are. Your emails are very hard to
understand for me.
jorge ivan poot diaz schrieb:
> I've already made a concatenation, in this file:
> http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/cui/source/tabpages/tpcolor.cxx#546
>
>
> Something like this:
>
> OUStringBuffer buf( 128 );
> buf.append( aName );
> buf.append( 4 );
> OUString string = buf.makeStringAndClear();
> OString oString = rtl::OUStringToOString( string ,
> RTL_TEXTENCODING_ASCII_US );
>
> Substituting aName by oString
why?
Reading code where a variable has the same or nearly the same identifier
as a data type is hard. Please avoid it. There might be other side
effects of using string as identifier.
in this fragment of code
> http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/cui/source/tabpages/tpcolor.cxx#549,
> I have the following error,
>
> http://ooo.pastebin.ca/2366521
Yes, the second parameter has a wrong type.
>
> So, I want to convert this code to a STRING:
STRING ?? Please be very exact in using lower or upper characters.
The class String is in main/cosv/inc/cosv/string.hxx
Kind regards
Regina
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Re: OUStringBuffer
Posted by Regina Henschel <rb...@t-online.de>.
Hi,
rahul bhola schrieb:
> take a substring that contains only the last letter and then use
> Integer.parseInt() to convert it into integer
??? We are in C++ not in Java.
Kind regards
Regina
>
>
> On Tue, May 7, 2013 at 9:56 PM, jorge ivan poot diaz <
> ivan.pootdiaz@gmail.com> wrote:
>
>> Hello,
>>
>> I have a doubt, help
>> I made this snippet
>>
>> String abuf = buf.charAt(nLen - 1);
>> double ng = ::rtl::math::stringToDouble( abuf, '.', ',', NULL, NULL
>> );
>> printf ( "Is : %i ", ng);
>>
>> But the return value is 0, in theory I want to return the last digit of the
>> string
>>
>> String : world1695
>> Is : 0
>> String : world3184
>> Is : 0
>>
>> ivan@ivan-Presario-CQ43-Notebook-PC:~$
>>
>> The idea is that
>> String : world3184
>> Is : 4
>>
>> Any ideas why not return a numeric value?
>>
>> Regards
>>
>>
>>
>> 2013/5/6 Regina Henschel <rb...@t-online.de>
>>
>>> Hi Jorge,
>>>
>>>
>>> jorge ivan poot diaz schrieb:
>>>
>>>> thanks,
>>>>
>>>>
>>>> buf.charAt (nLen - 1): this variable has a string as '1' or '2',
>> '3'...'9'
>>>> as it could change to int, any ideas, please help!
>>>>
>>>> I've done this:
>>>> int ty = buf.charAt(nLen - 1);
>>>> built well, but the result is not as expected.
>>>>
>>>
>>> You should post what you get and what you expect. But perhaps the
>>> following hints might already solve your problem.
>>>
>>> Have a look at stringToDouble in main/sal/rtl/source/math.cxx to learn
>>> about converting to number.
>>>
>>> Or
>>>
>>> charAt returns a sal_Unicode. Searching the definition for sal_unicode
>> you
>>> come to main/sal/inc/sal/types.h with leads you to wchar_t. So search in
>>> internet for "wchar_t to int" to get an idea what to do.
>>>
>>> Kind regards
>>> Regina
>>>
>>>
>>>
>>> ------------------------------**------------------------------**---------
>>> To unsubscribe, e-mail: dev-unsubscribe@openoffice.**apache.org<
>> dev-unsubscribe@openoffice.apache.org>
>>> For additional commands, e-mail: dev-help@openoffice.apache.org
>>>
>>>
>>
>
>
>
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Re: OUStringBuffer
Posted by rahul bhola <rb...@gmail.com>.
take a substring that contains only the last letter and then use
Integer.parseInt() to convert it into integer
On Tue, May 7, 2013 at 9:56 PM, jorge ivan poot diaz <
ivan.pootdiaz@gmail.com> wrote:
> Hello,
>
> I have a doubt, help
> I made this snippet
>
> String abuf = buf.charAt(nLen - 1);
> double ng = ::rtl::math::stringToDouble( abuf, '.', ',', NULL, NULL
> );
> printf ( "Is : %i ", ng);
>
> But the return value is 0, in theory I want to return the last digit of the
> string
>
> String : world1695
> Is : 0
> String : world3184
> Is : 0
>
> ivan@ivan-Presario-CQ43-Notebook-PC:~$
>
> The idea is that
> String : world3184
> Is : 4
>
> Any ideas why not return a numeric value?
