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Posted to users@camel.apache.org by janylj <ja...@gmail.com> on 2009/08/11 01:11:19 UTC
How to create a Servlet component?
Hello,
Camel is pretty new to me. This might be a simple question but I cannot find
the answer in the web.
I am following Servlet Component page
(http://camel.apache.org/servlet.html). However, when I start Tomcat, there
are repeating warning message said,
Aug 10, 2009 3:44:03 PM
org.apache.camel.impl.DefaultPollingConsumerPollStrategy rollback
WARNING: Consumer Consumer[servlet:/hello] could not poll endpoint:
servlet:/hello caused by: unsupported protocol: 'servlet'
java.lang.IllegalStateException: unsupported protocol: 'servlet'
at
org.apache.commons.httpclient.protocol.Protocol.lazyRegisterProtocol(Protocol.java:149)
at
org.apache.commons.httpclient.protocol.Protocol.getProtocol(Protocol.java:117)
at org.apache.commons.httpclient.HttpHost.<init>(HttpHost.java:107)
at
org.apache.commons.httpclient.HttpMethodBase.setURI(HttpMethodBase.java:280)
at
org.apache.commons.httpclient.HttpMethodBase.<init>(HttpMethodBase.java:220)
at
org.apache.commons.httpclient.methods.GetMethod.<init>(GetMethod.java:89)
at
org.apache.camel.component.http.HttpPollingConsumer.createMethod(HttpPollingConsumer.java:110)
at
org.apache.camel.component.http.HttpPollingConsumer.receiveNoWait(HttpPollingConsumer.java:60)
at
org.apache.camel.impl.DefaultScheduledPollConsumer.poll(DefaultScheduledPollConsumer.java:45)
at
org.apache.camel.impl.ScheduledPollConsumer.run(ScheduledPollConsumer.java:98)
at java.util.concurrent.Executors$RunnableAdapter.call(Executors.java:417)
at
java.util.concurrent.FutureTask$Sync.innerRunAndReset(FutureTask.java:280)
at java.util.concurrent.FutureTask.runAndReset(FutureTask.java:135)
at
java.util.concurrent.ScheduledThreadPoolExecutor$ScheduledFutureTask.access$101(ScheduledThreadPoolExecutor.java:65)
at
java.util.concurrent.ScheduledThreadPoolExecutor$ScheduledFutureTask.runPeriodic(ScheduledThreadPoolExecutor.java:142)
at
java.util.concurrent.ScheduledThreadPoolExecutor$ScheduledFutureTask.run(ScheduledThreadPoolExecutor.java:166)
at
java.util.concurrent.ThreadPoolExecutor$Worker.runTask(ThreadPoolExecutor.java:650)
at
java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:675)
at java.lang.Thread.run(Thread.java:595)
My web.xml has:
<!-- location of spring xml files -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:camel-config.xml</param-value>
</context-param>
<!-- the listener that kick-starts Spring -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>CamelServlet</servlet-name>
<servlet-class>
org.apache.camel.component.servlet.CamelHttpTransportServlet
</servlet-class>
<init-param>
<param-name>matchOnUriPrefix</param-name>
<param-value>true</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>CamelServlet</servlet-name>
<url-pattern>/services/*</url-pattern>
</servlet-mapping>
The camel-context.xml has:
<!-- create a camel context as to start Camel -->
<camelContext id="camel" xmlns="http://camel.apache.org/schema/spring">
<package>package.has.routebuilderl</package>
</camelContext>
<bean id="servlet" class="org.apache.camel.component.http.HttpComponent">
<property name="camelContext" ref="camel" />
</bean>
The RouteBuilder is exactly what lists in the web page.
from("servlet:///hello").process(new Processor() {
public void process(Exchange exchange) throws Exception {
String contentType =
exchange.getIn().getHeader(Exchange.CONTENT_TYPE, String.class);
String path = exchange.getIn().getHeader(Exchange.HTTP_PATH,
String.class);
assertEquals("Get a wrong content type", CONTENT_TYPE, contentType);
String charsetEncoding =
exchange.getIn().getHeader(Exchange.HTTP_CHARACTER_ENCODING, String.class);
assertEquals("Get a wrong charset name", "UTF-8", charsetEncoding);
exchange.getOut().setHeader(Exchange.CONTENT_TYPE, contentType + ";
charset=UTF-8");
exchange.getOut().setHeader("PATH", path);
exchange.getOut().setBody("Hello World");
}
});
--
View this message in context: http://www.nabble.com/How-to-create-a-Servlet-component--tp24909157p24909157.html
Sent from the Camel - Users mailing list archive at Nabble.com.
