[jira] Commented: (DERBY-4752) CheapDateFormatter returns incorrect and invalid date strings

["Knut Anders Hatlen (JIRA)" <ji...@apache.org>]

    [ https://issues.apache.org/jira/browse/DERBY-4752?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=12890707#action_12890707 ] 

Knut Anders Hatlen commented on DERBY-4752:
-------------------------------------------

Examples:

Issue 1:

CheapDateFormatter.formatDate(1325376000000L) returns "2011-13-01 00:00:00.000 GMT", expected: "2012-01-01 00:00:00.000 GMT"

The returned date is wrong and invalid because there is no month 13.

Issue 2:

CheapDateFormatter.formatDate(4114195200000L) returns "2100-05-16 00:00:00.000 GMT", expected: "2100-05-17 00:00:00.000 GMT"

The returned date is one day off.

Issue 3:

CheapDateFormatter.formatDate(4107542400000L) returns "2100-02-29 00:00:00.000 GMT", expected "2100-03-01 00:00:00.000 GMT"

The returned date is invalid because there is no February 29 in the year 2100.

> CheapDateFormatter returns incorrect and invalid date strings
> -------------------------------------------------------------
>
>                 Key: DERBY-4752
>                 URL: https://issues.apache.org/jira/browse/DERBY-4752
>             Project: Derby
>          Issue Type: Bug
>          Components: Services
>    Affects Versions: 10.7.0.0
>            Reporter: Knut Anders Hatlen
>            Priority: Minor
>
> CheapDateFormatter has multiple problems. These are the ones I'm aware of:
> 1) On the boundary between non-leap years and leap years it will return first day of thirteenth month in previous year (for instance, 2011-13-01 instead of 2012-01-01)
> 2) It treats all years divisible by four as leap years. Those divisible by 100 and not by 400 are not leap years. It attempts to adjust for that (see the snippet below) but it always ends up setting leapYear=true if (year%4)==0.
> 		// It's a leap year if divisible by 4, unless divisible by 100,
> 		// unless divisible by 400.
> 		if ((year % 4L) == 0) {
> 			if ((year % 100L) == 0) {
> 				if ((year % 400L) == 0) {
> 					leapYear = true;
> 				}
> 			}
> 			leapYear = true;
> 		}
> 3) More leap year trouble. To find out which year it is, it calculates the number of four year periods that have elapsed since 1970-01-01. A four year period is considered 365*3+366 days. Although most four year periods are of that length, some are shorter, so we'll get one day off starting from year 2100, two days off from year 2200, and so on.

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