Re: [opennlp-users] get heads of parse constituents

[Rodrigo Agerri <ro...@ehu.es>]

Hello,

Yes, thanks, I just needed to do a recursion over a parse object using the
getHead function.




On Wed, Mar 20, 2013 at 9:34 AM, Jörn Kottmann <ko...@gmail.com> wrote:

> Hello,
>
> the head finder in the parser is rule bases and can also be used
> standalone I think.
>
> Parse.getHead should work as far as I know gives you the head, you could
> then
> just change the label yourself to attach the H tag.
>
> Jörn
>
>
> On 03/14/2013 11:16 AM, Rodrigo Agerri wrote:
>
>> Hello!
>>
>> I am using the parser (chunking) from the API. I currently get this
>>
>> ( (S (NP-SBJ-A (NP (NNP Pierre) (NNP Vinken)) (, ,) (ADJP (NP (CD 61)
>> (NNS years)) (JJ old)) (, ,)) (VP-H (MD will) (VP-A (VB join) (NP-A
>> (DT the) (NN board)) (PP-CLR (IN as) (NP-A (DT a) (JJ nonexecutive)
>> (NN director))) (NP-TMP (NNP Nov.) (CD 29)))) (. .)))
>>
>> Which is fine, but I what I really want is this:
>>
>> ( (S-H (NP-SBJ-A (NP-H (NNP Pierre) (NNP-H Vinken)) (, ,) (ADJP (NP
>> (CD 61) (NNS-H years)) (JJ-H old)) (, ,)) (VP-H (MD-H will) (VP-A
>> (VB-H join) (NP-A (DT the) (NN-H board)) (PP-CLR (IN-H as) (NP-A (DT
>> a) (JJ nonexecutive) (NN-H director))) (NP-TMP (NNP-H Nov.) (CD 29))))
>> (. .)))
>>
>> Is there a functionality implemented to obtain the parse tree with the
>> heads of every constituent? I have been looking at the HeadFinder
>> functions and the Parse getHead() functions but I do not seem to find
>> a way to obtain this from the API.
>>
>> Cheers,
>>
>> Rodrigo
>>
>
>