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Posted to java-user@axis.apache.org by Fabrício <fa...@de9.ime.eb.br> on 2005/08/29 19:54:51 UTC
Implementing (De)Serializer
Hello all,
I created a web service that returns a bean instance. Firstly, when I was
running my clients I was obtaining SAX Exceptions saying unexpected end of
file.
So I tried to do my own Serializers. I created my Bean.java, a
Bean(De)Serializer.java and Bean(De)SerializerFactory.java at the same
package.
My web service is still the same. Than, I deployed my web service using the
following WSDD:
<deployment xmlns="http://xml.apache.org/axis/wsdd/"
xmlns:java="http://xml.apache.org/axis/wsdd/providers/java">
<service name="MyService" provider="java:RPC">
<parameter name="className" value="MyService"/>
<parameter name="allowedMethods" value="*"/>
<typeMapping qname="ns:Bean"
xmlns:ns="urn:MyService"
languageSpecificType="java:my_package.Bean"
serializer=" my_package.BeanSerializerFactory "
deserializer=" my_package.BeanDeserializerFactory "
encodingStyle="http://schemas.xmlsoap.org/soap/encoding/"/>
</service>
</deployment>
And now Im obtaining the error:
; nested exception is:
org.xml.sax.SAXException: Deserializing parameter 'getBeanReturn': could
not find deserializer for type {urn:MyService}Bean
at
org.apache.axis.message.RPCHandler.onStartChild(RPCHandler.java:270)
at
org.apache.axis.encoding.DeserializationContext.startElement(Deserialization
Context.java:1035)
at
org.apache.axis.message.SAX2EventRecorder.replay(SAX2EventRecorder.java:165)
at
org.apache.axis.message.MessageElement.publishToHandler(MessageElement.java:
1140)
at
org.apache.axis.message.RPCElement.deserialize(RPCElement.java:347)
at
org.apache.axis.message.RPCElement.getParams(RPCElement.java:386)
at
org.apache.axis.client.Call.invoke(Call.java:2437)
at
org.apache.axis.client.Call.invoke(Call.java:2336)
at
org.apache.axis.client.Call.invoke(Call.java:1793)
at testeWSCliente.main(testeWSCliente.java:17)
Finished executing
Does anyone know why this is happening?
Thanks a lot,
Fabrício.