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Posted to notifications@apisix.apache.org by GitBox <gi...@apache.org> on 2022/09/27 09:55:04 UTC

[GitHub] [apisix] tokers commented on issue #7993: feat: As a user, I want to 用网关的jwt做sso , so that 需要jwt校验失败可以返回更多的信息

tokers commented on issue #7993:
URL: https://github.com/apache/apisix/issues/7993#issuecomment-1259266173

   Currently, it's not feasible. You may use the plugin metadata to inject a custom error response but it cannot inject the URL right now.
   
   See https://apisix.apache.org/docs/apisix/terminology/plugin/#plugin-common-configuration.
   


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