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Posted to j-users@xalan.apache.org by Pramodh Peddi <pe...@contextmedia.com> on 2004/01/14 17:35:36 UTC

replacing ALL chars in a string while transforming

Hi,
Do we have any way to replace ALL different characters in String with other
characters in ONE SINGLE shot?
Example: I have a String "&#174; &#8482;" and the resulting String should be
"&amp;#174; &amp;#8482;". Which means '&#174;' should be replaced by
'&amp;#174;', '&#8482;' should be replaced by '&amp;#8482;'.

Below is what I am doing right now. It is working, but I am happening to
call the template once for each string replacement. Thus, it becomes slow. I
want to know if there is any way we can replace ALL the strings in a SINGLE
call:
          <description>
          <xsl:text
disable-output-escaping="yes"><![CDATA[<![CDATA[]]></xsl:text>
            <xsl:variable name="repregdesc">
            <xsl:call-template name="do-replace">
              <xsl:with-param name="text">
                <xsl:copy-of
select="normalize-space(translate(DESCRIPTION,'ý',' '))"/>
              </xsl:with-param>
              <xsl:with-param name="replace">&#174;</xsl:with-param>
              <xsl:with-param name="by">
                <xsl:text
disable-output-escaping="yes">&amp;#174;</xsl:text>
              </xsl:with-param>
            </xsl:call-template>
            </xsl:variable>
            <xsl:call-template name="do-replace">
              <xsl:with-param name="text">
                <xsl:copy-of select="$repregdesc"/>
              </xsl:with-param>
              <xsl:with-param name="replace">
                &#8482;
              </xsl:with-param>
              <xsl:with-param name="by">
                <xsl:text
disable-output-escaping="yes">&amp;#8482;</xsl:text>
              </xsl:with-param>
            </xsl:call-template>
            <xsl:text
disable-output-escaping="yes"><![CDATA[]]]]>></xsl:text>
          </description>

and the do-replace template is as follows:

  <xsl:template name="do-replace">
    <xsl:param name="text"/>
    <xsl:param name="replace"/>
    <xsl:param name="by"/>
    <xsl:choose>
      <xsl:when test="contains($text,$replace)">
        <xsl:copy-of select="substring-before($text,$replace)"/><xsl:copy-of
select="$by"/><xsl:call-template name="do-replace">
        <xsl:with-param name="text"><xsl:copy-of
select="substring-after($text,$replace)"/></xsl:with-param>
        <xsl:with-param name="replace" select="$replace"/>
        <xsl:with-param name="by"><xsl:copy-of
select="$by"/></xsl:with-param>
      </xsl:call-template>
    </xsl:when>
    <xsl:otherwise>
      <xsl:copy-of select="$text"/>
    </xsl:otherwise>
  </xsl:choose>
</xsl:template>

Any help would be greatly appreciated.

Thanks,

Pramodh.

Re: replacing ALL chars in a string while transforming

Posted by Santiago Pericas-Geertsen <Sa...@Sun.COM>.
Pramodh,

 Have you considered using an external Java function? Operations such as
these are typically easier and perform better if written in Java. See
[1] for more information.

-- Santiago

[1] http://xml.apache.org/xalan-j/extensions.html#ext-functions

On Wed, 2004-01-14 at 11:35, Pramodh Peddi wrote:
> Hi,
> Do we have any way to replace ALL different characters in String with other
> characters in ONE SINGLE shot?
> Example: I have a String "&#174; &#8482;" and the resulting String should be
> "&amp;#174; &amp;#8482;". Which means '&#174;' should be replaced by
> '&amp;#174;', '&#8482;' should be replaced by '&amp;#8482;'.
> 
> Below is what I am doing right now. It is working, but I am happening to
> call the template once for each string replacement. Thus, it becomes slow. I
> want to know if there is any way we can replace ALL the strings in a SINGLE
> call:
>           <description>
>           <xsl:text
> disable-output-escaping="yes"><![CDATA[<![CDATA[]]></xsl:text>
>             <xsl:variable name="repregdesc">
>             <xsl:call-template name="do-replace">
>               <xsl:with-param name="text">
>                 <xsl:copy-of
> select="normalize-space(translate(DESCRIPTION,'ý',' '))"/>
>               </xsl:with-param>
>               <xsl:with-param name="replace">&#174;</xsl:with-param>
>               <xsl:with-param name="by">
>                 <xsl:text
> disable-output-escaping="yes">&amp;#174;</xsl:text>
>               </xsl:with-param>
>             </xsl:call-template>
>             </xsl:variable>
>             <xsl:call-template name="do-replace">
>               <xsl:with-param name="text">
>                 <xsl:copy-of select="$repregdesc"/>
>               </xsl:with-param>
>               <xsl:with-param name="replace">
>                 &#8482;
>               </xsl:with-param>
>               <xsl:with-param name="by">
>                 <xsl:text
> disable-output-escaping="yes">&amp;#8482;</xsl:text>
>               </xsl:with-param>
>             </xsl:call-template>
>             <xsl:text
> disable-output-escaping="yes"><![CDATA[]]]]>></xsl:text>
>           </description>
> 
> and the do-replace template is as follows:
> 
>   <xsl:template name="do-replace">
>     <xsl:param name="text"/>
>     <xsl:param name="replace"/>
>     <xsl:param name="by"/>
>     <xsl:choose>
>       <xsl:when test="contains($text,$replace)">
>         <xsl:copy-of select="substring-before($text,$replace)"/><xsl:copy-of
> select="$by"/><xsl:call-template name="do-replace">
>         <xsl:with-param name="text"><xsl:copy-of
> select="substring-after($text,$replace)"/></xsl:with-param>
>         <xsl:with-param name="replace" select="$replace"/>
>         <xsl:with-param name="by"><xsl:copy-of
> select="$by"/></xsl:with-param>
>       </xsl:call-template>
>     </xsl:when>
>     <xsl:otherwise>
>       <xsl:copy-of select="$text"/>
>     </xsl:otherwise>
>   </xsl:choose>
> </xsl:template>
> 
> Any help would be greatly appreciated.
> 
> Thanks,
> 
> Pramodh.
>