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Posted to notifications@apisix.apache.org by GitBox <gi...@apache.org> on 2020/11/20 02:58:12 UTC

[GitHub] [apisix] spacewander opened a new issue #2798: [DISCUSS] provide a control interface to expose APISIX internal state

spacewander opened a new issue #2798:
URL: https://github.com/apache/apisix/issues/2798


   We can let APISIX listen a specific port and provide some APIs just like the current admin server.
   
   Those APIs include:
   * /healthcheck: show the status of healthcheck. See #2797.


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[GitHub] [apisix] spacewander commented on issue #2798: [DISCUSS] provide a control interface to expose APISIX internal state

Posted by GitBox <gi...@apache.org>.
spacewander commented on issue #2798:
URL: https://github.com/apache/apisix/issues/2798#issuecomment-763278334


   So we can get the check & upstream's configuration, the healthy nodes (unhealthy nodes can be found via `nodes` - `healthy nodes`).


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[GitHub] [apisix] tokers commented on issue #2798: [DISCUSS] provide a control interface to expose APISIX internal state

Posted by GitBox <gi...@apache.org>.
tokers commented on issue #2798:
URL: https://github.com/apache/apisix/issues/2798#issuecomment-730930424






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[GitHub] [apisix] spacewander commented on issue #2798: [DISCUSS] provide a control interface to expose APISIX internal state

Posted by GitBox <gi...@apache.org>.
spacewander commented on issue #2798:
URL: https://github.com/apache/apisix/issues/2798#issuecomment-730814817


   @gzhsnail What kind of health check information you need?


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[GitHub] [apisix] gzhsnail commented on issue #2798: [DISCUSS] provide a control interface to expose APISIX internal state

Posted by GitBox <gi...@apache.org>.
gzhsnail commented on issue #2798:
URL: https://github.com/apache/apisix/issues/2798#issuecomment-730970724


   > 
   > 
   > @gzhsnail What kind of health check information you need?
   
    For the time being, only upstream is required to be active 。
   暂时只需要 upstream 主动检查是否健康和被动检查是否健康。


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[GitHub] [apisix] tokers commented on issue #2798: [DISCUSS] provide a control interface to expose APISIX internal state

Posted by GitBox <gi...@apache.org>.
tokers commented on issue #2798:
URL: https://github.com/apache/apisix/issues/2798#issuecomment-730813745


   Yep, i'm devoting to the /status api, i think the health check result is also required.


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[GitHub] [apisix] membphis closed issue #2798: [DISCUSS] provide a control interface to expose APISIX internal state

Posted by GitBox <gi...@apache.org>.
membphis closed issue #2798:
URL: https://github.com/apache/apisix/issues/2798


   


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[GitHub] [apisix] spacewander commented on issue #2798: [DISCUSS] provide a control interface to expose APISIX internal state

Posted by GitBox <gi...@apache.org>.
spacewander commented on issue #2798:
URL: https://github.com/apache/apisix/issues/2798#issuecomment-763265836


   @gzhsnail 
   There is not concept of "主动检查是否健康" and "被动检查是否健康".
   There is only two state: "healthy" and "unhealthy". Both "active check" and "passive check" can change a node from "healthy" to "unhealthy", or reverse.


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