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Posted to user@commons.apache.org by pedro Cristian <pe...@yahoo.fr> on 2005/04/29 13:59:36 UTC

[JXPath] deprecated doc 

I was just looking at the JXPath documentation.

http://jakarta.apache.org/commons/jxpath/users-guide.html

The user guide recommends using the XMLContainer

"An example of a useful container is XMLDocumentContainer  . When you create an
XMLDocumentContainer, you give it a pointer to an XML file (a URL or a
javax.xml.transform.Source)."

However, this class is deprecated.

http://jakarta.apache.org/commons/jxpath/apidocs/org/apache/commons/jxpath/XMLDocumentContainer.html

So if someone wants to evaluate an XPath on an XML flow what is the recommended
solution? Use this deprecated class using a SAX source, or use another XPath
capable library like Jaxen?

Is it a misunderstanding of the aim of JXPath (more centered on accessing java
objects and xml file in the classfile or accessed thru an url)?


Pedro


	

	
		
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Re: [JXPath] deprecated doc

Posted by Pedro Cristian <pe...@yahoo.fr>.
 --- Dmitri Plotnikov <dm...@plotnix.com> a écrit : 
> Pedro,
> 
> The class is now called simply DocumentContainer.
> 
> I will update the documentation when I get a chance.
> 
> Thank you,
However DocumentContainer does not have a constructor with a Source. Just with
an URL. Or is there a way that I don't know in order to transform an internal
String into an URL (without using a File)?

Pedro




	

	
		
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Re: [JXPath] deprecated doc

Posted by Dmitri Plotnikov <dm...@plotnix.com>.
Pedro,

The class is now called simply DocumentContainer.

I will update the documentation when I get a chance.

Thank you,

- Dmitri


----- Original Message ----- 
From: "pedro Cristian" <pe...@yahoo.fr>
To: <co...@jakarta.apache.org>
Sent: Friday, April 29, 2005 7:59 AM
Subject: [JXPath] deprecated doc


>I was just looking at the JXPath documentation.
>
> http://jakarta.apache.org/commons/jxpath/users-guide.html
>
> The user guide recommends using the XMLContainer
>
> "An example of a useful container is XMLDocumentContainer  . When you 
> create an
> XMLDocumentContainer, you give it a pointer to an XML file (a URL or a
> javax.xml.transform.Source)."
>
> However, this class is deprecated.
>
> http://jakarta.apache.org/commons/jxpath/apidocs/org/apache/commons/jxpath/XMLDocumentContainer.html
>
> So if someone wants to evaluate an XPath on an XML flow what is the 
> recommended
> solution? Use this deprecated class using a SAX source, or use another 
> XPath
> capable library like Jaxen?
>
> Is it a misunderstanding of the aim of JXPath (more centered on accessing 
> java
> objects and xml file in the classfile or accessed thru an url)?
>
>
> Pedro
>
>
>
>
>
>
> __________________________________________________________________
> Découvrez le nouveau Yahoo! Mail : 250 Mo d'espace de stockage pour vos 
> mails !
> Créez votre Yahoo! Mail sur http://fr.mail.yahoo.com/
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: commons-user-unsubscribe@jakarta.apache.org
> For additional commands, e-mail: commons-user-help@jakarta.apache.org
>
>
>
> 



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