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Posted to issues@spark.apache.org by "Mithun Radhakrishnan (Jira)" <ji...@apache.org> on 2020/06/19 23:45:00 UTC

[jira] [Created] (SPARK-32038) Regression in handling NaN values in COUNT(DISTINCT)

Mithun Radhakrishnan created SPARK-32038:
--------------------------------------------

             Summary: Regression in handling NaN values in COUNT(DISTINCT)
                 Key: SPARK-32038
                 URL: https://issues.apache.org/jira/browse/SPARK-32038
             Project: Spark
          Issue Type: Bug
          Components: Optimizer, SQL
    Affects Versions: 3.0.0
            Reporter: Mithun Radhakrishnan


There seems to be a regression in Spark 3.0.0, with regard to how {{NaN}} values are normalized/handled in {{COUNT(DISTINCT ...)}}. Here is an illustration:
{code:scala}
case class Test( uid:String, score:Float)

val POS_NAN_1 = java.lang.Float.intBitsToFloat(0x7f800001)
val POS_NAN_2 = java.lang.Float.intBitsToFloat(0x7fffffff)

val rows = Seq(

 Test("mithunr",  Float.NaN),	
 Test("mithunr",  POS_NAN_1),
 Test("mithunr",  POS_NAN_2),
 Test("abellina", 1.0f),
 Test("abellina", 2.0f)

).toDF.createOrReplaceTempView("mytable")

spark.sql(" select uid, count(distinct score) from mytable group by 1 order by 1 asc ").show
{code}

Here are the results under Spark 3.0.0:
{code:title=Spark 3.0.0 (single aggregation)}
+--------+---------------------+
|     uid|count(DISTINCT score)|
+--------+---------------------+
|abellina|                    2|
| mithunr|                    3|
+--------+---------------------+
{code}

Note that the count against {{mithunr}} is {{3}}, accounting for each distinct value for {{NaN}}.
The right results are returned when another aggregation is added to the GBY:
{code:scala|title=Spark 3.0.0 (multiple aggregations)}
scala> spark.sql(" select uid, count(distinct score), max(score) from mytable group by 1 order by 1 asc ").show
+--------+---------------------+----------+
|     uid|count(DISTINCT score)|max(score)|
+--------+---------------------+----------+
|abellina|                    2|       2.0|
| mithunr|                    1|       NaN|
+--------+---------------------+----------+
{code}

Also, note that Spark 2.4.6 normalizes the `DISTINCT` expression correctly:
{code:scala|title=Spark 2.4.6}
scala> spark.sql(" select uid, count(distinct score)             from mytable group by 1 order by 1 asc ").show

+--------+---------------------+
|     uid|count(DISTINCT score)|
+--------+---------------------+
|abellina|                    2|
| mithunr|                    1|
+--------+---------------------+
{code}



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