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Posted to user@jmeter.apache.org by "Chen, Song" <ch...@amazon.com> on 2007/04/13 16:19:46 UTC
the throughput
Hi all
Anyone knows how the throughput is caculated?
I have current aggregate report said:
samples: 4025
Throughput: 56.2
The test uses a "duration (seconds)" of 120?
Who knows how to get the Throughput?
4025/120=33.5
Thanks
Chen Song
答复: the throughput
Posted by "Chen, Song" <ch...@amazon.com>.
it is quite a simple test plan, with only one thread group.
number of threads : 5
ramp-up period : 0
loop: for ever
scheduler: checked
start time and end time: not empty, but 2007/3/12....so so
Duration: 120
startup delay: 1
what other else can effect the samples count or time?
Thanks
Chen Song
-----邮件原件-----
发件人: sebb [mailto:sebbaz@gmail.com]
发送时间: 2007年4月14日 1:05
收件人: JMeter Users List
主题: Re: the throughput
On 13/04/07, Chen, Song <ch...@amazon.com> wrote:
> then in this case
> the start time 07:12:49.324
> the end time 07:14:00:916...
>
> then its strange, why i set duration 120, but this only runs about only 70 seconds?
>
Because the samplers only took 70 seconds?
Without further detail on the test plan, one can only guess - but please don't post the full JMX file to the list!
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答复: the throughput
Posted by "Chen, Song" <ch...@amazon.com>.
Hi Sebb, i found the reason.
in jmeter.log a error message
ERROR - jmeter.threads.JMeterThread: Test failed! java.lang.OutOfMemoryError: Java heap space
then all threads ended one by one.
what's the possible reason of this?
Thanks
Chen Song
-----邮件原件-----
发件人: sebb [mailto:sebbaz@gmail.com]
发送时间: 2007年4月14日 1:05
收件人: JMeter Users List
主题: Re: the throughput
On 13/04/07, Chen, Song <ch...@amazon.com> wrote:
> then in this case
> the start time 07:12:49.324
> the end time 07:14:00:916...
>
> then its strange, why i set duration 120, but this only runs about only 70 seconds?
>
Because the samplers only took 70 seconds?
Without further detail on the test plan, one can only guess - but please don't post the full JMX file to the list!
---------------------------------------------------------------------
To unsubscribe, e-mail: jmeter-user-unsubscribe@jakarta.apache.org
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For additional commands, e-mail: jmeter-user-help@jakarta.apache.org
Re: the throughput
Posted by sebb <se...@gmail.com>.
On 13/04/07, Chen, Song <ch...@amazon.com> wrote:
> then in this case
> the start time 07:12:49.324
> the end time 07:14:00:916...
>
> then its strange, why i set duration 120, but this only runs about only 70 seconds?
>
Because the samplers only took 70 seconds?
Without further detail on the test plan, one can only guess - but
please don't post the full JMX file to the list!
---------------------------------------------------------------------
To unsubscribe, e-mail: jmeter-user-unsubscribe@jakarta.apache.org
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答复: the throughput
Posted by "Chen, Song" <ch...@amazon.com>.
then in this case
the start time 07:12:49.324
the end time 07:14:00:916...
then its strange, why i set duration 120, but this only runs about only 70 seconds?
Thanks
Chen Song
-----邮件原件-----
发件人: sebb [mailto:sebbaz@gmail.com]
发送时间: 2007年4月13日 22:37
收件人: JMeter Users List
主题: Re: the throughput
Throughput = (sample count)/(elapsed time)
Elapsed time=end-time - start-time
This is not necessarily the same as the test duration.
On 13/04/07, Chen, Song <ch...@amazon.com> wrote:
> Hi all
> Anyone knows how the throughput is caculated?
>
> I have current aggregate report said:
> samples: 4025
> Throughput: 56.2
>
> The test uses a "duration (seconds)" of 120?
>
> Who knows how to get the Throughput?
>
> 4025/120=33.5
>
> Thanks
>
> Chen Song
>
>
>
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For additional commands, e-mail: jmeter-user-help@jakarta.apache.org
---------------------------------------------------------------------
To unsubscribe, e-mail: jmeter-user-unsubscribe@jakarta.apache.org
For additional commands, e-mail: jmeter-user-help@jakarta.apache.org
Re: the throughput
Posted by sebb <se...@gmail.com>.
Throughput = (sample count)/(elapsed time)
Elapsed time=end-time - start-time
This is not necessarily the same as the test duration.
On 13/04/07, Chen, Song <ch...@amazon.com> wrote:
> Hi all
> Anyone knows how the throughput is caculated?
>
> I have current aggregate report said:
> samples: 4025
> Throughput: 56.2
>
> The test uses a "duration (seconds)" of 120?
>
> Who knows how to get the Throughput?
>
> 4025/120=33.5
>
> Thanks
>
> Chen Song
>
>
>
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