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Posted to dev@hbase.apache.org by "Andrew Purtell (JIRA)" <ji...@apache.org> on 2009/11/23 05:18:40 UTC
[jira] Updated: (HBASE-2003) [shell] deleteall does not work quite
as advertised
[ https://issues.apache.org/jira/browse/HBASE-2003?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel ]
Andrew Purtell updated HBASE-2003:
----------------------------------
Attachment: HBASE-2003.patch
> [shell] deleteall does not work quite as advertised
> ---------------------------------------------------
>
> Key: HBASE-2003
> URL: https://issues.apache.org/jira/browse/HBASE-2003
> Project: Hadoop HBase
> Issue Type: Bug
> Reporter: Andrew Purtell
> Priority: Minor
> Fix For: 0.20.3, 0.21.0
>
> Attachments: HBASE-2003.patch
>
>
> In the shell, a delete must match the value's coordinates exactly. By default the delete command uses the latest timestamp but you can provide on explicitly. So you have to delete each version independent of the others if there are multiple versions of a value.
> The command 'deleteall' is supposed to clear out a whole row or a whole column of values:
> {noformat}
> deleteall Delete all cells in a given row; pass a table name, row, and optionally
> a column and timestamp
> {noformat}
> but the code won't work as advertised:
> {code}
> def deleteall(row, column = nil, timestamp = HConstants::LATEST_TIMESTAMP)
> now = Time.now
> d = Delete.new(row.to_java_bytes, timestamp, nil)
> @table.delete(d)
> @formatter.header()
> @formatter.footer(now)
> end
> {code}
> 'column' is ignored.
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