jsessionid in URL results in RequestExceptionHandler

[Leon Derks <le...@aurumeurope.com>]

Hello

Every once in a while I get the error below after logging in. The jsessionid is then visible in my url.
I don't understand why this happens and why this occurs sometimes. 

Does somebody of you know what is going wrong and what I can do to solve this?

regards,
Leon

ERROR org.apache.tapestry5.services.TapestryModule.RequestExceptionHandler-63 - Processing of request failed with uncaught exception: Input string 'login;jsessionid=76D07FFDD475963D6909F85947390F7A' is not valid; the character ';' at position 6 is not valid.
java.lang.IllegalArgumentException: Input string 'login;jsessionid=76D07FFDD475963D6909F85947390F7A' is not valid; the character ';' at position 6 is not valid.
	at org.apache.tapestry5.internal.services.URLEncoderImpl.decode(URLEncoderImpl.java:144)
	at $URLEncoder_1332c6935b7.decode($URLEncoder_1332c6935b7.java)
	at org.apache.tapestry5.internal.services.ContextPathEncoderImpl.decodePath(ContextPathEncoderImpl.java:92)
	at $ContextPathEncoder_1332c6935ab.decodePath($ContextPathEncoder_1332c6935ab.java)
	at org.apache.tapestry5.internal.services.ComponentEventLinkEncoderImpl.checkIfPage(ComponentEventLinkEncoderImpl.java:328)
	at org.apache.tapestry5.internal.services.ComponentEventLinkEncoderImpl.decodePageRenderRequest(ComponentEventLinkEncoderImpl.java:320)
	at org.apache.tapestry5.internal.services.linktransform.LinkTransformerInterceptor.decodePageRenderRequest(LinkTransformerInterceptor.java:68)
	at $ComponentEventLinkEncoder_1332c69359d.decodePageRenderRequest($ComponentEventLinkEncoder_1332c69359d.java)


---------------------------------------------------------------------
To unsubscribe, e-mail: users-unsubscribe@tapestry.apache.org
For additional commands, e-mail: users-help@tapestry.apache.org