Re: How to create a Servlet component?
Posted by Willem Jiang <wi...@gmail.com>.
Hi,
I just wrote a simple unit test which is based on your test case, I got
the same error.
That is because the camel context is created before the servlet instance
is initialized.
So I added an init parameter in the CamelHttpTransportServlet to
consumer the spring application context configure file, and make sure
the camel context is created after servlet initialization.
You can find the example here.
http://svn.apache.org/viewvc?rev=803805&view=rev
Willem
janylj wrote:
> Sure.
>
> camel-config.xml:
>
> <beans xmlns="http://www.springframework.org/schema/beans"
> xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
> xsi:schemaLocation="
> http://camel.apache.org/schema/spring
> http://camel.apache.org/schema/spring/camel-spring.xsd
> http://www.springframework.org/schema/beans
> http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">
>
> <!-- create a camel context as to start Camel -->
> <camelContext id="camel" xmlns="http://camel.apache.org/schema/spring">
> <package>package.contains.route.builder</package>
> </camelContext>
> </beans>
>
> web.xml:
> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
> xmlns="http://java.sun.com/xml/ns/javaee"
> xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
> xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
> http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
> id="WebApp_ID" version="2.5">
>
> <servlet>
> <servlet-name>CamelServlet</servlet-name>
> <servlet-class>
> org.apache.camel.component.servlet.CamelHttpTransportServlet
> </servlet-class>
> <init-param>
> <param-name>matchOnUriPrefix</param-name>
> <param-value>true</param-value>
> </init-param>
> <load-on-startup>1</load-on-startup>
> </servlet>
>
> <servlet-mapping>
> <servlet-name>CamelServlet</servlet-name>
> <url-pattern>/services/*</url-pattern>
> </servlet-mapping>
>
> <!-- location of spring xml files -->
> <context-param>
> <param-name>contextConfigLocation</param-name>
> <param-value>classpath:camel-config.xml</param-value>
> </context-param>
>
> <!-- the listener that kick-starts Spring -->
> <listener>
>
> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
> </listener>
> </web-app>
>
> RouteBuilder java class:
> public class ServletToJmsRouteBuilder extends RouteBuilder {
>
> public void configure() throws Exception {
> from("servlet:///hello?servletName=CamelServlet").process(new Processor()
> {
>
> public void process(Exchange exchange) {
> String contentType = (String)
> exchange.getIn().getHeader(Exchange.CONTENT_TYPE, String.class);
> String path = (String)
> exchange.getIn().getHeader(Exchange.HTTP_PATH, String.class);
> String charsetEncoding = (String)
> exchange.getIn().getHeader(Exchange.HTTP_CHARACTER_ENCODING, String.class);
> exchange.getOut().setHeader(Exchange.CONTENT_TYPE,
> contentType + "; charset=UTF-8");
> exchange.getOut().setHeader("PATH", path);
> exchange.getOut().setBody("Hello World");
> }
> });
> }
> }
>
> Please let me know if you need anything else. Thanks a lot.
>
>
> willem.jiang wrote:
>> Hi,
>>
>> Can you show me the camel-config.xml?
>> A simple demo help me debug the issue.
>>
>> Willem
>>
>> janylj wrote:
>>> willem.jiang wrote:
>>>> If you create the servlet component, you need to specify the servlet
>>>> which the component will attach to.
>>>> <bean id="servlet"
>>>> class="org.apache.camel.component.servlet.ServletComponent">
>>>> <property name="camelContext" ref="camel" />
>>>> <property name="servletName" value="CamelServlet" />
>>>> </bean>
>>>>
>>>>
>>> doesn't work, because Tomcat starts error said,
>>>
>>> Caused by: org.springframework.beans.InvalidPropertyException: Invalid
>>> property 'servletName' of bean class
>>> [org.apache.camel.component.servlet.ServletComponent]: No property
>>> 'servletName' found
>>>
>>>
>>> willem.jiang wrote:
>>>> You don't need to specify the servlet component in spring, if there is
>>>> only one camel servlet created in the web context.
>>>>
>>>>
>>> doesn't work, because Tomcat starts error said,
>>>
>>> Caused by: java.lang.IllegalArgumentException: Can't find the deployied
>>> servlet, please set the ServletComponent with it or delopy a
>>> CamelHttpTransportServlet int the web container
>>>
>>> What I am missing? Please note that I am using Spring
>>> ContextLoaderListener.
