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Posted to java-user@axis.apache.org by Srisathya Thirumalai <ts...@hotmail.com> on 2008/09/27 09:33:10 UTC
Get XML REquest File
Hello,
How do I get the XML version of the request the client is sending to the web service? The client is using Axis 2.
Thanks
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RE: Get XML REquest File
Posted by Srisathya Thirumalai <ts...@hotmail.com>.
Thanks Martin. That logging tips worked for me.
From: mgainty@hotmail.comTo: axis-user@ws.apache.orgSubject: RE: Get XML REquest FileDate: Sat, 27 Sep 2008 18:38:32 -0400
configure Log4j to use ConsoleAppender ### direct log messages to stdout ###log4j.appender.stdout=org.apache.log4j.ConsoleAppenderlog4j.appender.stdout.Target=System.outlog4j.appender.stdout.layout=org.apache.log4j.PatternLayoutlog4j.appender.stdout.layout.ConversionPattern=%d{ABSOLUTE} %5p %c{1}:%L - %m%nlog4j.rootLogger=debug, stdoutimport org.apache.log4j.Logger;... private static org.apache.log4j.Logger log = Logger .getLogger(YourClassNameGoesHere.class);and when use you call log.debug("foo");you will see the debug statements on screendocumentation is available athttp://www.onjava.com/pub/a/onjava/2002/08/07/log4j.html?page=3you can also use Log4J Category as in this example..static Category cat = Category.getInstance(YOURClassNameGoesHere.class.getName());//now test the various debugging capabilities of the logger as explained herecat.info("Just testing a log message with priority set to INFO");cat.warn("Just testing a log message with priority set to WARN");cat.error("Just testing a log message with priority set to ERROR");cat.fatal("Just testing a log message with priority set to FATAL")HTHMartin ______________________________________________ Disclaimer and confidentiality note Everything in this e-mail and any attachments relates to the official business of Sender. This transmission is of a confidential nature and Sender does not endorse distribution to any party other than intended recipient. Sender does not necessarily endorse content contained within this transmission.
From: tsathya@hotmail.comTo: axis-user@ws.apache.orgSubject: RE: Get XML REquest FileDate: Sat, 27 Sep 2008 18:17:39 -0400
I am using Axis2 as the client. The server is not controlled by me. I want to spit the XML request I am sending to the server. Can you please tell me how to do that? (My request fails and the server person wants me to send the request XML to him so he can see what went wrong? )Thanks for replying!> Date: Sat, 27 Sep 2008 09:22:30 -0400> From: deepal@opensource.lk> To: axis-user@ws.apache.org> Subject: Re: Get XML REquest File> > > > Hello,> > How do I get the XML version of the request the client is sending to> > the web service? The client is using Axis 2.> If you are using Axis2 as the server , then you can write your service> using Axiom. Then you can get the XML as the input parameter. With this> your service would look like,> > public class MyService {> > public void doFoo(OMElement parameter){> // do your service logic here> }> > }> > > Thank you!> > > http://blogs.deepal.org> > > ---------------------------------------------------------------------> To unsubscribe, e-mail: axis-user-unsubscribe@ws.apache.org> For additional commands, e-mail: axis-user-help@ws.apache.org>
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RE: Get XML REquest File
Posted by Martin Gainty <mg...@hotmail.com>.
configure Log4j to use ConsoleAppender
### direct log messages to stdout ###
log4j.appender.stdout=org.apache.log4j.ConsoleAppender
log4j.appender.stdout.Target=System.out
log4j.appender.stdout.layout=org.apache.log4j.PatternLayout
log4j.appender.stdout.layout.ConversionPattern=%d{ABSOLUTE} %5p %c{1}:%L - %m%n
log4j.rootLogger=debug, stdoutimport org.apache.log4j.Logger;
...
private static org.apache.log4j.Logger log = Logger
.getLogger(YourClassNameGoesHere.class);
and when use you call log.debug("foo");
you will see the debug statements on screen
documentation is available at
http://www.onjava.com/pub/a/onjava/2002/08/07/log4j.html?page=3
you can also use Log4J Category as in this example..
static Category cat = Category.getInstance(YOURClassNameGoesHere.class.getName());
//now test the various debugging capabilities of the logger as explained here
cat.info("Just testing a log message with priority set to INFO");
cat.warn("Just testing a log message with priority set to WARN");
cat.error("Just testing a log message with priority set to ERROR");
cat.fatal("Just testing a log message with priority set to FATAL")HTH
Martin
______________________________________________
Disclaimer and confidentiality note
Everything in this e-mail and any attachments relates to the official business of Sender. This transmission is of a confidential nature and Sender does not endorse distribution to any party other than intended recipient. Sender does not necessarily endorse content contained within this transmission.
