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Posted to issues@spark.apache.org by "Bo Yang (JIRA)" <ji...@apache.org> on 2018/10/09 22:37:00 UTC

[jira] [Updated] (SPARK-25694) URL.setURLStreamHandlerFactory causing incompatible HttpURLConnection issue

     [ https://issues.apache.org/jira/browse/SPARK-25694?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel ]

Bo Yang updated SPARK-25694:
----------------------------
    Summary: URL.setURLStreamHandlerFactory causing incompatible HttpURLConnection issue  (was: URL.setURLStreamHandlerFactory causing incompatible HttpURLConnection)

> URL.setURLStreamHandlerFactory causing incompatible HttpURLConnection issue
> ---------------------------------------------------------------------------
>
>                 Key: SPARK-25694
>                 URL: https://issues.apache.org/jira/browse/SPARK-25694
>             Project: Spark
>          Issue Type: Bug
>          Components: Spark Core, SQL
>    Affects Versions: 2.3.0, 2.3.1, 2.3.2
>            Reporter: Bo Yang
>            Priority: Major
>
> URL.setURLStreamHandlerFactory() in SharedState causes URL.openConnection() returns FsUrlConnection object, which is not compatible with HttpURLConnection. This will cause exception when using some third party http library (e.g. scalaj.http).
> The following code in Spark 2.3.0 introduced the issue: sql/core/src/main/scala/org/apache/spark/sql/internal/SharedState.scala:
> {code}
> object SharedState extends Logging  {   ...   
>   URL.setURLStreamHandlerFactory(new FsUrlStreamHandlerFactory())   ...
> }
> {code}
> Example exception when using scalaj.http in Spark:
>  StackTrace: scala.MatchError: org.apache.hadoop.fs.FsUrlConnection:[http://wwww.example.com|http://wwww.example.com/] (of class org.apache.hadoop.fs.FsUrlConnection)
>  at scalaj.http.HttpRequest.scalaj$http$HttpRequest$$doConnection(Http.scala:343)
>  at scalaj.http.HttpRequest.exec(Http.scala:335)
>  at scalaj.http.HttpRequest.asString(Http.scala:455)
>   
> One option to fix the issue is to return null in URLStreamHandlerFactory.createURLStreamHandler when the protocol is http/https, so it will use the default behavior and be compatible with scalaj.http. Following is the code example:
> {code}
> class SparkUrlStreamHandlerFactory extends URLStreamHandlerFactory with Logging {
>   private val fsUrlStreamHandlerFactory = new FsUrlStreamHandlerFactory()
>   override def createURLStreamHandler(protocol: String): URLStreamHandler = {
>     val handler = fsUrlStreamHandlerFactory.createURLStreamHandler(protocol)
>     if (handler == null) {
>       return null
>     }
>     if (protocol != null &&
>       (protocol.equalsIgnoreCase("http")
>       || protocol.equalsIgnoreCase("https"))) {
>       // return null to use system default URLStreamHandler
>       null
>     } else {
>       handler
>     }
>   }
> }
> {code}
>  
>  



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