[file upload with XSP-actions] first try

[steph <pr...@free.fr>]

Hello,


As my application need to do an upload, I am searching how to do this
with cocoon (2.1.4 with a GNU/Linux box).

I saw on the wiki that the 2 recommended ways to do that are Actions and
flows. But , as I don't use flows (for my co-workers javascript is a
"patching" langage), I'd like to do this with actions.


As a beginner, I had a look at how actions run and this is what I
understood (correct me if i'm wrong).
- actions must be wrote in cocoon sources
- each time I'd like to create a new action I have a to re compile
cocoon.


As I've got an "old" 300 Mhz computer, I won't be annoying waiting 30
minutes (whithout cocoon/postgresql configuration) to see if my action
works correctly (and then re run the compilation 'cause it does never
work at first time :) ).

This is why I choose to try XSP-actions.

Even if the wiki page was pretty I still don't know how to start writing
it.

this is a first try (that does not work!):


			/************/

<?xml version="1.0" encoding="ISO-8859-1"?>

<xsp:page language="java"
          xmlns:xsp="http://apache.org/xsp"
	  xmlns:action="http://apache.org/cocoon/action/1.0"
	  xmlns:xsp-request="http://apache.org/xsp/request/2.0">


<xsp:structure>
<xsp:include>java.util.*</xsp:include>
<xsp:include>java.io.File</xsp:include>
<xsp:include>java.util.Collections</xsp:include>
<xsp:include>java.util.Map</xsp:include>
<xsp:include>org.apache.cocoon.environment.*</xsp:include>
<xsp:include>org.apache.cocoon.components.request.*</xsp:include>
</xsp:structure>

 <xsp:logic>
  try
  {
    FilePart filePart = (FilePart) request.get("uploaded_file");

    File file = ((FilePartFile)filePart).getFile();
    System.out.println("Uploaded file = "+file.getCanonicalPath()+"\n");
  }
  catch(Exception e)
  {
    e.printStackTrace() ;
    <action:set-failure/>
  }
  </xsp:logic>

</xsp:page>

   


              /***********************/
...
<map:components>
  <map:actions>
    <map:action
      logger="sitemap.action.xsp-action"
      name="xsp-action"
      src="org.apache.cocoon.acting.ServerPagesAction"/>
  </map:actions>
...


   <map:match pattern="affichage">
     <map:act type ="xsp-action" src="FileUpload.xsp">
     <map:transform src="affichage.xsl">
       <map:parameter name="use-request-parameters" value="true"/>
     </map:transform>
    <map:serialize type="html"/>
    </map:act>
   </map:match>


     /*****************/

The first goal of this little XSP-action is to print the name of the
uploaded page on the shell where I run cocoon (as a servlet).
It seems that I can't use the FilePart type.

(I can post my error message if needed but it's rather long and I think
I made comprehension errors before syntax ones)


The final Application will be able to upload a file, put it in the
correct directory and save its path in database. (I guess that actions
could do this)


Thank you in advance,
Stephane


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Re: [file upload with XSP-actions] first try

[Askild Aaberg Olsen <as...@xangeli.com>]

> Hello,
> 
> The first goal of this little XSP-action is to print the name
> of the uploaded page on the shell where I run cocoon (as a 
> servlet). It seems that I can't use the FilePart type.

What if you use:

PartOnDisk part = (PartOnDisk) request.get("upload_file")   ?

Askild
-



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