[jira] Updated: (OPENJPA-236) No apparent way to generate all required SQL within a class derived from FullClassStrategy

["David Ezzio (JIRA)" <ji...@apache.org>]

     [ https://issues.apache.org/jira/browse/OPENJPA-236?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel ]

David Ezzio updated OPENJPA-236:
--------------------------------

    Attachment: OpenJPACustomSQL.zip

A test case that can be used to explore the issues raised here.

> No apparent way to generate all required SQL within a class derived from FullClassStrategy
> ------------------------------------------------------------------------------------------
>
>                 Key: OPENJPA-236
>                 URL: https://issues.apache.org/jira/browse/OPENJPA-236
>             Project: OpenJPA
>          Issue Type: New Feature
>          Components: kernel
>    Affects Versions: 0.9.7
>            Reporter: David Ezzio
>         Attachments: OpenJPABugCustomSQL.zip, OpenJPACustomSQL.zip
>
>
> FullClassStrategy has several optional methods for overriding OpenJPA's generation of SQL. However, in a simple case, there is no apparent way to generate the required SQL within a class derived from FullClassStrategy.
> The model consists of two classes, BizA which has a one-way, one-to-many relationship to BizB. The relationship is mapped with a FK within the BizB table.
> The custom class strategy BizBMapping attempts to insert a BizB record and is able to do so, provided that it is not contained within a BizA collection. Otherwise, the attempt to persist a BizA with a contained BizB yields a SQL exception because OpenJPA generates additional SQL that conflicts with the SQL generated within BizBMapping.customInsert. Even if OpenJPA did not generate conflicting insert statement, there is no apparent way to get the value for the A_ID column within the BizBMapping.customInsert method.
> This issue is critical for users who want to substitute their own SQL (such as calls to stored procedures) for all of the OpenJPA generated SQL.
> Synopsis of the output log:
> INSERT INTO BIZB (ID, INFO) VALUES (?, ?) [params=(String) B22047141, (String) random]
> INSERT INTO BizA (id, info) VALUES (?, ?) [params=(String) A32968849, (String) random]
> INSERT INTO BizB (A_ID) VALUES (?) [params=(String) A32968849]
> SQLException: Column 'ID'  cannot accept a NULL value. 

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