>
> Regards
>
>
>
> 2013/5/6 Regina Henschel <rb...@t-online.de>
>
> > Hi Jorge,
> >
> >
> > jorge ivan poot diaz schrieb:
> >
> >> thanks,
> >>
> >>
> >> buf.charAt (nLen - 1): this variable has a string as '1' or '2',
> '3'...'9'
> >> as it could change to int, any ideas, please help!
> >>
> >> I've done this:
> >> int ty = buf.charAt(nLen - 1);
> >> built well, but the result is not as expected.
> >>
> >
> > You should post what you get and what you expect. But perhaps the
> > following hints might already solve your problem.
> >
> > Have a look at stringToDouble in main/sal/rtl/source/math.cxx to learn
> > about converting to number.
> >
> > Or
> >
> > charAt returns a sal_Unicode. Searching the definition for sal_unicode
> you
> > come to main/sal/inc/sal/types.h with leads you to wchar_t. So search in
> > internet for "wchar_t to int" to get an idea what to do.
> >
> > Kind regards
> > Regina
> >
> >
> >
> > ------------------------------**------------------------------**---------
> > To unsubscribe, e-mail: dev-unsubscribe@openoffice.**apache.org<
> dev-unsubscribe@openoffice.apache.org>
> > For additional commands, e-mail: dev-help@openoffice.apache.org
> >
> >
>
--
Rahul Bhola
B.E.
computers
Core Member
Department of backstage
Bits Pilani KK Birla Goa Campus
Re: OUStringBuffer
Posted by rahul bhola <rb...@gmail.com>.
sorry was working with openmeetings and that is in java
On Wed, May 8, 2013 at 4:42 AM, Regina Henschel <rb...@t-online.de>wrote:
> Hi Jorge,
>
> jorge ivan poot diaz schrieb:
>
>> Hello,
>>
>>
>> I have a doubt, help
>> I made this snippet
>>
>> String abuf = buf.charAt(nLen - 1);
>> double ng = ::rtl::math::stringToDouble( abuf, '.', ',', NULL,
>> NULL
>> );
>> printf ( "Is : %i ", ng);
>>
>
> I do not meant, that you should call stringToDouble. I meant, that you
> should look into the implementation of that method to see how the
> conversion from character to digit is done there.
>
> Are you sure that the line
>
> String abuf = buf.charAt(nLen - 1);
> really does, what you think that it does?
>
> Kind regards
> Regina
>
>
> ------------------------------**------------------------------**---------
> To unsubscribe, e-mail: dev-unsubscribe@openoffice.**apache.org<de...@openoffice.apache.org>
>
> For additional commands, e-mail: dev-help@openoffice.apache.org
>
>
--
Rahul Bhola
B.E.
computers
Core Member
Department of backstage
Bits Pilani KK Birla Goa Campus
Re: OUStringBuffer
Posted by Regina Henschel <rb...@t-online.de>.
Hi Jorge,
jorge ivan poot diaz schrieb:
> Hello,
>
> I have a doubt, help
> I made this snippet
>
> String abuf = buf.charAt(nLen - 1);
> double ng = ::rtl::math::stringToDouble( abuf, '.', ',', NULL, NULL
> );
> printf ( "Is : %i ", ng);
I do not meant, that you should call stringToDouble. I meant, that you
should look into the implementation of that method to see how the
conversion from character to digit is done there.
Are you sure that the line
String abuf = buf.charAt(nLen - 1);
really does, what you think that it does?
Kind regards
Regina
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Re: OUStringBuffer
Posted by jorge ivan poot diaz <iv...@gmail.com>.
Hello,
I have a doubt, help
I made this snippet
String abuf = buf.charAt(nLen - 1);
double ng = ::rtl::math::stringToDouble( abuf, '.', ',', NULL, NULL
);
printf ( "Is : %i ", ng);
But the return value is 0, in theory I want to return the last digit of the
string
String : world1695
Is : 0
String : world3184
Is : 0
ivan@ivan-Presario-CQ43-Notebook-PC:~$
The idea is that
String : world3184
Is : 4
Any ideas why not return a numeric value?
Regards
2013/5/6 Regina Henschel <rb...@t-online.de>
> Hi Jorge,
>
>
> jorge ivan poot diaz schrieb:
>
>> thanks,
>>
>>
>> buf.charAt (nLen - 1): this variable has a string as '1' or '2', '3'...'9'
>> as it could change to int, any ideas, please help!
