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Posted to users@tomcat.apache.org by "Anil Goyal -X (anigoyal - Aricent Technologies at Cisco)" <an...@cisco.com> on 2013/02/07 14:03:42 UTC
deploy application in new service in tomcat
Hi,
I am creating a new service in tomcat (7.0.20) with service name 'catalina_new' and appBase='webapps' by doing some changes in server.xml.
I am keeping the appBase same as that for default service 'catalina'
I have several applications deployed under webapps.
I want only a single application with context '/feeder' to be accesible through new service.
Condition: I do not want to have a separate appBase for new service and deployed only the required app under this new appBase.
In short, do we have a context based filtering in tomcat so that tomcat incorporate request only from a specific context path and ignore all others
Thanks
Anil
Re: deploy application in new service in tomcat
Posted by Pid <pi...@pidster.com>.
On 07/02/2013 13:03, Anil Goyal -X (anigoyal - Aricent Technologies at
Cisco) wrote:
> Hi,
>
> I am creating a new service in tomcat (7.0.20) with service name 'catalina_new' and appBase='webapps' by doing some changes in server.xml.
> I am keeping the appBase same as that for default service 'catalina'
Why?
A side effect will be that all apps in webapps are deployed to both
services. This is because you've told Tomcat to do that.
What do you gain by having the same appBase?
> I have several applications deployed under webapps.
> I want only a single application with context '/feeder' to be accesible through new service.
>
> Condition: I do not want to have a separate appBase for new service and deployed only the required app under this new appBase.
Why not?
Why have you invented a spurious and unnecessary condition like this?
> In short, do we have a context based filtering in tomcat so that tomcat incorporate request only from a specific context path and ignore all others
No.
p
> Thanks
> Anil
>
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Re: deploy application in new service in tomcat
Posted by André Warnier <aw...@ice-sa.com>.
Anil Goyal -X (anigoyal - Aricent Technologies at Cisco) wrote:
> Hi.
> On this list, the convention is to not "top post".
> Put your answers either in-line, in the text, or at the end.
> That is much easier for others to follow the conversation in a logical order.
>
> Anil Goyal -X (anigoyal - Aricent Technologies at Cisco) wrote:
>> Thanks for the reply Andre.....
>>
>> Let me explain you in detail.
>> Let's suppose we have two applications App1.war and App2.war, deployed in webapps of tomcat.
>> Now I want only App2 to listen additionally on a separate connector port(lets suppose 8181) along with port 8080 to which it is already listen.
>> But I want App1 to listen only on port 8080 not on port 8181.
>>
>> So what I did, I create a new service in tomcat with name 'catalina_new' and appBase='webapps_new' and I add a connector port 8181 in this.
>> Now I deploy my App2.war in webapps_new.
>> So after restart the tomcat, I am able to make App2 to listen on port 8080 as well as port 8181(since App2.war is present in both webapps and webapps_new), and App1 is listen on only port 8080.
>> Till now, everything was fine.
>>
>> Now I do not want to have a separate appBase for service
>> 'catalina_new', means I want appBase='webapps' for service 'catalina_new' as well So by doing this change, my App1 also starts listen on port 8181 which is not required.
>> So what can I do to make only App2 to listen on new port under new service with 'appBase=webapps'
>>
>> Hope you understand my query now!
>>
>
> I do understand, approximately. But honestly, your way of thinking about this is different from mine, and I have some trouble following your idea.
> This may also be because my knowledge of the inner workings of Tomcat is limited, and I am not even sure that what you are currently doing is even supposed to work.
>
> In my understanding, what is "listening" on a given port is not a webapp, it is Tomcat.
> Tomcat accepts a connection on one of the ports that it is listening to, through one of the Connector elements of that Tomcat.
> (Until now, the webapps are not involved at all) Then Tomcat allocates this connection to a Thread, to process the HTTP request which has been written by the client to that connection.
> Then the Thread reads the HTTP request line sent by the client, and the HTTP request header lines.
> (Until now, the webapps are not involved at all) Then the Thread reads the "Host:" header line in that request, and determines to which <Host> this request is addressed. Then the Thread loads the appropriate configuration for that <Host>, before processing the request any further.
> (Until now, the webapps are still not involved at all)
> *Now* the Thread knows that for this <Host>, the active applications are located somewhere, and it knows to which "context path" each application should be answering.
> So *now* the Thread can call the appropriate webapp and give it the incoming request to process.