>>> Thanks a lot.
>>>
>>> my web.xml,
>>>
>>> <!-- location of spring xml files -->
>>> <context-param>
>>> <param-name>contextConfigLocation</param-name>
>>> <param-value>classpath:camel-config.xml</param-value>
>>> </context-param>
>>>
>>> <!-- the listener that kick-starts Spring -->
>>> <listener>
>>>
>>> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
>>> </listener>
>>>
>>> <servlet>
>>> <servlet-name>CamelServlet</servlet-name>
>>> <servlet-class>
>>> org.apache.camel.component.servlet.CamelHttpTransportServlet
>>> </servlet-class>
>>> <init-param>
>>> <param-name>matchOnUriPrefix</param-name>
>>> <param-value>true</param-value>
>>> </init-param>
>>> <load-on-startup>1</load-on-startup>
>>> </servlet>
>>>
>>> <servlet-mapping>
>>> <servlet-name>CamelServlet</servlet-name>
>>> <url-pattern>/services/*</url-pattern>
>>> </servlet-mapping>
>>>
>>>
>>>
>>
>>
>
Re: How to create a Servlet component?
Posted by Claus Ibsen <cl...@gmail.com>.
Hi
Just to inform Camel have the camel-jetty component that allows you to
expose a HTTP service and let Camel handle the request and return a
reply.
http://camel.apache.org/jetty
But you got the right source about the Camel Servlet as it was Willem
who wrote it.
On Wed, Aug 12, 2009 at 6:28 PM, janylj<ja...@gmail.com> wrote:
>
> Sure.
>
> camel-config.xml:
>
> <beans xmlns="http://www.springframework.org/schema/beans"
> xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
> xsi:schemaLocation="
> http://camel.apache.org/schema/spring
> http://camel.apache.org/schema/spring/camel-spring.xsd
> http://www.springframework.org/schema/beans
> http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">
>
> <!-- create a camel context as to start Camel -->
> <camelContext id="camel" xmlns="http://camel.apache.org/schema/spring">
> <package>package.contains.route.builder</package>
> </camelContext>
> </beans>
>
> web.xml:
> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
> xmlns="http://java.sun.com/xml/ns/javaee"
> xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
> xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
> http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
> id="WebApp_ID" version="2.5">
>
> <servlet>
> <servlet-name>CamelServlet</servlet-name>
> <servlet-class>
> org.apache.camel.component.servlet.CamelHttpTransportServlet
> </servlet-class>
> <init-param>
> <param-name>matchOnUriPrefix</param-name>
> <param-value>true</param-value>
> </init-param>
> <load-on-startup>1</load-on-startup>
> </servlet>
>
> <servlet-mapping>
> <servlet-name>CamelServlet</servlet-name>
> <url-pattern>/services/*</url-pattern>
> </servlet-mapping>
>
> <!-- location of spring xml files -->
> <context-param>
> <param-name>contextConfigLocation</param-name>
> <param-value>classpath:camel-config.xml</param-value>
> </context-param>
>
> <!-- the listener that kick-starts Spring -->
> <listener>
>
> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
> </listener>
> </web-app>
>
> RouteBuilder java class:
> public class ServletToJmsRouteBuilder extends RouteBuilder {
>
> public void configure() throws Exception {
> from("servlet:///hello?servletName=CamelServlet").process(new Processor()
> {
>
> public void process(Exchange exchange) {
> String contentType = (String)
> exchange.getIn().getHeader(Exchange.CONTENT_TYPE, String.class);
> String path = (String)
> exchange.getIn().getHeader(Exchange.HTTP_PATH, String.class);
> String charsetEncoding = (String)
> exchange.getIn().getHeader(Exchange.HTTP_CHARACTER_ENCODING, String.class);
> exchange.getOut().setHeader(Exchange.CONTENT_TYPE,
> contentType + "; charset=UTF-8");
> exchange.getOut().setHeader("PATH", path);
> exchange.getOut().setBody("Hello World");
> }
> });
> }
> }
>
> Please let me know if you need anything else. Thanks a lot.
>
>
> willem.jiang wrote:
>>
>> Hi,
>>
>> Can you show me the camel-config.xml?
>> A simple demo help me debug the issue.
>>
>> Willem
>>
>> janylj wrote:
>>>
>>> willem.jiang wrote:
>>>>
>>>> If you create the servlet component, you need to specify the servlet
>>>> which the component will attach to.
