DO NOT REPLY [Bug 9543] New: - Iusses with Encoder and Tomcat 4.0.3

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http://nagoya.apache.org/bugzilla/show_bug.cgi?id=9543

Iusses with Encoder and Tomcat 4.0.3

           Summary: Iusses with Encoder and Tomcat 4.0.3
           Product: XalanJ2
           Version: CurrentCVS
          Platform: PC
        OS/Version: Windows NT/2K
            Status: NEW
          Severity: Normal
          Priority: Other
         Component: org.apache.xalan.serialize
        AssignedTo: xalan-dev@xml.apache.org
        ReportedBy: bk@avolent.com


I attempted to use the nightly build of Xalan from 5/22/2002 within Tomcat
4.0.3. I have unjarred build into a web-app. I got a null point ecxception on
line 357 of org.apache.xalan.serialized.Encodings.java. I believe the issue is
how the Encodings.java is located within tomcats nested class loaders.

I debugged a little bit and modified the code, and this is what I saw (See the
System.outs)

"ST" was blank
"BK" showed a tomcat WebAppClass loader which pointed to the WEB-INF\classes
directory as it should. It delegeted up several layers as is typical for tomcat. 
"B" was null
"C" was null

by moving the location of the file, it was found. TO be fair.. I do not recall
if it ws "B" or "C" that found it however.


  private static EncodingInfo[] loadEncodingInfo()
  {
    URL url = null;
    try {
      String urlString =
        System.getProperty("org.apache.xalan.serialize.encodings", "");
      System.out.println("ST" + urlString) ;
      if (urlString == null || urlString.length() == 0) {
        ClassLoader cl = Encodings.class.getClassLoader();
        System.out.println("org/apache/xalan/serialize/" +
                                              ENCODINGS_FILE) ;
        System.out.println("BK" + cl) ;

        if (cl == null) {
          url = ClassLoader.getSystemResource("org/apache/xalan/serialize/" +
                                              ENCODINGS_FILE);
          System.out.println("A" + url) ;

        } else {
          url = cl.getResource(ENCODINGS_FILE);
          System.out.println("B" + url) ;
          if (url == null)
            url = ClassLoader.getSystemResource("org/apache/xalan/serialize/" +
                                              ENCODINGS_FILE);
          System.out.println("C" + url) ;

        }
      } else {
        url = new URL (urlString);
        System.out.println("D" + url) ;

      }

      // ? consider whether we should allow an exception here if resource
      // is not found or should we return an empty array ?
      InputStream is = url.openStream();