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Posted to notifications@groovy.apache.org by "Jason Garrett (Jira)" <ji...@apache.org> on 2023/04/07 21:03:00 UTC

[jira] [Created] (GROOVY-11005) CompileStatic: Cannot set default-visible property in superclass that has a getter without a setter

Jason Garrett created GROOVY-11005:
--------------------------------------

             Summary: CompileStatic: Cannot set default-visible property in superclass that has a getter without a setter
                 Key: GROOVY-11005
                 URL: https://issues.apache.org/jira/browse/GROOVY-11005
             Project: Groovy
          Issue Type: Bug
          Components: Compiler
    Affects Versions: 3.0.17
            Reporter: Jason Garrett


If a class's ancestors declare a default-visibility property and a getter for that property:

 
{code:java}
class HasProperty {
    Object foo

    Object getFoo() {
       return foo
    }
} {code}
Then the class, if it is CompileStatic, cannot set that property.

 

This fails to compile:

 
{code:java}
import groovy.transform.CompileStatic

@CompileStatic
class SetsProperty extends HasProperty {
    void doStuff() {
       foo = "example"
    }
} {code}
Compiler output:

 
{noformat}
SetsProperty.groovy: 8: [Static type checking] - Cannot set read-only property: foo
 @ line 8, column 3.
           foo = "example"{noformat}
 

 

It also fails to compile with "this.@":

 
{code:java}
import groovy.transform.CompileStatic

@CompileStatic
class SetsProperty extends HasProperty {
    void doStuff() {
       this.@foo = "example"
    }
} {code}
Results in:

 

 
{noformat}
SetsProperty.groovy: 8: [Static type checking] - The field HasProperty.foo is not accessible
 @ line 8, column 9.
           this.@foo = "example"{noformat}
 

 

{{These do compile if the class is not CompileStatic, or if the property is explicitly declared "public".}}

 

 



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