> So *now* one of the active webapps is involved.
> And at this point, it could be any webapp that is active within that <Host>.
>
> What I am trying to say, is that the selection of the port on which a request comes in is not controlled by the webapp, and cannot be. It is done much earlier in the cycle, and depends only on to which port the client connects and sends his request on.
> At the moment Tomcat accepts such a request, it does not know yet neither the <Host>, nor the webapp within the <Host>, which this client wants. And it cannot at that point decide to accept or refuse this request depending on which webapp it will ultimately go to, because it does not know that yet.
>
> I must confess that I do not really know if your idea of doing this by having 2 <Service> elements in Tomcat may or may not provide a way to overcome this.
> But to me, at this point, the idea seems a bit strange.
>
> To say the truth, I don't even know if your basic idea to restrict the access to a webapp based on which port the request comes in, makes really sense for what your basic issue is.
> But if that is really the issue, then I would do this on the base of a servlet filter configured for that webapp.
> You could probably use the urlrewrite filter (http://tuckey.org/urlrewrite/) for that, which would be much easier than your current setup.
>
>> The flow that you explain is absolutely fine and even I have the same flow in my mind as well.
>
> As you know there is one param 'deployIgnore' in Host Configuration. Can't we use that one for that.
> As I already explained you earlier that the case is regarding the two services in tomcat pointing to same appBase. If we add connector port lets suppose 8080 in service 1 and 8181 in service 2 then what will happen if I hit the url
> http://ip-address:8080/App1
> http://ip-address:8080/App2
> http://ip-address:8181/App1
> http://ip-address:8181/App2
>
> It will give 200 Ok response in all the cases .
>
> Now what if with port 8181, I want to access App1 only means now what I want is
> http://ip-address:8080/App1 should be 200OK
>
> http://ip-address:8080/App2 should be 200OK
>
> http://ip-address:8181/App1 should be 200OK
>
> http://ip-address:8181/App2 should be 404 Error
>
> To achieve this, what I want to do in server.xml of tomcat.
> How can I achieve that App1 should be accessible from both the ports 8080 and 8181, App2 should be accessible from 8080 not 8181.
>
> I think we can add deployIgnore="App2" in Host configuration of new service in server.xml to make App2 not accessible at new port 8181
> What you suggest??
>
>
I will repeat what I said before : I think the way that you are thinking about this (with
the second <Service>) is too complicated, and may trigger side-effects that you do not expect.
What I would do is :
- use a normal Tomcat installation, with one Service etc..
- deploy your webapp1 and webapp2 applications normally
- however, in webapp2, add a servlet filter (urlrewritefilter), and in that filter you
/can/ test on which port the request came in, and then return a 404 error if it is not the
port that you want.
The additional advantage is that this kind of setup is totally standard for a java servlet
container, and servlet filters are standard for all servlet containers. So this
configuration would be totally portable.
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RE: deploy application in new service in tomcat
Posted by "Anil Goyal -X (anigoyal - Aricent Technologies at Cisco)" <an...@cisco.com>.
Hi.
On this list, the convention is to not "top post".
Put your answers either in-line, in the text, or at the end.
That is much easier for others to follow the conversation in a logical order.
Anil Goyal -X (anigoyal - Aricent Technologies at Cisco) wrote:
> Thanks for the reply Andre.....
>
> Let me explain you in detail.
> Let's suppose we have two applications App1.war and App2.war, deployed in webapps of tomcat.
> Now I want only App2 to listen additionally on a separate connector port(lets suppose 8181) along with port 8080 to which it is already listen.
> But I want App1 to listen only on port 8080 not on port 8181.
>
> So what I did, I create a new service in tomcat with name 'catalina_new' and appBase='webapps_new' and I add a connector port 8181 in this.
> Now I deploy my App2.war in webapps_new.
> So after restart the tomcat, I am able to make App2 to listen on port 8080 as well as port 8181(since App2.war is present in both webapps and webapps_new), and App1 is listen on only port 8080.
> Till now, everything was fine.
>
> Now I do not want to have a separate appBase for service
> 'catalina_new', means I want appBase='webapps' for service 'catalina_new' as well So by doing this change, my App1 also starts listen on port 8181 which is not required.
> So what can I do to make only App2 to listen on new port under new service with 'appBase=webapps'
>
> Hope you understand my query now!
