Namespaces and preprocessing LotusXSL to Xalan

[Peet Sneekes <pe...@mediamatic.nl>]

Hi,

There's one problem I could not solve while converting from LotusXSL to
Xalan.
I use the Xalan processor to make a  XSL file(3) from a XSL(1) and a XML(2)
(two DOM's).
This preprocessed XSL file(3) is used to convert a XML(4) into a HTML(5).
To ensure that the XSL-namespace of the second round is NOT transformed or
interpreted
in the first round, I made the following constuction in the first XSL(1):

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                xmlns:xsl2="quote:http://www.w3.org/1999/XSL/Transform"
                xmlns="http://www.w3.org/TR/REC-html40">

Please notice the 'quote' part in the XSL2 namespace definition, this is
stripped in the first round, leaving the following namespace definition in
the preprocessed XSL(3):

<xsl:stylesheet xmlns:xsl2="http://www.w3.org/1999/XSL/Transform"
                xmlns="http://www.w3.org/TR/REC-html40">

Now the problem:
I can't convice Xalan to do the same thing as LotusXSL did for me before:
I use the folowing code:

  XSLTInputSource  i  = new XSLTInputSource(content);
  XSLTInputSource  s  = new XSLTInputSource(stylesheet);
  Document      out = new DocumentImpl();
  XSLTResultTarget o  = new XSLTResultTarget(out);

  org.apache.xalan.xpath.xml.XMLParserLiaisonDefault xmlParserLiaison = new
XMLParserLiaisonDefault();
  xmlParserLiaison.setProcessNamespaces(true);
  xmlParserLiaison.setUseValidation(true);
  XSLTProcessor processor =
XSLTProcessorFactory.getProcessor(xmlParserLiaison);
  processor.setProblemListener(pl);
  processor.process(i, s, o);


Anyways, can anyone give me a hint?

Thanks,

Peet