From: tsathya@hotmail.com
To: axis-user@ws.apache.org
Subject: RE: Get XML REquest File
Date: Sat, 27 Sep 2008 18:17:39 -0400
I am using Axis2 as the client. The server is not controlled by me. I want to spit the XML request I am sending to the server. Can you please tell me how to do that?
(My request fails and the server person wants me to send the request XML to him so he can see what went wrong? )
Thanks for replying!
> Date: Sat, 27 Sep 2008 09:22:30 -0400
> From: deepal@opensource.lk
> To: axis-user@ws.apache.org
> Subject: Re: Get XML REquest File
>
>
> > Hello,
> > How do I get the XML version of the request the client is sending to
> > the web service? The client is using Axis 2.
> If you are using Axis2 as the server , then you can write your service
> using Axiom. Then you can get the XML as the input parameter. With this
> your service would look like,
>
> public class MyService {
>
> public void doFoo(OMElement parameter){
> // do your service logic here
> }
>
> }
> >
> Thank you!
>
>
> http://blogs.deepal.org
>
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: axis-user-unsubscribe@ws.apache.org
> For additional commands, e-mail: axis-user-help@ws.apache.org
>
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Re: Get XML REquest File
Posted by Nan Null <nu...@gmail.com>.
Lookup TCP monitor included with Axis library. This is how it works:
Client ------> TCP Monitor ------> Server
The TCP monitor will display all the messages back and forth.
On Sat, Sep 27, 2008 at 6:17 PM, Srisathya Thirumalai
<ts...@hotmail.com> wrote:
> I am using Axis2 as the client. The server is not controlled by me. I want
> to spit the XML request I am sending to the server. Can you please tell me
> how to do that?
>
> (My request fails and the server person wants me to send the request XML to
> him so he can see what went wrong? )
>
> Thanks for replying!
>
>
>
>> Date: Sat, 27 Sep 2008 09:22:30 -0400
>> From: deepal@opensource.lk
>> To: axis-user@ws.apache.org
>> Subject: Re: Get XML REquest File
>>
>>
>> > Hello,
>> > How do I get the XML version of the request the client is sending to
>> > the web service? The client is using Axis 2.
>> If you are using Axis2 as the server , then you can write your service
>> using Axiom. Then you can get the XML as the input parameter. With this
>> your service would look like,
>>
>> public class MyService {
>>
>> public void doFoo(OMElement parameter){
>> // do your service logic here
>> }
>>
>> }
>> >
>> Thank you!
>>
>>
>> http://blogs.deepal.org
>>
>>
>> ---------------------------------------------------------------------
>> To unsubscribe, e-mail: axis-user-unsubscribe@ws.apache.org
>> For additional commands, e-mail: axis-user-help@ws.apache.org
>>
>
>
> ________________________________
> See how Windows Mobile brings your life together—at home, work, or on the
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RE: Get XML REquest File
Posted by Srisathya Thirumalai <ts...@hotmail.com>.
I am using Axis2 as the client. The server is not controlled by me. I want to spit the XML request I am sending to the server. Can you please tell me how to do that?
(My request fails and the server person wants me to send the request XML to him so he can see what went wrong? )
Thanks for replying!> Date: Sat, 27 Sep 2008 09:22:30 -0400> From: deepal@opensource.lk> To: axis-user@ws.apache.org> Subject: Re: Get XML REquest File> > > > Hello,> > How do I get the XML version of the request the client is sending to> > the web service? The client is using Axis 2.> If you are using Axis2 as the server , then you can write your service> using Axiom. Then you can get the XML as the input parameter. With this> your service would look like,> > public class MyService {> > public void doFoo(OMElement parameter){> // do your service logic here> }> > }> > > Thank you!> > > http://blogs.deepal.org> > > ---------------------------------------------------------------------> To unsubscribe, e-mail: axis-user-unsubscribe@ws.apache.org> For additional commands, e-mail: axis-user-help@ws.apache.org>
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Re: Get XML REquest File
Posted by Deepal Jayasinghe <de...@opensource.lk>.
> Hello,
> How do I get the XML version of the request the client is sending to
> the web service? The client is using Axis 2.
If you are using Axis2 as the server , then you can write your service
using Axiom. Then you can get the XML as the input parameter. With this
your service would look like,
public class MyService {
public void doFoo(OMElement parameter){
// do your service logic here
}
}
>
Thank you!
http://blogs.deepal.org
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To unsubscribe, e-mail: axis-user-unsubscribe@ws.apache.org
For additional commands, e-mail: axis-user-help@ws.apache.org