>>
>> I've done this:
>> int ty = buf.charAt(nLen - 1);
>> built well, but the result is not as expected.
>>
>
> You should post what you get and what you expect. But perhaps the
> following hints might already solve your problem.
>
> Have a look at stringToDouble in main/sal/rtl/source/math.cxx to learn
> about converting to number.
>
> Or
>
> charAt returns a sal_Unicode. Searching the definition for sal_unicode you
> come to main/sal/inc/sal/types.h with leads you to wchar_t. So search in
> internet for "wchar_t to int" to get an idea what to do.
>
> Kind regards
> Regina
>
>
>
> ------------------------------**------------------------------**---------
> To unsubscribe, e-mail: dev-unsubscribe@openoffice.**apache.org<de...@openoffice.apache.org>
> For additional commands, e-mail: dev-help@openoffice.apache.org
>
>
Re: OUStringBuffer
Posted by Regina Henschel <rb...@t-online.de>.
Hi Jorge,
jorge ivan poot diaz schrieb:
> thanks,
>
> buf.charAt (nLen - 1): this variable has a string as '1' or '2', '3'...'9'
> as it could change to int, any ideas, please help!
>
> I've done this:
> int ty = buf.charAt(nLen - 1);
> built well, but the result is not as expected.
You should post what you get and what you expect. But perhaps the
following hints might already solve your problem.
Have a look at stringToDouble in main/sal/rtl/source/math.cxx to learn
about converting to number.
Or
charAt returns a sal_Unicode. Searching the definition for sal_unicode
you come to main/sal/inc/sal/types.h with leads you to wchar_t. So
search in internet for "wchar_t to int" to get an idea what to do.
Kind regards
Regina
---------------------------------------------------------------------
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Re: OUStringBuffer
Posted by jorge ivan poot diaz <iv...@gmail.com>.
thanks,
buf.charAt (nLen - 1): this variable has a string as '1' or '2', '3'...'9'
as it could change to int, any ideas, please help!
I've done this:
int ty = buf.charAt(nLen - 1);
built well, but the result is not as expected.
regards!
2013/4/29 Herbert Dürr <hd...@apache.org>
> Hi Jorge,
>
> like Regina I have a hard time to understand the question. My best guess
> is that you have an OUStringBuffer object and need an UniString (aka tool's
> String [1]). If that is so you can get it using the UniString constructor
> that takes an OUString argument:
>
> UniString( buf.makeStringAndClear() )
>
> [1] http://opengrok.adfinis-**sygroup.org/source/xref/aoo-**
> trunk/main/tools/inc/tools/**solar.h#269<http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/tools/inc/tools/solar.h#269>
>
> Hope that helps,
> Herbert
>
>
> On 2013/04/25 8:00 PM, jorge ivan poot diaz wrote:
>
>> I've already made a concatenation, in this file:
>> http://opengrok.adfinis-**sygroup.org/source/xref/aoo-**
>> trunk/main/cui/source/**tabpages/tpcolor.cxx#546<http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/cui/source/tabpages/tpcolor.cxx#546>
>>
>>
>> Something like this:
>>
>> OUStringBuffer buf( 128 );
>> buf.append( aName );
>> buf.append( 4 );
>> OUString string = buf.makeStringAndClear();
>> OString oString = rtl::OUStringToOString( string ,
>> RTL_TEXTENCODING_ASCII_US );
>>
>> Substituting aName by oString in this fragment of code
>> http://opengrok.adfinis-**sygroup.org/source/xref/aoo-**
>> trunk/main/cui/source/**tabpages/tpcolor.cxx#549<http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/cui/source/tabpages/tpcolor.cxx#549>
>> ,
>> I have the following error,
>>
>> http://ooo.pastebin.ca/2366521
>>
>> So, I want to convert this code to a STRING:
>> OString oString = rtl::OUStringToOString( string ,
>> RTL_TEXTENCODING_ASCII_US );
>>
>> Because the definition of aName is STRING, as you can see here:
>> http://ooo.pastebin.ca/2366523
>>
>> The file is located at:
>> http://opengrok.adfinis-**sygroup.org/source/xref/aoo-**
>> trunk/main/svx/inc/svx/xtable.**hxx#57<http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/svx/inc/svx/xtable.hxx#57>
>>
>
>
> ------------------------------**------------------------------**---------
> To unsubscribe, e-mail: dev-unsubscribe@openoffice.**apache.org<de...@openoffice.apache.org>
> For additional commands, e-mail: dev-help@openoffice.apache.org
>
>
Re: OUStringBuffer
Posted by Herbert Dürr <hd...@apache.org>.