>
I do understand, approximately. But honestly, your way of thinking about this is different from mine, and I have some trouble following your idea.
This may also be because my knowledge of the inner workings of Tomcat is limited, and I am not even sure that what you are currently doing is even supposed to work.
In my understanding, what is "listening" on a given port is not a webapp, it is Tomcat.
Tomcat accepts a connection on one of the ports that it is listening to, through one of the Connector elements of that Tomcat.
(Until now, the webapps are not involved at all) Then Tomcat allocates this connection to a Thread, to process the HTTP request which has been written by the client to that connection.
Then the Thread reads the HTTP request line sent by the client, and the HTTP request header lines.
(Until now, the webapps are not involved at all) Then the Thread reads the "Host:" header line in that request, and determines to which <Host> this request is addressed. Then the Thread loads the appropriate configuration for that <Host>, before processing the request any further.
(Until now, the webapps are still not involved at all)
*Now* the Thread knows that for this <Host>, the active applications are located somewhere, and it knows to which "context path" each application should be answering.
So *now* the Thread can call the appropriate webapp and give it the incoming request to process.
So *now* one of the active webapps is involved.
And at this point, it could be any webapp that is active within that <Host>.
What I am trying to say, is that the selection of the port on which a request comes in is not controlled by the webapp, and cannot be. It is done much earlier in the cycle, and depends only on to which port the client connects and sends his request on.
At the moment Tomcat accepts such a request, it does not know yet neither the <Host>, nor the webapp within the <Host>, which this client wants. And it cannot at that point decide to accept or refuse this request depending on which webapp it will ultimately go to, because it does not know that yet.
I must confess that I do not really know if your idea of doing this by having 2 <Service> elements in Tomcat may or may not provide a way to overcome this.
But to me, at this point, the idea seems a bit strange.
To say the truth, I don't even know if your basic idea to restrict the access to a webapp based on which port the request comes in, makes really sense for what your basic issue is.
But if that is really the issue, then I would do this on the base of a servlet filter configured for that webapp.
You could probably use the urlrewrite filter (http://tuckey.org/urlrewrite/) for that, which would be much easier than your current setup.
>The flow that you explain is absolutely fine and even I have the same flow in my mind as well.
As you know there is one param 'deployIgnore' in Host Configuration. Can't we use that one for that.
As I already explained you earlier that the case is regarding the two services in tomcat pointing to same appBase. If we add connector port lets suppose 8080 in service 1 and 8181 in service 2 then what will happen if I hit the url
http://ip-address:8080/App1
http://ip-address:8080/App2
http://ip-address:8181/App1
http://ip-address:8181/App2
It will give 200 Ok response in all the cases .
Now what if with port 8181, I want to access App1 only means now what I want is
http://ip-address:8080/App1 should be 200OK
http://ip-address:8080/App2 should be 200OK
http://ip-address:8181/App1 should be 200OK
http://ip-address:8181/App2 should be 404 Error
To achieve this, what I want to do in server.xml of tomcat.
How can I achieve that App1 should be accessible from both the ports 8080 and 8181, App2 should be accessible from 8080 not 8181.
I think we can add deployIgnore="App2" in Host configuration of new service in server.xml to make App2 not accessible at new port 8181
What you suggest??
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Re: deploy application in new service in tomcat
Posted by André Warnier <aw...@ice-sa.com>.
Hi.
On this list, the convention is to not "top post".
Put your answers either in-line, in the text, or at the end.
That is much easier for others to follow the conversation in a logical order.
Anil Goyal -X (anigoyal - Aricent Technologies at Cisco) wrote:
> Thanks for the reply Andre.....
>
> Let me explain you in detail.
> Let's suppose we have two applications App1.war and App2.war, deployed in webapps of tomcat.
> Now I want only App2 to listen additionally on a separate connector port(lets suppose 8181) along with port 8080 to which it is already listen.
> But I want App1 to listen only on port 8080 not on port 8181.
>
> So what I did, I create a new service in tomcat with name 'catalina_new' and appBase='webapps_new' and I add a connector port 8181 in this.
> Now I deploy my App2.war in webapps_new.
> So after restart the tomcat, I am able to make App2 to listen on port 8080 as well as port 8181(since App2.war is present in both webapps and webapps_new), and App1 is listen on only port 8080.
> Till now, everything was fine.
