Time component lost from Date

[Vineeth Varghese <vi...@tavant.com>]

Hi,

We have type definitions in our schema like :-

-------------Basic Type Definition----------------------------
 <xs:simpleType name="Date">
  <xs:restriction base="xs:date">
   <xs:pattern value="\d\d\d\d-\d\d-\d\d"/>
  </xs:restriction>
 </xs:simpleType>

 <xs:simpleType name="DateTime">
  <xs:restriction base="xs:dateTime">
   <xs:pattern
value="\d\d\d\d-\d\d-\d\dT\d\d:\d\d:\d\d(Z|(\+|-)\d\d:\d\d)"/>
  </xs:restriction>
 </xs:simpleType>

 <xs:simpleType name="DateTimeAny">
  <xs:union memberTypes="Date DateTime"/>
 </xs:simpleType>


------------BOD element definition-----------------------------
 <xs:element name="CallBackDate" type="DateTimeAny" minOccurs="0"/>
---------------------------------------------------------------

The getter for this element returns a Calendar Object. Things are fine as
long as a Date value is set but if we want the time component and expect a
DateTime, the time component seem to be lost from the Calendar's toString()
value. 

By the current definition of DateTimeAny, Calendar object will use the
format of the first element in the union member type list of DateTimeAny
which is Date in this case so I am getting a Date string. If I change the
type definition to :-

 <xs:simpleType name="DateTimeAny">
  <xs:union memberTypes="DateTime Date"/>
 </xs:simpleType>

Calendar object picks the format of DateTime and returns timestamp string
with the time.

So my question is, does XMLBean have any feature by which instead of a
Calendar Object from the bean getter I get an object which I can type cast
appropriately to org.apache.xmlbeans.XMLDate or
org.apache.xmlbeans.XMLDateTime. The actual type can depend on the
availabilty of the time component. Is this possible in XMLBean right now?

Thanks,

Vineeth.