>>>> <bean id="servlet"
>>>> class="org.apache.camel.component.servlet.ServletComponent">
>>>> <property name="camelContext" ref="camel" />
>>>> <property name="servletName" value="CamelServlet" />
>>>> </bean>
>>>>
>>>>
>>>
>>> doesn't work, because Tomcat starts error said,
>>>
>>> Caused by: org.springframework.beans.InvalidPropertyException: Invalid
>>> property 'servletName' of bean class
>>> [org.apache.camel.component.servlet.ServletComponent]: No property
>>> 'servletName' found
>>>
>>>
>>> willem.jiang wrote:
>>>>
>>>> You don't need to specify the servlet component in spring, if there is
>>>> only one camel servlet created in the web context.
>>>>
>>>>
>>>
>>> doesn't work, because Tomcat starts error said,
>>>
>>> Caused by: java.lang.IllegalArgumentException: Can't find the deployied
>>> servlet, please set the ServletComponent with it or delopy a
>>> CamelHttpTransportServlet int the web container
>>>
>>> What I am missing? Please note that I am using Spring
>>> ContextLoaderListener.
>>> Thanks a lot.
>>>
>>> my web.xml,
>>>
>>> <!-- location of spring xml files -->
>>> <context-param>
>>> <param-name>contextConfigLocation</param-name>
>>> <param-value>classpath:camel-config.xml</param-value>
>>> </context-param>
>>>
>>> <!-- the listener that kick-starts Spring -->
>>> <listener>
>>>
>>> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
>>> </listener>
>>>
>>> <servlet>
>>> <servlet-name>CamelServlet</servlet-name>
>>> <servlet-class>
>>> org.apache.camel.component.servlet.CamelHttpTransportServlet
>>> </servlet-class>
>>> <init-param>
>>> <param-name>matchOnUriPrefix</param-name>
>>> <param-value>true</param-value>
>>> </init-param>
>>> <load-on-startup>1</load-on-startup>
>>> </servlet>
>>>
>>> <servlet-mapping>
>>> <servlet-name>CamelServlet</servlet-name>
>>> <url-pattern>/services/*</url-pattern>
>>> </servlet-mapping>
>>>
>>>
>>>
>>
>>
>>
>
> --
> View this message in context: http://www.nabble.com/How-to-create-a-Servlet-component--tp24909157p24940161.html
> Sent from the Camel - Users mailing list archive at Nabble.com.
>
>
--
Claus Ibsen
Apache Camel Committer
Open Source Integration: http://fusesource.com
Blog: http://davsclaus.blogspot.com/
Twitter: http://twitter.com/davsclaus
Re: How to create a Servlet component?
Posted by janylj <ja...@gmail.com>.
Sure.
camel-config.xml:
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://camel.apache.org/schema/spring
http://camel.apache.org/schema/spring/camel-spring.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">
<!-- create a camel context as to start Camel -->
<camelContext id="camel" xmlns="http://camel.apache.org/schema/spring">
<package>package.contains.route.builder</package>
</camelContext>
</beans>
web.xml:
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<servlet>
<servlet-name>CamelServlet</servlet-name>
<servlet-class>
org.apache.camel.component.servlet.CamelHttpTransportServlet
</servlet-class>
<init-param>
<param-name>matchOnUriPrefix</param-name>
<param-value>true</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>CamelServlet</servlet-name>
<url-pattern>/services/*</url-pattern>
</servlet-mapping>
<!-- location of spring xml files -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:camel-config.xml</param-value>
</context-param>
<!-- the listener that kick-starts Spring -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
</web-app>
RouteBuilder java class:
public class ServletToJmsRouteBuilder extends RouteBuilder {
public void configure() throws Exception {
from("servlet:///hello?servletName=CamelServlet").process(new Processor()
{
public void process(Exchange exchange) {
String contentType = (String)
exchange.getIn().getHeader(Exchange.CONTENT_TYPE, String.class);
String path = (String)
exchange.getIn().getHeader(Exchange.HTTP_PATH, String.class);
String charsetEncoding = (String)
exchange.getIn().getHeader(Exchange.HTTP_CHARACTER_ENCODING, String.class);
exchange.getOut().setHeader(Exchange.CONTENT_TYPE,
contentType + "; charset=UTF-8");
exchange.getOut().setHeader("PATH", path);
exchange.getOut().setBody("Hello World");
}
});
}
}
Please let me know if you need anything else. Thanks a lot.
willem.jiang wrote:
>
> Hi,
>
> Can you show me the camel-config.xml?