>
> Now I do not want to have a separate appBase for service 'catalina_new', means I want appBase='webapps' for service 'catalina_new' as well
> So by doing this change, my App1 also starts listen on port 8181 which is not required.
> So what can I do to make only App2 to listen on new port under new service with 'appBase=webapps'
>
> Hope you understand my query now!
>
I do understand, approximately. But honestly, your way of thinking about this is
different from mine, and I have some trouble following your idea.
This may also be because my knowledge of the inner workings of Tomcat is limited, and I am
not even sure that what you are currently doing is even supposed to work.
In my understanding, what is "listening" on a given port is not a webapp, it is Tomcat.
Tomcat accepts a connection on one of the ports that it is listening to, through one of
the Connector elements of that Tomcat.
(Until now, the webapps are not involved at all)
Then Tomcat allocates this connection to a Thread, to process the HTTP request which has
been written by the client to that connection.
Then the Thread reads the HTTP request line sent by the client, and the HTTP request
header lines.
(Until now, the webapps are not involved at all)
Then the Thread reads the "Host:" header line in that request, and determines to which
<Host> this request is addressed. Then the Thread loads the appropriate configuration for
that <Host>, before processing the request any further.
(Until now, the webapps are still not involved at all)
*Now* the Thread knows that for this <Host>, the active applications are located
somewhere, and it knows to which "context path" each application should be answering.
So *now* the Thread can call the appropriate webapp and give it the incoming request to
process.
So *now* one of the active webapps is involved.
And at this point, it could be any webapp that is active within that <Host>.
What I am trying to say, is that the selection of the port on which a request comes in is
not controlled by the webapp, and cannot be. It is done much earlier in the cycle, and
depends only on to which port the client connects and sends his request on.
At the moment Tomcat accepts such a request, it does not know yet neither the <Host>, nor
the webapp within the <Host>, which this client wants. And it cannot at that point decide
to accept or refuse this request depending on which webapp it will ultimately go to,
because it does not know that yet.
I must confess that I do not really know if your idea of doing this by having 2 <Service>
elements in Tomcat may or may not provide a way to overcome this.
But to me, at this point, the idea seems a bit strange.
To say the truth, I don't even know if your basic idea to restrict the access to a webapp
based on which port the request comes in, makes really sense for what your basic issue is.
But if that is really the issue, then I would do this on the base of a servlet filter
configured for that webapp.
You could probably use the urlrewrite filter (http://tuckey.org/urlrewrite/) for that,
which would be much easier than your current setup.
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RE: deploy application in new service in tomcat
Posted by "Anil Goyal -X (anigoyal - Aricent Technologies at Cisco)" <an...@cisco.com>.
Thanks for the reply Andre.....
Let me explain you in detail.
Let's suppose we have two applications App1.war and App2.war, deployed in webapps of tomcat.
Now I want only App2 to listen additionally on a separate connector port(lets suppose 8181) along with port 8080 to which it is already listen.
But I want App1 to listen only on port 8080 not on port 8181.
So what I did, I create a new service in tomcat with name 'catalina_new' and appBase='webapps_new' and I add a connector port 8181 in this.
Now I deploy my App2.war in webapps_new.
So after restart the tomcat, I am able to make App2 to listen on port 8080 as well as port 8181(since App2.war is present in both webapps and webapps_new), and App1 is listen on only port 8080.
Till now, everything was fine.
Now I do not want to have a separate appBase for service 'catalina_new', means I want appBase='webapps' for service 'catalina_new' as well
So by doing this change, my App1 also starts listen on port 8181 which is not required.
So what can I do to make only App2 to listen on new port under new service with 'appBase=webapps'
Hope you understand my query now!
Thanks
-----Original Message-----
From: André Warnier [mailto:aw@ice-sa.com]
Sent: Thursday, February 07, 2013 7:35 PM
To: Tomcat Users List
Subject: Re: deploy application in new service in tomcat
André Warnier wrote:
> Anil Goyal -X (anigoyal - Aricent Technologies at Cisco) wrote:
>> Hi,
>>
>> I am creating a new service in tomcat (7.0.20) with service name
>> 'catalina_new' and appBase='webapps' by doing some changes in server.xml.
>> I am keeping the appBase same as that for default service 'catalina'
>> I have several applications deployed under webapps.
>> I want only a single application with context '/feeder' to be
>> accesible through new service.
>> Condition: I do not want to have a separate appBase for new service
>> and deployed only the required app under this new appBase.
