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Posted to issues@camel.apache.org by "Hieu Nguyen (JIRA)" <ji...@apache.org> on 2015/06/10 19:38:01 UTC

[jira] [Commented] (CAMEL-7031) RabbitMQ Producer not able to use the default exchange

    [ https://issues.apache.org/jira/browse/CAMEL-7031?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=14580860#comment-14580860 ] 

Hieu Nguyen commented on CAMEL-7031:
------------------------------------

I'm camel-rabbitmq component as as rabbitmq consumer. The consumer is consuming message from a default exchange "" with a routing key. When I started up the app, I got the exception "Caused by: java.lang.IllegalArgumentException: No URI path as the exchangeName for the RabbitMQEndpoint". 
The camel version I'm using is 2.15.2.

Regards,

> RabbitMQ Producer not able to use the default exchange
> ------------------------------------------------------
>
>                 Key: CAMEL-7031
>                 URL: https://issues.apache.org/jira/browse/CAMEL-7031
>             Project: Camel
>          Issue Type: Bug
>          Components: camel-rabbitmq
>    Affects Versions: 2.12.2
>            Reporter: Jason Foster
>            Assignee: Willem Jiang
>             Fix For: 2.12.3
>
>
> In RabbitMQ, the default exchange is a direct exchange with no name (empty string) and is pre-declared by the broker. It has one special property that makes it very useful for simple applications: every queue that is created is automatically bound to it with a routing key which is the same as the queue name.  This is especially useful in RPC style messaging when the producer specifies a REPLY_TO queue name that was created "exclusive"  Since RabbitMQ binds that queue onto the default exchange, it makes RPC much simpler.
> However, the camel rabbitmq producer throws an IllegalArgumentException if the exchange name is empty, which prevents this simple RPC exchange.  The fix for this is simple, just don't throw that IllegalArgumentException if the exchange name was set to empty string.
> The same problem may exists with the Consumer as well.
> This python script will send an rpc request (from RabbitMQ in Action)
> {code}
> import time, json, pika
> creds_broker = pika.PlainCredentials("guest", "guest")
> conn_params = pika.ConnectionParameters("localhost",
>                                          virtual_host = "/",
>                                          credentials = creds_broker)
> conn_broker = pika.BlockingConnection(conn_params)
> channel = conn_broker.channel()
> msg = json.dumps({"client_name": "RPC Client 1.0",
>                   "time" : time.time()})
> result = channel.queue_declare(exclusive=True, auto_delete=True)
> msg_props = pika.BasicProperties()
> msg_props.reply_to = result.method.queue
> msg_props.content_type = "application/json"
> msg_props.correlation_id = "1"
> msg_props.delivery_mode = 2
> channel.basic_publish(body=msg,
>                       exchange="rpc",
>                       properties=msg_props,
>                       routing_key="ping")
> print "Sent 'Ping' RPC call.  Waiting for reply..."
> def reply_callback(channel, method, header, body):
>      """Receives RPC server replies."""
>      print "RPC Reply --- " + body
>      channel.stop_consuming()
> channel.basic_consume(reply_callback,
>                       queue=result.method.queue,
>                       consumer_tag=result.method.queue)
> channel.start_consuming()
> {code}
> This route would be what I would want to do when consuming from Rabbit the rpc call and sending back a response:
> {code}
>         from("rabbitmq://192.168.213.130/rpc?queue=ping&routingKey=ping&durable=True&autoDelete=False&autoAck=False&username=guest&password=guest")
>             .log("Incoming Headers: ${headers}")
>             .setHeader("rabbitmq.ROUTING_KEY", header("rabbitmq.REPLY_TO"))
>             .removeHeader("rabbitmq.REPLY_TO")
>             .removeHeader("rabbitmq.EXCHANGE_NAME")
>             .setBody(simple("Pong!"))
>             .to("rabbitmq://192.168.213.130/?username=guest&password=guest");
> {code}
> If I remove the illegalargumentexception, the code works as expected.



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