determine NS release/level using regexp

["Esbrook, Scott" <Sc...@compuware.com>]

Hi. I'm somewhat of a regexp newbie, so apologies if this question is
painfully easy.

I created an RE object using code 

RE nsRegExp = new RE("(netscape*)/");

but when I do 

boolean matched = nsRegExp.match("mozilla/5.0 (windows; u; windows nt 5.0;
en-us; rv:0.9.2) gecko/20010726 netscape6/6.1");

matched is coming back false. Is forward slash some kind of special
character? I don't see anything in the docs.

FYI--I'm trying to determine a user's browser version and release level on
server side. For Netscape 6 and up, I get the following useragent strings:

useragent returned from NS 6.1 running on W2K:
mozilla/5.0 (windows; u; windows nt 5.0; en-us; rv:0.9.2) gecko/20010726
netscape6/6.1

useragent returned from NS 6.2 running on Win98:
mozilla/5.0 (windows; u; win98; en-us; rv:0.9.4) gecko/20011019
netscape6/6.2

useragent string returned from NS 7.01 running on W2K
mozilla/5.0 (windows; u; windows nt 5.0; en-us; rv:1.0.2) gecko/20021120
netscape/7.01

Using jakarta-regexp-1.2. 

Thanks,

Scott Esbrook
Software Developer
Compuware Corporation



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Re: determine NS release/level using regexp

[Schamil Wackenhut <sw...@wacke.org>]

* Esbrook, Scott meinte:

> RE nsRegExp = new RE("(netscape*)/");

this matches:
'n' followed by 'e' fb 't' fb 's' ... fb 'p' fb 'e' fb 'null or more "e"'
fb '/'
 
> boolean matched = nsRegExp.match("mozilla/5.0 (windows; u; windows nt 5.0;
> en-us; rv:0.9.2) gecko/20010726 netscape6/6.1");

return false, cause 'e' is followed by '6' not 'null or more "e"'

.sw
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