> A simple demo help me debug the issue.
>
> Willem
>
> janylj wrote:
>>
>> willem.jiang wrote:
>>>
>>> If you create the servlet component, you need to specify the servlet
>>> which the component will attach to.
>>> <bean id="servlet"
>>> class="org.apache.camel.component.servlet.ServletComponent">
>>> <property name="camelContext" ref="camel" />
>>> <property name="servletName" value="CamelServlet" />
>>> </bean>
>>>
>>>
>>
>> doesn't work, because Tomcat starts error said,
>>
>> Caused by: org.springframework.beans.InvalidPropertyException: Invalid
>> property 'servletName' of bean class
>> [org.apache.camel.component.servlet.ServletComponent]: No property
>> 'servletName' found
>>
>>
>> willem.jiang wrote:
>>>
>>> You don't need to specify the servlet component in spring, if there is
>>> only one camel servlet created in the web context.
>>>
>>>
>>
>> doesn't work, because Tomcat starts error said,
>>
>> Caused by: java.lang.IllegalArgumentException: Can't find the deployied
>> servlet, please set the ServletComponent with it or delopy a
>> CamelHttpTransportServlet int the web container
>>
>> What I am missing? Please note that I am using Spring
>> ContextLoaderListener.
>> Thanks a lot.
>>
>> my web.xml,
>>
>> <!-- location of spring xml files -->
>> <context-param>
>> <param-name>contextConfigLocation</param-name>
>> <param-value>classpath:camel-config.xml</param-value>
>> </context-param>
>>
>> <!-- the listener that kick-starts Spring -->
>> <listener>
>>
>> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
>> </listener>
>>
>> <servlet>
>> <servlet-name>CamelServlet</servlet-name>
>> <servlet-class>
>> org.apache.camel.component.servlet.CamelHttpTransportServlet
>> </servlet-class>
>> <init-param>
>> <param-name>matchOnUriPrefix</param-name>
>> <param-value>true</param-value>
>> </init-param>
>> <load-on-startup>1</load-on-startup>
>> </servlet>
>>
>> <servlet-mapping>
>> <servlet-name>CamelServlet</servlet-name>
>> <url-pattern>/services/*</url-pattern>
>> </servlet-mapping>
>>
>>
>>
>
>
>
--
View this message in context: http://www.nabble.com/How-to-create-a-Servlet-component--tp24909157p24940161.html
Sent from the Camel - Users mailing list archive at Nabble.com.
Re: How to create a Servlet component?
Posted by Willem Jiang <wi...@gmail.com>.
Hi,
Can you show me the camel-config.xml?
A simple demo help me debug the issue.
Willem
janylj wrote:
>
> willem.jiang wrote:
>>
>> If you create the servlet component, you need to specify the servlet
>> which the component will attach to.
>> <bean id="servlet"
>> class="org.apache.camel.component.servlet.ServletComponent">
>> <property name="camelContext" ref="camel" />
>> <property name="servletName" value="CamelServlet" />
>> </bean>
>>
>>
>
> doesn't work, because Tomcat starts error said,
>
> Caused by: org.springframework.beans.InvalidPropertyException: Invalid
> property 'servletName' of bean class
> [org.apache.camel.component.servlet.ServletComponent]: No property
> 'servletName' found
>
>
> willem.jiang wrote:
>>
>> You don't need to specify the servlet component in spring, if there is
>> only one camel servlet created in the web context.
>>
>>
>
> doesn't work, because Tomcat starts error said,
>
> Caused by: java.lang.IllegalArgumentException: Can't find the deployied
> servlet, please set the ServletComponent with it or delopy a
> CamelHttpTransportServlet int the web container
>
> What I am missing? Please note that I am using Spring ContextLoaderListener.
> Thanks a lot.
>
> my web.xml,
>
> <!-- location of spring xml files -->
> <context-param>
> <param-name>contextConfigLocation</param-name>
> <param-value>classpath:camel-config.xml</param-value>
> </context-param>
>
> <!-- the listener that kick-starts Spring -->
> <listener>
>
> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
> </listener>
>
> <servlet>
> <servlet-name>CamelServlet</servlet-name>
> <servlet-class>
> org.apache.camel.component.servlet.CamelHttpTransportServlet
> </servlet-class>
> <init-param>
> <param-name>matchOnUriPrefix</param-name>
> <param-value>true</param-value>
> </init-param>
> <load-on-startup>1</load-on-startup>
> </servlet>
>
> <servlet-mapping>
> <servlet-name>CamelServlet</servlet-name>
> <url-pattern>/services/*</url-pattern>
> </servlet-mapping>
>
>
>
Re: How to create a Servlet component?
