[jira] [Created] (SPARK-42193) dataframe API filter criteria throwing ParseException when reading a JDBC column name with special characters

["Shanmugavel Kuttiyandi Chandrakasu (Jira)" <ji...@apache.org>]

Shanmugavel Kuttiyandi Chandrakasu created SPARK-42193:
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             Summary: dataframe API filter criteria throwing ParseException when reading a JDBC column name with special characters
                 Key: SPARK-42193
                 URL: https://issues.apache.org/jira/browse/SPARK-42193
             Project: Spark
          Issue Type: Bug
          Components: Spark Core
    Affects Versions: 3.3.0
            Reporter: Shanmugavel Kuttiyandi Chandrakasu


*On Spark 3.3.0,* when reading from a JDBC table(used SQLite to repro) using spark.read.jdbc command with sqlite-jdbc:3.34.0.jar on a table and column name containing special characters. Dataframe API filter criteria fails with parse Exception 

*[#Script:]*
{code:java}
from pyspark.sql import SparkSession

spark = SparkSession \
    .builder \
    .appName("Databricks Support") \
    .config("spark.jars.packages", "org.xerial:sqlite-jdbc:3.34.0") \
    .getOrCreate()

columns = ["id", "/abc/column", "value"]
data = [(1, 'A', 100), (2, 'B', 200), (3, 'B', 300)]

rdd = spark.sparkContext.parallelize(data)
df = spark.createDataFrame(rdd).toDF(*columns)

options = {"url": "jdbc:sqlite:/<local-path>/spark-3.3.1-bin-hadoop3/jars/test.db", "dbtable": '"/abc/table"', "driver": "org.sqlite.JDBC"}

df.coalesce(1).write.format("jdbc").options(**options).mode("append").save()

df_1 = spark.read.format("jdbc") \
    .option("url", "jdbc:sqlite:/<local-path>/spark-3.3.1-bin-hadoop3/jars/test.db") \
    .option("dbtable", '"/abc/table"') \
    .option("driver", "org.sqlite.JDBC") \
    .load()

df_2 = df_1.filter("`/abc/column` = 'B'")

df_2.show() {code}
 

Error:

 
{code:java}
``` Traceback (most recent call last):
 File "<stdin>", line 1, in <module>
 File "/opt/homebrew/Cellar/apache-spark/3.3.1/libexec/python/pyspark/sql/dataframe.py", line 606, in show
  print(self._jdf.showString(n, 20, vertical))
 File "/opt/homebrew/Cellar/apache-spark/3.3.1/libexec/python/lib/py4j-0.10.9.5-src.zip/py4j/java_gateway.py", line 1321, in __call__
 File "/opt/homebrew/Cellar/apache-spark/3.3.1/libexec/python/pyspark/sql/utils.py", line 196, in deco
  raise converted from None
pyspark.sql.utils.ParseException: 
Syntax error at or near '/': extra input '/'(line 1, pos 0)

== SQL ==
/abc/column
^^^```  {code}
However, when using Spark 3.2.1, we are able to successfully apply dataframe.filter option

 

 
{code:java}
>>> df_2.show()
+---+-----------+-----+
| id|/abc/column|value|
+---+-----------+-----+
|  2|          B|  200|
|  3|          B|  300|
+---+-----------+-----+ {code}
 

 

Repro steps:
 # Download [Spark 3.2.1 in local |https://archive.apache.org/dist/spark/spark-3.2.1/spark-3.2.1-bin-hadoop3.2.tgz]
 # Download and Copy the sqlite-jdbc:3.34.0.jar into the jar folder present in the local spark download folder
 # Run the above [#script] by providing the jar path 
 # This will create a */abc/table* with column */abc/column*  and returns result when applying filter criteria
 # Download spark ** [3.3.0 in local|https://www.apache.org/dyn/closer.lua/spark/spark-3.3.1/spark-3.3.1-bin-hadoop3.tgz]
 # Repeat #2, #3 
 # Fails with parse exception. 

could you please let us know how we can filter on the special characters column or escape them on spark version 3.3.0?



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