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Posted to users@tomcat.apache.org by Marot Laurent <La...@alliacom.com> on 2004/09/03 10:27:57 UTC

[OT] RE: javascript and servlets.

very surprising ...

to ensure you really send parameters, just try to get one of them with usual getParameter("param").

but i think it is slighly off-topic


-----Message d'origine-----
De : David.Pawson@rnib.org.uk [mailto:David.Pawson@rnib.org.uk]
Envoyé : vendredi 3 septembre 2004 09:38
À : tomcat-user@jakarta.apache.org
Objet : RE: javascript and servlets.


 

    -----Original Message-----
    From: Marot Laurent [mailto:Laurent.Marot@alliacom.com] 
    Sent: 03 September 2004 08:33
    To: Tomcat Users List
    Subject: RE: javascript and servlets.
    
    use getParameterNames
    public java.util.Enumeration getParameterNames() 
    
    to get the name of all input fields and then getParameter 
    to get the value(s) oh each parameter
Thanks Laurent:

	java.util.Enumeration enum = request.getParameterNames();
	while (enum.hasMoreElements()){
	    String s = (String)enum.nextElement();
	    out.println("<p>"+s+"</p>");
	}

Produces no output?
    Implies that hasMoreElements() is false?


Ralph suggested

String[] f = request.getParameterValues("file0");

f[0]
..
f[f.length - 1]

but I can't see how that will access the entry with name file1, file2 etc?

Perhaps all the entries should be named the same (which seems illogical).

regards DaveP

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