>>
>> In short, do we have a context based filtering in tomcat so that
>> tomcat incorporate request only from a specific context path and
>> ignore all others
>>
>
> I am not sure if I understand your question correctly, but if I do
> then there is some kind of contradiction, or impossibility.
> In tomcat (and in the servlet spec in general) a "context" /is/ a web
> application.
> So if you have a tomcat with an application under
> CATALINA_BASE/webapps/feeder, and a client asks for the URL
> http://your_tomcat_host:port/feeder, it will get it.
> If you do not want this application to be accessible, don't deploy it
> in your host.
> Or use a separate <Host> to give it a separate hostname and/or port
> and a separate appBase. That's less complicated than running two
> separate Tomcat instances.
>
>
I know that replying to my own posts is bad form, but I also missed something else above.
Why would you want to create a new "Service" in Tomcat, just to deploy an additional application ?
I'm not sure exactly what a new "Service"-level item brings here, but surely that's not the right level at which to do these things, or ?
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Re: deploy application in new service in tomcat
Posted by André Warnier <aw...@ice-sa.com>.
André Warnier wrote:
> Anil Goyal -X (anigoyal - Aricent Technologies at Cisco) wrote:
>> Hi,
>>
>> I am creating a new service in tomcat (7.0.20) with service name
>> 'catalina_new' and appBase='webapps' by doing some changes in server.xml.
>> I am keeping the appBase same as that for default service 'catalina'
>> I have several applications deployed under webapps.
>> I want only a single application with context '/feeder' to be
>> accesible through new service.
>> Condition: I do not want to have a separate appBase for new service
>> and deployed only the required app under this new appBase.
>>
>> In short, do we have a context based filtering in tomcat so that
>> tomcat incorporate request only from a specific context path and
>> ignore all others
>>
>
> I am not sure if I understand your question correctly, but if I do then
> there is some kind of contradiction, or impossibility.
> In tomcat (and in the servlet spec in general) a "context" /is/ a web
> application.
> So if you have a tomcat with an application under
> CATALINA_BASE/webapps/feeder, and a client asks for the URL
> http://your_tomcat_host:port/feeder, it will get it.
> If you do not want this application to be accessible, don't deploy it in
> your host.
> Or use a separate <Host> to give it a separate hostname and/or port and
> a separate appBase. That's less complicated than running two separate
> Tomcat instances.
>
>
I know that replying to my own posts is bad form, but I also missed something else above.
Why would you want to create a new "Service" in Tomcat, just to deploy an additional
application ?
I'm not sure exactly what a new "Service"-level item brings here, but surely that's not
the right level at which to do these things, or ?
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Re: deploy application in new service in tomcat
Posted by André Warnier <aw...@ice-sa.com>.
Anil Goyal -X (anigoyal - Aricent Technologies at Cisco) wrote:
> Hi,
>
> I am creating a new service in tomcat (7.0.20) with service name 'catalina_new' and appBase='webapps' by doing some changes in server.xml.
> I am keeping the appBase same as that for default service 'catalina'
> I have several applications deployed under webapps.
> I want only a single application with context '/feeder' to be accesible through new service.
> Condition: I do not want to have a separate appBase for new service and deployed only the required app under this new appBase.
>
> In short, do we have a context based filtering in tomcat so that tomcat incorporate request only from a specific context path and ignore all others
>
I am not sure if I understand your question correctly, but if I do then there is some kind
of contradiction, or impossibility.
In tomcat (and in the servlet spec in general) a "context" /is/ a web application.
So if you have a tomcat with an application under CATALINA_BASE/webapps/feeder, and a
client asks for the URL http://your_tomcat_host:port/feeder, it will get it.
If you do not want this application to be accessible, don't deploy it in your host.
Or use a separate <Host> to give it a separate hostname and/or port and a separate
appBase. That's less complicated than running two separate Tomcat instances.
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Re: deploy application in new service in tomcat
Posted by Daniel Mikusa <dm...@vmware.com>.
On Feb 8, 2013, at 5:23 AM, Anil Goyal -X (anigoyal - Aricent Technologies at Cisco) wrote:
> Hi Daniel,
>
> 'deployIgnore' option work for me. Can you please tell me how we can add multiple context path (context path for multiple applications) in this.
It's a regular expression and whatever it matches will be ignored. If you need it to match multiple things, just adjust the regular expression so that it matches those things.