Posted by janylj <ja...@gmail.com>.
willem.jiang wrote:
>
>
> If you create the servlet component, you need to specify the servlet
> which the component will attach to.
> <bean id="servlet"
> class="org.apache.camel.component.servlet.ServletComponent">
> <property name="camelContext" ref="camel" />
> <property name="servletName" value="CamelServlet" />
> </bean>
>
>
doesn't work, because Tomcat starts error said,
Caused by: org.springframework.beans.InvalidPropertyException: Invalid
property 'servletName' of bean class
[org.apache.camel.component.servlet.ServletComponent]: No property
'servletName' found
willem.jiang wrote:
>
>
> You don't need to specify the servlet component in spring, if there is
> only one camel servlet created in the web context.
>
>
doesn't work, because Tomcat starts error said,
Caused by: java.lang.IllegalArgumentException: Can't find the deployied
servlet, please set the ServletComponent with it or delopy a
CamelHttpTransportServlet int the web container
What I am missing? Please note that I am using Spring ContextLoaderListener.
Thanks a lot.
my web.xml,
<!-- location of spring xml files -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:camel-config.xml</param-value>
</context-param>
<!-- the listener that kick-starts Spring -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>CamelServlet</servlet-name>
<servlet-class>
org.apache.camel.component.servlet.CamelHttpTransportServlet
</servlet-class>
<init-param>
<param-name>matchOnUriPrefix</param-name>
<param-value>true</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>CamelServlet</servlet-name>
<url-pattern>/services/*</url-pattern>
</servlet-mapping>
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Re: How to create a Servlet component?
Posted by Willem Jiang <wi...@gmail.com>.
Hi,
You don't need to specify the servlet component in spring, if there is
only one camel servlet created in the web context.
If you create the servlet component, you need to specify the servlet
which the component will attach to.
<bean id="servlet"
class="org.apache.camel.component.servlet.ServletComponent">
<property name="camelContext" ref="camel" />
<property name="servletName" value="CamelServlet" />
</bean>
Web.xml
<web-app>
<servlet>
<servlet-name>CamelServlet</servlet-name>
<display-name>Camel Http Transport Servlet</display-name>
<servlet-class>
org.apache.camel.component.servlet.CamelHttpTransportServlet
</servlet-class>
<init-param>
<param-name>matchOnUriPrefix</param-name>
<param-value>true</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>CamelServlet</servlet-name>
<url-pattern>/services/*</url-pattern>
</servlet-mapping>
</web-app>
Willem
janylj wrote:
> I add camel-servlet to pom.xml and in the camel-context.xml, I added:
>
> <bean id="servlet"
> class="org.apache.camel.component.servlet.ServletComponent">
> <property name="camelContext" ref="camel" />
> </bean>
>
> However, I still get the following error when starting Tomcat.