Hi Jorge,
like Regina I have a hard time to understand the question. My best guess
is that you have an OUStringBuffer object and need an UniString (aka
tool's String [1]). If that is so you can get it using the UniString
constructor that takes an OUString argument:
UniString( buf.makeStringAndClear() )
[1]
http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/tools/inc/tools/solar.h#269
Hope that helps,
Herbert
On 2013/04/25 8:00 PM, jorge ivan poot diaz wrote:
> I've already made a concatenation, in this file:
> http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/cui/source/tabpages/tpcolor.cxx#546
>
>
> Something like this:
>
> OUStringBuffer buf( 128 );
> buf.append( aName );
> buf.append( 4 );
> OUString string = buf.makeStringAndClear();
> OString oString = rtl::OUStringToOString( string ,
> RTL_TEXTENCODING_ASCII_US );
>
> Substituting aName by oString in this fragment of code
> http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/cui/source/tabpages/tpcolor.cxx#549,
> I have the following error,
>
> http://ooo.pastebin.ca/2366521
>
> So, I want to convert this code to a STRING:
> OString oString = rtl::OUStringToOString( string ,
> RTL_TEXTENCODING_ASCII_US );
>
> Because the definition of aName is STRING, as you can see here:
> http://ooo.pastebin.ca/2366523
>
> The file is located at:
> http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/svx/inc/svx/xtable.hxx#57
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Re: OUStringBuffer
Posted by jorge ivan poot diaz <iv...@gmail.com>.
I've already made a concatenation, in this file:
http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/cui/source/tabpages/tpcolor.cxx#546
Something like this:
OUStringBuffer buf( 128 );
buf.append( aName );
buf.append( 4 );
OUString string = buf.makeStringAndClear();
OString oString = rtl::OUStringToOString( string ,
RTL_TEXTENCODING_ASCII_US );
Substituting aName by oString in this fragment of code
http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/cui/source/tabpages/tpcolor.cxx#549,
I have the following error,
http://ooo.pastebin.ca/2366521
So, I want to convert this code to a STRING:
OString oString = rtl::OUStringToOString( string ,
RTL_TEXTENCODING_ASCII_US );
Because the definition of aName is STRING, as you can see here:
http://ooo.pastebin.ca/2366523
The file is located at:
http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/svx/inc/svx/xtable.hxx#57
Regards.
2013/4/25 Regina Henschel <rb...@t-online.de>
> Hi,
>
> jorge ivan poot diaz schrieb:
>
> I have doubts about using
>> class OUStringBuffer
>>
>
> You should be more specific about your problem. Do you need help in
> understanding the descriptions in ustrbuf.hxx? Or do you get an compiler
> error, which do you not understand? Or do you need help about the
> difference to other string types? Or ...?
>
>
>
>> I want to implement this code:
>>
>> x = new OUStringBuffer().append("a").**append(4).append("c").**
>> toString();
>> (one example)
>>
>> This snippet, missing something? (A declaration of variables?)
>>
>
> Please post a little bit more. Where do you want to use that code? What is
> x ? Do you want to do something specific, or is it an exercise, some kind
> of "hello world"?
>
> Kind regards
> Regina
>
> ------------------------------**------------------------------**---------
> To unsubscribe, e-mail: dev-unsubscribe@openoffice.**apache.org<de...@openoffice.apache.org>
> For additional commands, e-mail: dev-help@openoffice.apache.org
>
>
Re: OUStringBuffer
Posted by Regina Henschel <rb...@t-online.de>.
Hi,
jorge ivan poot diaz schrieb:
> I have doubts about using
> class OUStringBuffer
You should be more specific about your problem. Do you need help in
understanding the descriptions in ustrbuf.hxx? Or do you get an compiler
error, which do you not understand? Or do you need help about the
difference to other string types? Or ...?
>
> I want to implement this code:
>
> x = new OUStringBuffer().append("a").append(4).append("c").toString();
> (one example)
>
> This snippet, missing something? (A declaration of variables?)
Please post a little bit more. Where do you want to use that code? What
is x ? Do you want to do something specific, or is it an exercise, some
kind of "hello world"?
Kind regards
Regina
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