Dan
>
> -----Original Message-----
> From: Daniel Mikusa [mailto:dmikusa@vmware.com]
> Sent: Thursday, February 07, 2013 6:43 PM
> To: Tomcat Users List
> Subject: Re: deploy application in new service in tomcat
>
> On Feb 7, 2013, at 8:03 AM, Anil Goyal -X (anigoyal - Aricent Technologies at Cisco) wrote:
>
>> Hi,
>>
>> I am creating a new service in tomcat (7.0.20)
>
> This is really old, you should upgrade.
>
>> with service name 'catalina_new' and appBase='webapps' by doing some changes in server.xml.
>> I am keeping the appBase same as that for default service 'catalina'
>> I have several applications deployed under webapps.
>> I want only a single application with context '/feeder' to be accesible through new service.
>> Condition: I do not want to have a separate appBase for new service and deployed only the required app under this new appBase.
>>
>> In short, do we have a context based filtering in tomcat so that tomcat incorporate request only from a specific context path and ignore all others
>
> Not sure I follow what you are trying to do, but it kinda sounds like you might want this? If not, please try to explain your use case a little more.
>
> "deployIgnore
>
> A regular expression defining paths to ignore when autoDeploy and deployOnStartup are set. This allows you to keep your configuration in a version control system, for example, and not deploy a .svn or CVS folder that happens to be in the appBase."
>
> https://tomcat.apache.org/tomcat-7.0-doc/config/host.html#Common%20Attributes
>
> Dan
>
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>
>
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RE: deploy application in new service in tomcat
Posted by "Anil Goyal -X (anigoyal - Aricent Technologies at Cisco)" <an...@cisco.com>.
Hi Daniel,
'deployIgnore' option work for me. Can you please tell me how we can add multiple context path (context path for multiple applications) in this.
-----Original Message-----
From: Daniel Mikusa [mailto:dmikusa@vmware.com]
Sent: Thursday, February 07, 2013 6:43 PM
To: Tomcat Users List
Subject: Re: deploy application in new service in tomcat
On Feb 7, 2013, at 8:03 AM, Anil Goyal -X (anigoyal - Aricent Technologies at Cisco) wrote:
> Hi,
>
> I am creating a new service in tomcat (7.0.20)
This is really old, you should upgrade.
> with service name 'catalina_new' and appBase='webapps' by doing some changes in server.xml.
> I am keeping the appBase same as that for default service 'catalina'
> I have several applications deployed under webapps.
> I want only a single application with context '/feeder' to be accesible through new service.
> Condition: I do not want to have a separate appBase for new service and deployed only the required app under this new appBase.
>
> In short, do we have a context based filtering in tomcat so that tomcat incorporate request only from a specific context path and ignore all others
Not sure I follow what you are trying to do, but it kinda sounds like you might want this? If not, please try to explain your use case a little more.
"deployIgnore
A regular expression defining paths to ignore when autoDeploy and deployOnStartup are set. This allows you to keep your configuration in a version control system, for example, and not deploy a .svn or CVS folder that happens to be in the appBase."
https://tomcat.apache.org/tomcat-7.0-doc/config/host.html#Common%20Attributes
Dan
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Re: deploy application in new service in tomcat
Posted by Daniel Mikusa <dm...@vmware.com>.
On Feb 7, 2013, at 8:03 AM, Anil Goyal -X (anigoyal - Aricent Technologies at Cisco) wrote:
> Hi,
>
> I am creating a new service in tomcat (7.0.20)
This is really old, you should upgrade.
> with service name 'catalina_new' and appBase='webapps' by doing some changes in server.xml.
> I am keeping the appBase same as that for default service 'catalina'
> I have several applications deployed under webapps.
> I want only a single application with context '/feeder' to be accesible through new service.
> Condition: I do not want to have a separate appBase for new service and deployed only the required app under this new appBase.
>
> In short, do we have a context based filtering in tomcat so that tomcat incorporate request only from a specific context path and ignore all others
Not sure I follow what you are trying to do, but it kinda sounds like you might want this? If not, please try to explain your use case a little more.
"deployIgnore
A regular expression defining paths to ignore when autoDeploy and deployOnStartup are set. This allows you to keep your configuration in a version control system, for example, and not deploy a .svn or CVS folder that happens to be in the appBase."
https://tomcat.apache.org/tomcat-7.0-doc/config/host.html#Common%20Attributes
Dan
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