>
> SEVERE: Context initialization failed
> org.apache.camel.RuntimeCamelException: java.lang.IllegalArgumentException:
> Can't find the deployied servlet, please set the ServletComponent with it or
> delopy a CamelHttpTransportServlet int the web container
> at
> org.apache.camel.util.ObjectHelper.wrapRuntimeCamelException(ObjectHelper.java:1011)
> at
> org.apache.camel.spring.SpringCamelContext.onApplicationEvent(SpringCamelContext.java:121)
> at
> org.apache.camel.spring.CamelContextFactoryBean.onApplicationEvent(CamelContextFactoryBean.java:461)
> at
> org.springframework.context.event.SimpleApplicationEventMulticaster$1.run(SimpleApplicationEventMulticaster.java:78)
> at
> org.springframework.core.task.SyncTaskExecutor.execute(SyncTaskExecutor.java:49)
> at
> org.springframework.context.event.SimpleApplicationEventMulticaster.multicastEvent(SimpleApplicationEventMulticaster.java:76)
> at
> org.springframework.context.support.AbstractApplicationContext.publishEvent(AbstractApplicationContext.java:275)
> at
> org.springframework.context.support.AbstractApplicationContext.finishRefresh(AbstractApplicationContext.java:737)
> at
> org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:384)
> at
> org.springframework.web.context.ContextLoader.createWebApplicationContext(ContextLoader.java:255)
> at
> org.springframework.web.context.ContextLoader.initWebApplicationContext(ContextLoader.java:199)
> at
> org.springframework.web.context.ContextLoaderListener.contextInitialized(ContextLoaderListener.java:45)
> at
> org.apache.catalina.core.StandardContext.listenerStart(StandardContext.java:3843)
> at
> org.apache.catalina.core.StandardContext.start(StandardContext.java:4350)
> at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1045)
> at org.apache.catalina.core.StandardHost.start(StandardHost.java:719)
> at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1045)
> at org.apache.catalina.core.StandardEngine.start(StandardEngine.java:443)
> at org.apache.catalina.core.StandardService.start(StandardService.java:516)
> at org.apache.catalina.core.StandardServer.start(StandardServer.java:710)
> at org.apache.catalina.startup.Catalina.start(Catalina.java:578)
> at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
> at
> sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
> at
> sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
> at java.lang.reflect.Method.invoke(Method.java:585)
> at org.apache.catalina.startup.Bootstrap.start(Bootstrap.java:288)
> at org.apache.catalina.startup.Bootstrap.main(Bootstrap.java:413)
>
> willem.jiang wrote:
>> Hi,
>>
>> You need to include the camel-servlet jar which is not a part of
>> camel-http module and the camel-servlet component is a new component for
>> camel 2.0 M3.
>>
>> I will update the wiki page for it.
>>
>> Willem
>>
>> janylj wrote:
>>>
>>> janylj wrote:
>>>> The camel-context.xml has:
>>>>
>>>> <!-- create a camel context as to start Camel -->
>>>> <camelContext id="camel" xmlns="http://camel.apache.org/schema/spring">
>>>> <package>package.has.routebuilderl</package>
>>>> </camelContext>
>>>> <bean id="servlet"
>>>> class="org.apache.camel.component.http.HttpComponent">
>>>> <property name="camelContext" ref="camel" />
>>>> </bean>
>>>>
>>>>
>>> I figure that I should not have a HttpComponent for servlet scheme
>>> because
>>> HttpComponent is only for output data. Then what component I should set
>>> for
>>> servlet. If I delete HttpComponent part, Tomat has error.
>>>
>>> SEVERE: Context initialization failed
>>> org.apache.camel.ResolveEndpointFailedException: Failed to resolve
>>> endpoint:
>>> servlet:///hello due to: No component found with scheme: servlet
>>> at
>>> org.apache.camel.impl.DefaultCamelContext.getEndpoint(DefaultCamelContext.java:411)
>>>
>>
>>
>
Re: How to create a Servlet component?
Posted by janylj <ja...@gmail.com>.
I add camel-servlet to pom.xml and in the camel-context.xml, I added:
<bean id="servlet"
class="org.apache.camel.component.servlet.ServletComponent">
<property name="camelContext" ref="camel" />
</bean>
However, I still get the following error when starting Tomcat.
SEVERE: Context initialization failed
org.apache.camel.RuntimeCamelException: java.lang.IllegalArgumentException:
Can't find the deployied servlet, please set the ServletComponent with it or
delopy a CamelHttpTransportServlet int the web container
at
org.apache.camel.util.ObjectHelper.wrapRuntimeCamelException(ObjectHelper.java:1011)
at
org.apache.camel.spring.SpringCamelContext.onApplicationEvent(SpringCamelContext.java:121)
at
org.apache.camel.spring.CamelContextFactoryBean.onApplicationEvent(CamelContextFactoryBean.java:461)
at
org.springframework.context.event.SimpleApplicationEventMulticaster$1.run(SimpleApplicationEventMulticaster.java:78)
at
org.springframework.core.task.SyncTaskExecutor.execute(SyncTaskExecutor.java:49)
at
org.springframework.context.event.SimpleApplicationEventMulticaster.multicastEvent(SimpleApplicationEventMulticaster.java:76)
at
org.springframework.context.support.AbstractApplicationContext.publishEvent(AbstractApplicationContext.java:275)
at
org.springframework.context.support.AbstractApplicationContext.finishRefresh(AbstractApplicationContext.java:737)
at
org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:384)
at
org.springframework.web.context.ContextLoader.createWebApplicationContext(ContextLoader.java:255)
at
org.springframework.web.context.ContextLoader.initWebApplicationContext(ContextLoader.java:199)
at
org.springframework.web.context.ContextLoaderListener.contextInitialized(ContextLoaderListener.java:45)
at
org.apache.catalina.core.StandardContext.listenerStart(StandardContext.java:3843)
at
org.apache.catalina.core.StandardContext.start(StandardContext.java:4350)
at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1045)
at org.apache.catalina.core.StandardHost.start(StandardHost.java:719)
at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1045)
at org.apache.catalina.core.StandardEngine.start(StandardEngine.java:443)
at org.apache.catalina.core.StandardService.start(StandardService.java:516)
at org.apache.catalina.core.StandardServer.start(StandardServer.java:710)
at org.apache.catalina.startup.Catalina.start(Catalina.java:578)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at
sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
at
sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
at java.lang.reflect.Method.invoke(Method.java:585)
at org.apache.catalina.startup.Bootstrap.start(Bootstrap.java:288)
at org.apache.catalina.startup.Bootstrap.main(Bootstrap.java:413)
willem.jiang wrote:
>
> Hi,
>
> You need to include the camel-servlet jar which is not a part of
> camel-http module and the camel-servlet component is a new component for
> camel 2.0 M3.
