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Posted to issues@calcite.apache.org by "Julian Hyde (JIRA)" <ji...@apache.org> on 2018/11/27 23:44:00 UTC

[jira] [Commented] (CALCITE-2712) Add rule to remove null-generating side of a Join

    [ https://issues.apache.org/jira/browse/CALCITE-2712?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=16701177#comment-16701177 ] 

Julian Hyde commented on CALCITE-2712:
--------------------------------------

cc [~swtalbot]

> Add rule to remove null-generating side of a Join
> -------------------------------------------------
>
>                 Key: CALCITE-2712
>                 URL: https://issues.apache.org/jira/browse/CALCITE-2712
>             Project: Calcite
>          Issue Type: Bug
>            Reporter: Julian Hyde
>            Assignee: Julian Hyde
>            Priority: Major
>
> Add a rule to remove the null-generating side of a Join. Here is an example  where we eliminate the "many" side of a "one-to-many" join:
> {code:sql}
> # Example 1: one-to-many
> SELECT c.id, COUNT(DISTINCT o.productId)
> FROM Customers AS c
> LEFT JOIN SupportCalls AS s ON c.id = s.customerId
> LEFT JOIN Orders AS o ON c.id = o.customerId{code}
> We can remove {{SupportCalls}} and the join to it, so the query becomes
> {code:sql}
> SELECT c.id, COUNT(DISTINCT o.productId)
> FROM Customers AS c
> LEFT JOIN Orders AS o ON c.id = o.customerId{code}
> Necessary conditions are:
> # no columns from {{SupportCalls}} are used
> # the join is LEFT, so customers will not be eliminated if they have no support calls,
> # there is an Aggregate on top, so we don't care if there are >1 support call per customer.
> A simpler example of one-to-many:
> {code:sql}
> # Example 2: simpler one-to-many
> SELECT DISTINCT c.id
> FROM Customers AS c
> LEFT JOIN SupportCalls AS s ON c.id = s.customerId{code}
> An example of many-to-one, where we eliminate the "one" side ({{Orders}}):
> {code:sql}
> # Example 3: many-to-one
> SELECT c.id, p.color
> FROM LineItems AS i
> LEFT JOIN Orders AS o ON o.id = i.orderId
> LEFT JOIN Products AS p ON p.id = i.orderId{code}
> so that the query becomes
> {code:sql}
> SELECT c.id, p.color
> FROM LineItems AS i
> LEFT JOIN Products AS p ON p.id = i.orderId{code}
> Here, necessary side-conditions are:
> # no columns from {{Orders}} are used;
> # unique key on {{Orders.id}}.
> We do not require aggregation, because the primary key on {{Orders.id}} ensures that {{Orders}} contributes at most one row.
> We can deal with similar cases like
> {code:sql}
> # Example 4: many-to-one, column aliasing required
> SELECT c.id, p.color
> FROM LineItems AS i
> LEFT JOIN Orders AS o ON o.id = i.orderId
> LEFT JOIN Products AS p ON p.id = o.id{code}
> if we use aliasing ({{o.id}} = {{i.orderId}}) and a foreign key that ensures the existence of an record in {{Orders}}.
> For examples 1 and 2 (one-to-many), we would need to match {{Aggregate}} on {{Join}}, therefore make a variant of {{AggregateJoinTransposeRule}}.
> For examples 3 and 4 (many-to-one or one-to-one)), we would match {{Project}} on {{Join}}, therefore make a variant of {{ProjectJoinTransposeRule}}.



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