Table style

[Miguel Tablado <mi...@gmail.com>]

Hi all;

I need to create a style for tr elements that it paints tr backgrounds on
different colors depending on its positions.

I mean, I need tables with n+1 and n+2 rows with blank background and n+3
and n+4 rows with grey one.

I have found it for css, but it doesn't work in all browsers.

table tr:nth-child(2+4n) { background-color: #F0F0F0}
table tr:nth-child(3+4n) { background-color: #F0F0F0}

Thanks, 
Miguel Tablado
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Re: Table style

[Andreas Delmelle <an...@telenet.be>]

On 12 Nov 2008, at 10:05, Miguel Tablado wrote:

Hi

> I need to create a style for tr elements that it paints tr  
> backgrounds on
> different colors depending on its positions.

On the one hand, this is problematic, since there is no mechanism in  
XSL-FO that allows you to do that, but...

There is a chance this can be done in XSLT, since depending on the  
data, it may be possible to vary the table-row's background-color  
according to the position of the nodes in the source tree.

Say, if you have <datarow> elements, and each of those generates a  
separate table-row, you could do something like:

<for-each select="datarow">
   <fo:table-row>
     <xsl:attribute name="background-color">
       <xsl:variable name="checkpos" select="position() mod 4" />
       <xsl:choose>
         <!-- grey background for cells n+3 and n+4 -->
         <xsl:when test="(checkpos = 0) or (checkpos = 3)">#F0F0F0</ 
xsl:when>
         <!-- white background otherwise -->
         <xsl:otherwise>#FFFFFF</xsl:otherwise>
       </xsl:choose>
     </xsl:attribute>
     <!-- rest of processing -->
   </fo:table-row>
</xsl:for-each>


HTH!

Cheers

Andreas

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