>
> I will update the wiki page for it.
>
> Willem
>
> janylj wrote:
>>
>>
>> janylj wrote:
>>>
>>> The camel-context.xml has:
>>>
>>> <!-- create a camel context as to start Camel -->
>>> <camelContext id="camel" xmlns="http://camel.apache.org/schema/spring">
>>> <package>package.has.routebuilderl</package>
>>> </camelContext>
>>> <bean id="servlet"
>>> class="org.apache.camel.component.http.HttpComponent">
>>> <property name="camelContext" ref="camel" />
>>> </bean>
>>>
>>>
>>
>> I figure that I should not have a HttpComponent for servlet scheme
>> because
>> HttpComponent is only for output data. Then what component I should set
>> for
>> servlet. If I delete HttpComponent part, Tomat has error.
>>
>> SEVERE: Context initialization failed
>> org.apache.camel.ResolveEndpointFailedException: Failed to resolve
>> endpoint:
>> servlet:///hello due to: No component found with scheme: servlet
>> at
>> org.apache.camel.impl.DefaultCamelContext.getEndpoint(DefaultCamelContext.java:411)
>>
>
>
>
--
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Re: How to create a Servlet component?
Posted by Willem Jiang <wi...@gmail.com>.
Hi,
You need to include the camel-servlet jar which is not a part of
camel-http module and the camel-servlet component is a new component for
camel 2.0 M3.
I will update the wiki page for it.
Willem
janylj wrote:
>
>
> janylj wrote:
>>
>> The camel-context.xml has:
>>
>> <!-- create a camel context as to start Camel -->
>> <camelContext id="camel" xmlns="http://camel.apache.org/schema/spring">
>> <package>package.has.routebuilderl</package>
>> </camelContext>
>> <bean id="servlet" class="org.apache.camel.component.http.HttpComponent">
>> <property name="camelContext" ref="camel" />
>> </bean>
>>
>>
>
> I figure that I should not have a HttpComponent for servlet scheme because
> HttpComponent is only for output data. Then what component I should set for
> servlet. If I delete HttpComponent part, Tomat has error.
>
> SEVERE: Context initialization failed
> org.apache.camel.ResolveEndpointFailedException: Failed to resolve endpoint:
> servlet:///hello due to: No component found with scheme: servlet
> at
> org.apache.camel.impl.DefaultCamelContext.getEndpoint(DefaultCamelContext.java:411)
>
Re: How to create a Servlet component?
Posted by janylj <ja...@gmail.com>.
janylj wrote:
>
>
> The camel-context.xml has:
>
> <!-- create a camel context as to start Camel -->
> <camelContext id="camel" xmlns="http://camel.apache.org/schema/spring">
> <package>package.has.routebuilderl</package>
> </camelContext>
> <bean id="servlet" class="org.apache.camel.component.http.HttpComponent">
> <property name="camelContext" ref="camel" />
> </bean>
>
>
I figure that I should not have a HttpComponent for servlet scheme because
HttpComponent is only for output data. Then what component I should set for
servlet. If I delete HttpComponent part, Tomat has error.
SEVERE: Context initialization failed
org.apache.camel.ResolveEndpointFailedException: Failed to resolve endpoint:
servlet:///hello due to: No component found with scheme: servlet
at
org.apache.camel.impl.DefaultCamelContext.getEndpoint(DefaultCamelContext.java:411)
--
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