xsl:copy

[Alejandro Raiczyk <al...@technisys.com.ar>]

Hey people,

I have this XML file:

<?xml version="1.0"?>
<?cocoon-process type="xslt"?>

<?xml-stylesheet href="xsl/formulario.xsl" type="text/xsl"?>


<formulario accion="perfilInversorUI.xml">
        <titulo colspan="2">Ingrese sus datos</titulo>
        <fila>
                <campo tipo="texto">Nombre</campo>
                <campo tipo="html"><input type="text" name="nombre"
size="20"/></campo>
        </fila>
</formulario>


and this template for matching the tag <campo>:

        <xsl:template match="campo">
                <xsl:choose>
                    <xsl:when test="@tipo='texto'">
                        <td height="25" bgcolor="#25AEAB"
colspan="{@colspan}">
                                <font face="Verdana" size="1">
                                <xsl:value-of select="."/>
                                </font>
                            </td>
                </xsl:when>

                    <xsl:when test="@tipo='html'">
                        <td height="25" bgcolor="#25AEAB"
colspan="{@colspan}">
                                        <xsl:copy>
<!-- HERE                                         <xsl:apply-templates
select="."/>   -->
                                        </xsl:copy>
                            </td>
                </xsl:when>
                </xsl:choose>
       
        </xsl:template> 

when tipo='html' I must copy the child nodes of 'campo' (I need the exact
copy, including attributes) and I don't know how to do it (see where says
HERE).

Help!!

Thanks